Problem 25
Question
Poiseuille's law states that the blood flow rate \(F\) (in \(L / \mathrm{min}\) ) through a major artery is directly proportional to the product of the fourth power of the radius \(r\) of the artery and the blood pressure \(P\). (a) Express \(F\) in terms of \(P, r\), and a constant of proportionality \(k\). (b) During heavy exercise, normal blood flow rates sometimes triple. If the radius of a major artery increases by \(10 \%\), approximately how much harder must the heart pump?
Step-by-Step Solution
Verified Answer
Expressed as \( F = k \cdot r^4 \cdot P \), the heart must pump about 2.05 times harder.
1Step 1: Express Blood Flow Rate Using Poiseuille's Law
According to Poiseuille's law, the blood flow rate \( F \) is directly proportional to the product of the fourth power of the radius \( r \) and the blood pressure \( P \). Thus, the expression for \( F \) in terms of the constant of proportionality \( k \), radius \( r \), and pressure \( P \) is:\[ F = k \cdot r^4 \cdot P \].
2Step 2: Understand the Conditions During Exercise
During exercise, the blood flow rate \( F \) triples, which means it becomes \( 3F \). If the radius \( r \) increases by \( 10\% \), the new radius \( r_{new} \) is \( r + 0.1r = 1.1r \). We need to find the new pressure \( P_{new} \) to determine how much harder the heart must pump.
3Step 3: Express the New Flow Rate in Terms of New Variables
Using the relationship from Step 1, the new flow rate \( 3F \) with radius \( r_{new} = 1.1r \) becomes:\[ 3F = k \cdot (1.1r)^4 \cdot P_{new} \].
4Step 4: Substitute and Solve for New Pressure
Substitute \( F = k \cdot r^4 \cdot P \) into the equation from Step 3:\[ 3(k \cdot r^4 \cdot P) = k \cdot (1.1r)^4 \cdot P_{new} \].Solving for \( P_{new} \) gives:\[ 3r^4P = (1.1)^4r^4P_{new} \].Cancel \( r^4 \) from both sides:\[ 3P = (1.1)^4P_{new} \].
5Step 5: Calculate the Necessary Increase in Pressure
Calculate \( (1.1)^4 \):\[ (1.1)^4 = 1.1 \times 1.1 \times 1.1 \times 1.1 = 1.4641 \].Now solve for \( P_{new} \):\[ P_{new} = \frac{3P}{1.4641} \].\[ P_{new} \approx 2.049P \].
6Step 6: Conclusion
The heart needs to pump approximately \( 2.05 \) times harder than it normally does to achieve the tripled blood flow rate when the artery radius increases by \( 10\% \).
Key Concepts
Blood Flow RateProportionality ConstantExercise PhysiologyBlood Pressure
Blood Flow Rate
Blood flow rate is a measure of the volume of blood passing through a vessel in a given period. In the context of Poiseuille's Law, it is often expressed in liters per minute (L/min). This rate is crucial because it determines how efficiently blood is delivered to various parts of the body.
When considering the relationship between the dimensions of an artery and the flow of blood, it's essential to understand that even slight changes in the vessel's radius can significantly alter the flow rate due to the fourth power relation. This is mathematically shown as:
When considering the relationship between the dimensions of an artery and the flow of blood, it's essential to understand that even slight changes in the vessel's radius can significantly alter the flow rate due to the fourth power relation. This is mathematically shown as:
- The flow rate, denoted by \( F \), is influenced greatly by the radius \( r \) and blood pressure \( P \).
- The equation \( F = k r^4 P \) illustrates how even a small increase in \( r \) can lead to a substantial increase in \( F \).
Proportionality Constant
The proportionality constant, often symbolized as \( k \) in mathematical equations, serves as a crucial factor that relates different physical quantities to each other in Poiseuille's Law.
In the equation \( F = k r^4 P \), \( k \) is what makes the proportionality between the product of \( r^4 \) and \( P \) and the blood flow rate \( F \) into a complete equation.
In the equation \( F = k r^4 P \), \( k \) is what makes the proportionality between the product of \( r^4 \) and \( P \) and the blood flow rate \( F \) into a complete equation.
- Although \( k \) itself is not often the focus for direct calculation, it incorporates various factors such as the viscosity of blood and other physical properties of the vessel.
- Understanding \( k \) helps elucidate why different fluids flow differently even under similar pressures and constraints.
Exercise Physiology
Exercise physiology delves into how physical activity influences bodily functions, including blood flow. During exercise, the body demands more oxygen and nutrients, necessitating increased blood flow.
- With greater physical exertion, the body responds by increasing the heart rate, dilating blood vessels, and modifying blood pressure to enhance flow to active muscles.
- This increased activity can result in the tripling of normal blood flow rates.
Blood Pressure
Blood pressure is the force exerted by circulating blood upon the walls of blood vessels. It's vital for moving blood throughout the body and is a central component in Poiseuille's Law.
The relationship given by the law indicates that blood flow \( F \) is directly proportional to blood pressure \( P \), amongst other factors. This means:
The relationship given by the law indicates that blood flow \( F \) is directly proportional to blood pressure \( P \), amongst other factors. This means:
- If the blood pressure increases, the blood flow rate will increase, provided that other factors such as the artery's radius and fluid viscosity remain constant.
- During strenuous situations like exercise, adjustments in pressure are one way the body meets increased demands for blood.
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