Problem 25
Question
Let $$f(x, y)=4-x^{2}-y^{2}$$ Compute \(f_{x}(1,1)\) and \(f_{y}(1,1)\), and interpret these partial derivatives geometrically.
Step-by-Step Solution
Verified Answer
\(f_{x}(1,1) = -2\) and \(f_{y}(1,1) = -2\); both indicate slopes in respective directions.
1Step 1: Identify the Function
The exercise gives you the function \( f(x, y) = 4 - x^2 - y^2 \). This is a function of two variables: \(x\) and \(y\).
2Step 2: Calculate the Partial Derivative with respect to x
To find \(f_{x}\), the partial derivative of \( f(x, y)\) with respect to \(x\), treat \(y\) as a constant and differentiate in terms of \(x\). This yields: \(f_{x} = \frac{\partial}{\partial x}(4 - x^2 - y^2) = -2x\).
3Step 3: Evaluate \( f_{x}(1, 1) \)
Substitute \(x = 1\) into the partial derivative function \(f_{x} = -2x\): \( f_{x}(1, 1) = -2(1) = -2\).
4Step 4: Calculate the Partial Derivative with respect to y
Next, compute the partial derivative of \(f(x, y)\) with respect to \(y\), treating \(x\) as a constant. This is: \(f_{y} = \frac{\partial}{\partial y}(4 - x^2 - y^2) = -2y\).
5Step 5: Evaluate \( f_{y}(1, 1) \)
Substitute \(y = 1\) into the partial derivative function \(f_{y} = -2y\): \( f_{y}(1, 1) = -2(1) = -2\).
6Step 6: Geometric Interpretation of Partial Derivatives
The partial derivative \(f_{x}(1, 1) = -2\) indicates the slope of the tangent line to the surface \(z = f(x, y)\) in the direction of the positive \(x \)-axis at point \((1, 1)\). Similarly, \(f_{y}(1, 1) = -2\) represents the slope of the tangent line to the surface in the direction of the positive \(y\)-axis at the same point.
Key Concepts
Geometric InterpretationMultivariable CalculusTangent Planes
Geometric Interpretation
Partial derivatives serve as a bridge connecting functions of two or more variables to their geometric properties. When we compute the partial derivatives of a function like \( f(x, y) = 4 - x^2 - y^2 \), we gain insights into its shape and behavior. These derivatives essentially describe the slope of the surface, or graph, formed by \( f(x, y) \) in three-dimensional space.
- The partial derivative \( f_x(1, 1) = -2 \) tells us about the slope of the slice of the surface when moving along the \( x \)-axis while keeping all other variables constant.
- Similarly, \( f_y(1, 1) = -2 \) indicates the slope of the surface slice along the \( y \)-axis.
Multivariable Calculus
Multivariable calculus extends the principles of calculus to functions of several variables. Rather than dealing with single-variable functions, where the domain is a line, multivariable functions have a domain that could encompass a plane or even higher-dimensional spaces. In this context, functions take the form \( f(x, y,...) \), where \( x \), \( y \), and so on are independent variables.
- The concept of multivariable calculus encompasses both differentiation and integration of functions with more than one variable.
- Partial derivatives, such as \( \frac{\partial f}{\partial x} \) and \( \frac{\partial f}{\partial y} \), are essential types of derivatives in this field.
Tangent Planes
Tangent planes represent a key concept that emerges from studying the partial derivatives of multivariable functions. Just as a tangent line approximates a curve at a point, a tangent plane approximates a surface at a given point in space. This is particularly useful when dealing with functions of two variables, such as \( f(x, y) \).
- The equation of a tangent plane at a point \( (x_0, y_0) \) is derived using partial derivatives.
- The general formula is: \( z = f(x_0, y_0) + f_x(x_0, y_0)(x-x_0) + f_y(x_0, y_0)(y-y_0) \).
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