Problem 25
Question
Let \(G\) be a group and \(S\) a subset of \(G\). Define \(\langle S\rangle\) to be the smallest subgroup of \(G\) containing \(S\), called the subgroup of \(G\) generated by \(S .\) Show that \(\langle S\rangle\) exists.
Step-by-Step Solution
Verified Answer
The subgroup \( \langle S \rangle \) exists as the intersection of all subgroups of \( G \) containing \( S \).
1Step 1: Use the Concept of Subset Intersection
The subgroup generated by a subset \( S \) of \( G \), \( \langle S \rangle \), can be defined as the intersection of all subgroups of \( G \) that contain \( S \). If each subgroup contains \( S \), their intersection must also contain \( S \).
2Step 2: Show Existence of Subgroup Containing S
Consider the entire group \( G \) itself as one of the subgroups containing \( S \). The set of all subgroups of \( G \) that contain \( S \) is non-empty since \( G \) itself is included. Therefore, this intersection is a well-defined non-empty set.
3Step 3: Verify Subgroup Properties
The intersection of subgroups is again a subgroup because it satisfies the group properties: closure, identity, and inverses. Specifically, if \( H_\alpha \) are subgroups containing \( S \), then their intersection \( H = \bigcap_\alpha H_\alpha \) also satisfies: - If \( a, b \in H \), then \( a b^{-1} \in H \). - The identity element exists in each \( H_\alpha \), hence in \( H \). - For each \( a \in H \), the inverse \( a^{-1} \in H \).
4Step 4: Establish Minimality of the Subgroup
The group \( \langle S \rangle = \bigcap_{\alpha} H_{\alpha} \) is the smallest subgroup containing \( S \) by construction since any subgroup of \( G \) that contains \( S \) must include every element of this intersection. Therefore, no smaller subgroup containing \( S \) can exist.
5Step 5: Conclude Existence and Uniqueness
Since \( \langle S \rangle = \bigcap_{\alpha} H_{\alpha} \), which is a subgroup and the smallest by construction, \( \langle S \rangle \) exists uniquely for any subset \( S \). Thus the subgroup generated by \( S \) always exists.
Key Concepts
Understanding SubgroupsExamining Group PropertiesIntersection of SubgroupsGenerated Subgroup
Understanding Subgroups
In the study of group theory, a subgroup is a group formed from a larger group that inherits the properties of the parent group. To be a subgroup, a subset of a group must satisfy specific criteria:
- Closure: For any two elements in the subset, their product must also be in the subset.
- Identity: There is an identity element in the subset that satisfies the identity property of the group.
- Inverses: For every element in the subset, there is an inverse element that is also in the subset.
Examining Group Properties
Group properties are foundational to understanding how groups, including subgroups, operate. A group is a set paired with an operation that satisfies certain criteria:
- Associativity: The operation on any three elements of the set is associative.
- Identity: There is an element in the group that leaves any element unchanged when combined with it.
- Inverse: Every element has an inverse such that when the element and its inverse are combined, the result is the identity.
Intersection of Subgroups
The concept of intersecting subgroups is vital when analyzing group structures. If you have multiple subgroups within a parent group that all contain a certain subset, their intersection will also be a subgroup. This is because:
- Closure is maintained, as any combination of elements that is valid in each subgroup remains valid in the intersection.
- The identity element exists in each subgroup, ensuring it exists in the intersection.
- Inverses of all elements are guaranteed, since they appear in every intersected subgroup.
Generated Subgroup
A generated subgroup is a uniquely important idea in group theory. Given a subset of a group, the subgroup generated by that subset, denoted as \( \langle S \rangle \), is the smallest subgroup containing that subset. To construct it:
- Consider every subgroup of the larger group that contains this subset.
- The intersection of all such subgroups is \( \langle S \rangle \).
Other exercises in this chapter
Problem 24
In Exercises 23 through 30 construct an example of a nontrivial homomorphism between the two indicated groups, if this is possible, or explain why this is not p
View solution Problem 25
Find the normalizer of the indicated subgroup in the indicated group. $$ \langle\mathrm{j}\rangle \text { in } Q_{8} $$
View solution Problem 25
Find the remainder of \(9^{1573}\) when divided by 11 .
View solution Problem 25
In Exercises 23 through 30 construct an example of a nontrivial homomorphism between the two indicated groups, if this is possible, or explain why this is not p
View solution