Problem 25
Question
In Problems \(23-28,\) use the discriminant to identify the conic without actually graphing. $$ 4 x^{2}-4 x y+y^{2}-6=0 $$
Step-by-Step Solution
Verified Answer
This equation represents a parabola.
1Step 1: Identify the equation form
The equation given is a general second-degree equation in two variables: \(Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0\). By comparing, we identify coefficients: \(A=4\), \(B=-4\), \(C=1\), \(D=0\), \(E=0\), and \(F=-6\).
2Step 2: Calculate the discriminant
The discriminant \(\Delta\) for a conic section is calculated using the formula \(\Delta = B^2 - 4AC\). Substitute the values: \(\Delta = (-4)^2 - 4 \cdot 4 \cdot 1 = 16 - 16 = 0\).
3Step 3: Interpret the discriminant
The value of the discriminant \(\Delta = 0\) indicates that the conic section is a parabola, as per the rules for discriminant interpretation for conics: \(\Delta > 0\) for hyperbolas, \(\Delta = 0\) for parabolas, and \(\Delta < 0\) for ellipses, which includes circles if \(A = C\).
Key Concepts
DiscriminantParabolasSecond-Degree Equations
Discriminant
The discriminant is a key mathematical concept that helps determine the nature of conic sections. For any conic section represented by a second-degree equation of the form: \\[ Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \]The discriminant \( \Delta \) is calculated using the formula:
- \( \Delta = B^2 - 4AC \)
- If \( \Delta > 0 \), the conic is a hyperbola.
- If \( \Delta = 0 \), the conic is a parabola.
- If \( \Delta < 0 \), the conic is an ellipse. A circle is a special form of an ellipse where \( A = C \).
Parabolas
Parabolas are one of the fundamental shapes in the family of conic sections. A critical identification feature of a parabola is when the discriminant, \( \Delta \), equals zero. This distinguishes it from other conics:
Parabolas have several characteristics:
Parabolas have several characteristics:
- They are symmetrical, with a line of symmetry running through their vertex.
- They open either vertically or horizontally, depending on their orientation.
- The vertex is the point where the parabola turns.
- Projectile motions, where the trajectory is parabolic.
- Reflector technologies, like satellite dishes and headlights.
Second-Degree Equations
Second-degree equations, or quadratic equations, are pivotal in describing conic sections. These equations take the form:
\[ Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \]Where:
\[ Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \]Where:
- \( A, B, C \) are coefficients that determine the equation's specific type.
- \( D, E \) are coefficients for linear terms in \( x \) and \( y \).
- \( F \) is a constant term.
Other exercises in this chapter
Problem 25
In Problems \(21-44,\) find an equation of the hyperbola that satisfies the given conditions. Foci \((\pm 4,0),\) length of transverse axis 6
View solution Problem 25
Find an equation of the ellipse that satisfies the given conditions. Vertices (0,±3) , endpoints of minor axis (±1,0)
View solution Problem 25
The given three points form a triangle. Determine which triangles are isosceles and which are right triangles. $$ (0,0,0),(3,6,-6),(2,1,2) $$
View solution Problem 25
In Problems \(25-44,\) find an equation of parabola that satisfies the given conditions. Focus \((0,7),\) directrix \(y=-7\)
View solution