Problem 25
Question
The Monod model is used to describe how the rate of reproduction of organisms depends on the amount of nutrients that are available. Monod (1949) studied how the rate of division of \(E\). coli cells depended upon the amount of sugar added to their growth flask. If \(r\) is the rate of reproduction (number of divisions in one hour) and \(C\) is the amount of glucose sugar added to the growth medium measured in moles then: $$r(C)=\frac{1.35 C}{C+0.22 \times 10^{-4}}$$ (a) Show that the reproduction rate goes to zero when the sugar level is low; that is: $$\lim _{C \rightarrow 0} r(C)=0$$ (b) Show that if more and more sugar is added, the reproductive rate plateaus; that is, \(\lim _{C \rightarrow \infty} r(C)\) exists and calculate this limit.
Step-by-Step Solution
VerifiedKey Concepts
Reproduction Rate
Limits in Calculus
- Low sugar level: Here, we analyze \( \lim_{C \to 0} r(C) \) to see what happens when \( C \) is very low. By substituting \( C = 0 \), we find that the reproduction rate approaches zero because the bacteria lack the necessary nutrients to multiply.
- High sugar level: Conversely, to understand the effect of excess sugar, we calculate \( \lim_{C \to \infty} r(C) \). As \( C \) becomes very large, the reproduction rate levels off at 1.35, as there's a limit to how fast the bacteria can reproduce, no matter how much sugar they have.
E. coli
Importance in Research
Researchers like Monod chose E. coli for studying the effects of nutrient concentration on reproduction rates for several reasons:- Fast Growth: E. coli can reproduce rapidly, making it ideal for observing quick changes in growth rate.
- Simple Nutritional Requirements: E. coli has simpler nutritional needs compared to other microorganisms, allowing for controlled experiments with nutrients like glucose.
- Genetic Manipulation: Its genetic material is easy to manipulate, making it a staple in genetic and microbiological research.