Problem 25
Question
Population The population \(P\) of a city is given by \(P=120,000 e^{0.016 t}\) where \(t\) represents the year, with \(t=0\) corresponding to 2000\. Sketch the graph of this equation. Use the model to predict the year in which the population of the city will reach about 180,000
Step-by-Step Solution
Verified Answer
The sketch of the graph will be an upward curving line starting from the point (0,120000). The year that the city population will reach about 180,000 can be calculated to be approximately 16.5 years after 2000, which corresponds to the year 2017.
1Step 1: Understanding the exponential growth formula
The exponential growth model is given by \(P=120,000 e^{0.016 t}\). Here, P is the population at time 't', 120,000 is the initial population at \(t = 0\) (Year 2000), e is the natural logarithm base approximately 2.71828, 0.016 is the annual growth rate, and 't' is the time in years from the year 2000.
2Step 2: Sketching the graph
To sketch the graph, take 't' on x-axis and 'P' on y-axis. Start from the point (0,120000) because the population is 120,000 at year 2000. As 't' increases, 'P' will also increase because of the positive exponent. It won't be a straight line but an upward curving line (due to the nature of exponential growth).
3Step 3: Predicting when the population will reach 180,000
To predict when the population will reach 180,000, simply solve the equation \(120,000 e^{0.016 t} = 180,000\). First, divide both sides by 120,000 to get \(e^{0.016 t} = 1.5\). Then, take natural log of both sides to get \(0.016t = ln(1.5)\). Finally, solve for 't' by dividing both sides by 0.016. This gives the number of years from the year 2000.
Key Concepts
Population ModelAnnual Growth RateNatural Logarithm
Population Model
A population model is a mathematical representation used to predict the growth or decline of a population over time. In our example, the population model used is an exponential model represented by the formula \(P = 120,000 e^{0.016 t}\). This model describes how the population \(P\) of a city changes over time \(t\).In this equation:
- The initial population at the starting year (2000) is 120,000.
- The variable \(t\) represents the number of years elapsed since 2000.
- The growth factor \(e^{0.016 t}\) accounts for how the population grows exponentially.
Annual Growth Rate
The annual growth rate is a crucial component of understanding how populations evolve over time. In the given equation, the annual growth rate is represented by the exponent 0.016. This rate is the constant percentage increase in population size per year.
Here's how it works:
- The 0.016 is derived from real-world data indicating that the population increases by roughly 1.6% each year.
- It informs us of the speed and nature of growth, making predictions about future population sizes possible.
Natural Logarithm
The natural logarithm is a fundamental concept in mathematics often used in exponential growth calculations. It is denoted as \(\ln\) and works with the natural base \(e\) (approximately 2.71828).In step 3 of solving the problem, the natural logarithm helps to isolate the variable \(t\) when predicting the future population:
- By taking the natural log of both sides, you transform the exponential equation \(e^{0.016 t} = 1.5\) into a linear equation: \(0.016 t = \ln(1.5)\).
- This step allows for easier manipulation and solution of the equation to find \(t\).
Other exercises in this chapter
Problem 24
Use the definition of a logarithm to write the equation in exponential form. For example, the exponential form of \(\log _{5} 125=3\) is \(5^{3}=125\).\(\log _{
View solution Problem 24
Sketch the graph of the function.\(g(x)=\left(\frac{3}{2}\right)^{x+2}\)
View solution Problem 25
Solve the exponential equation algebraically. Approximate the result to three decimal places.\(2\left(3^{x}\right)=16\)
View solution Problem 25
Evaluate the logarithm. Round your result to three decimal places.\(\log _{2} 6\)
View solution