Problem 25
Question
The Bell numbers \(B_{n},\) named after the English mathematician Eric T. Bell (1883-1960) and used in combinatorics, are defined recursively as follows: $$B_{0}=1$$ $$B_{n}=\sum_{i=0}^{n-1}\left(\begin{array}{c} n-1 \\ i \end{array}\right) B_{i}, \quad n \geq 1$$ Compute each Bell number. $$B_{3}$$
Step-by-Step Solution
Verified Answer
The Bell number for n = 3 is \(B_3 = 5\).
1Step 1: Understanding the formula
The given formula for Bell numbers is as follows:
\(B_n = \sum_{i=0}^{n-1} {n-1 \choose i} B_i \quad\) for \(n \geq 1\)
Here,
- \(B_n\) denotes the Bell number for the given value of n.
- \(\sum_{i=0}^{n-1}\) is a summation from i=0 to i=n-1.
- \({n-1 \choose i}\) are binomial coefficients, also expressed as \(\frac{(n-1)!}{i!(n-1-i)!}\), where "n! " represents the factorial of n.
- \(B_i\) represents the Bell numbers for the values i=0 to i=n-1.
Now that we understand the formula let's proceed to compute the Bell number for n=3.
2Step 2: Plugging in the value of n
We need to compute the Bell number for \(n = 3\), i.e., \(B_3\).
Using the formula:
\(B_3 = \sum_{i=0}^{3-1} {3-1 \choose i} B_i\)
This simplifies to:
\(B_3 = \sum_{i=0}^{2} {2 \choose i} B_i\)
3Step 3: Calculating each term in the summation
We will now calculate each term in the summation:
1. When i = 0:
\({2 \choose 0} = \frac{2!}{(2-0)! 0!} = \frac{2}{2} = 1\)
Since \(B_0 = 1\), we have:
\({2 \choose 0} B_0 = 1 \cdot 1 = 1\)
2. When i = 1:
\({2 \choose 1} = \frac{2!}{(2-1)!(1!)} = \frac{2}{1} = 2\)
Since \(B_1 = 1\), we have:
\({2 \choose 1} B_1 = 2 \cdot 1 = 2\)
3. When i = 2:
\({2 \choose 2} = \frac{2!}{(2-2)! (2!)} = \frac{2}{2} = 1\)
Since \(B_2 = 2\), we have:
\({2 \choose 2} B_2= 1 \cdot 2 = 2\)
4Step 4: Adding all computed terms to find B_3
Combining all calculated terms to find \(B_3\):
\(B_3 = \sum_{i=0}^{2} {2 \choose i} B_i = {2 \choose 0} B_0 + {2 \choose 1} B_1 + {2 \choose 2} B_2\)
Thus,
\(B_3 = 1 + 2 + 2 = 5\)
So the Bell number for n = 3 is:
\(B_3 = 5\)
Key Concepts
CombinatoricsBinomial CoefficientsRecursive FormulaFactorial
Combinatorics
Combinatorics is a fascinating field of mathematics that deals with counting, arranging, and analyzing configurations. Imagine trying to figure out how many different ways you can assign tasks to a group of people, or how many possible hands you can be dealt in a card game. These are classic examples where combinatorics steps in. For instance, the Bell numbers, which tell us the number of ways to partition a set, are a powerful tool in combinatorics because they allow us to quantify different scenarios logically.
By using combintorial techniques, you can solve problems involving permutations, combinations, and partitions. Such methods often utilize formulas and numbers that can handle large quantities and complex arrangements, making them indispensable in both pure and applied mathematics.
By using combintorial techniques, you can solve problems involving permutations, combinations, and partitions. Such methods often utilize formulas and numbers that can handle large quantities and complex arrangements, making them indispensable in both pure and applied mathematics.
Binomial Coefficients
Binomial coefficients are a crucial component in combinatorics, and they often appear in the expansion of binomial expressions, hence their name. As part of the theory of combinations, binomial coefficients provide a way to choose subsets from a larger set, a task often referred to as "n choose k."
In the context of Bell numbers, the binomial coefficient \({n-1 \choose i}\) is used to weigh different parts of the recursive formula. It defines the number of ways to choose \(i\) elements from \(n-1\) elements without considering the order of selection. This coefficient can be calculated using the formula:
In the context of Bell numbers, the binomial coefficient \({n-1 \choose i}\) is used to weigh different parts of the recursive formula. It defines the number of ways to choose \(i\) elements from \(n-1\) elements without considering the order of selection. This coefficient can be calculated using the formula:
- \(\frac{(n-1)!}{i!(n-1-i)!}\)
Recursive Formula
A recursive formula is a formula that defines each term of a sequence using the preceding ones. This method is particularly relevant in mathematical sequences or structures that grow based on previous stages. For functions or numbers defined recursively, the next value in the sequence is based on the combination or transformation of previous values.
You can see a stellar example of this in the recursive formula for Bell numbers:
You can see a stellar example of this in the recursive formula for Bell numbers:
- \(B_n = \sum_{i=0}^{n-1} {n-1 \choose i} B_i\)
Factorial
The factorial function, represented by an exclamation mark \((!\)), is a core concept in mathematics, particularly within combinatorics. It refers to the product of all positive integers up to a specified number \(n\). For example, \(5!\) is equal to \(5 \times 4 \times 3 \times 2 \times 1\), which equals 120.
Factorials are vital in calculating combinations and permutations, where the order of elements is paramount. They provide the foundation for computing binomial coefficients, as seen in their formula:
Factorials are vital in calculating combinations and permutations, where the order of elements is paramount. They provide the foundation for computing binomial coefficients, as seen in their formula:
- \(\frac{(n-1)!}{i!(n-1-i)!}\)
Other exercises in this chapter
Problem 24
Find the number of ways each sum can be formed from a collection of 10 nickels and 5 quarters. 25 cents
View solution Problem 25
There are 15 rabbits in a cage. Five of them are injected with a certain drug. Three of the 15 rabbits are selected successively at random for an experiment. Fi
View solution Problem 25
Find the number of solutions to each equation, where the variables are nonnegative integers. $$x_{1}+x_{2}+x_{3}+x_{4}+x_{5}=11$$
View solution Problem 25
Find the number of ways each sum can be formed from a collection of 10 nickels and 5 quarters. 30 cents
View solution