Problem 25
Question
In Exercises 25-28, use the matrix capabilities of a graphing utility to evaluate the expression. Round your results to three decimal places, if necessary. \(\dfrac{3}{7}\left[\begin{array}{r} 2 & 5 \\ -1 & -4 \end{array}\right] + 6\left[\begin{array}{r} -3 & 0 \\ 2 & 2 \end{array}\right]\)
Step-by-Step Solution
Verified Answer
The result of the expression is \( \left[\begin{array}{r} -17.143 & 2.142 \ 11.572 & 10.286 \end{array}\right] \)
1Step 1: Perform the Scalar Multiplication
Perform Scalar multiplications on both matrices. For scalar multiplication, each entry in the matrix is multiplied by the scalar. \(\dfrac{3}{7}\left[\begin{array}{r} 2 & 5 \ -1 & -4 \end{array}\right] = \left[\begin{array}{r} \dfrac{3}{7}*2 & \dfrac{3}{7}*5 \ \dfrac{3}{7}*(-1) & \dfrac{3}{7}*(-4) \end{array}\right] = \left[\begin{array}{r} 0.857 & 2.142 \ -0.428 & -1.714 \end{array}\right]\)\(6\left[\begin{array}{r} -3 & 0 \ 2 & 2 \end{array}\right] = \left[\begin{array}{r} 6*(-3) & 6*0 \ 6*2 & 6*2 \end{array}\right] = \left[\begin{array}{r} -18 & 0 \ 12 & 12 \end{array}\right]\)
2Step 2: Perform the Matrix Addition
Perform the addition of the two resulting matrices from step 1. For matrix addition, corresponding elements in the matrix are added together.\(\left[\begin{array}{r} 0.857 & 2.142 \ -0.428 & -1.714 \end{array}\right] + \left[\begin{array}{r} -18 & 0 \ 12 & 12 \end{array}\right] = \left[\begin{array}{r} 0.857-18 & 2.142+0 \ -0.428+12 & -1.714+12 \end{array}\right] = \left[\begin{array}{r} -17.143 & 2.142 \ 11.572 & 10.286 \end{array}\right]\)
Key Concepts
Understanding Scalar MultiplicationExploring Matrix AdditionUsing Graphing Utilities for Matrix Operations
Understanding Scalar Multiplication
Scalar multiplication is a fundamental operation in matrix algebra that involves multiplying every entry within a matrix by a scalar, which is just a fancy term for a real number. Let's break that down with an example. Suppose you have a matrix:
- Matrix: \[\begin{bmatrix} 2 & 5 \ -1 & -4 \end{bmatrix}\]
- \(\frac{3}{7} \times 2\) becomes approximately \(0.857\)
- \(\frac{3}{7} \times 5\) becomes approximately \(2.142\)
- \(\frac{3}{7} \times -1\) becomes approximately \(-0.428\)
- \(\frac{3}{7} \times -4\) becomes approximately \(-1.714\)
Exploring Matrix Addition
Matrix addition is another basic yet crucial operation in linear algebra, which allows for the combination of two matrices of the same dimensions by adding corresponding elements. For successful addition, both matrices must have identical numbers of rows and columns.
Let's explore with the matrices already processed through scalar multiplication:
Let's explore with the matrices already processed through scalar multiplication:
- Matrix 1: \[\begin{bmatrix} 0.857 & 2.142 \ -0.428 & -1.714 \end{bmatrix}\]
- Matrix 2: \[\begin{bmatrix} -18 & 0 \ 12 & 12 \end{bmatrix}\]
- Top left: \(0.857 + (-18) = -17.143\)
- Top right: \(2.142 + 0 = 2.142\)
- Bottom left: \(-0.428 + 12 = 11.572\)
- Bottom right: \(-1.714 + 12 = 10.286\)
Using Graphing Utilities for Matrix Operations
Graphing utilities are incredibly useful tools for visualizing and performing operations with matrices. These digital tools can perform complex calculations quickly and display the results in a clear and visual manner. Essential functions include:
- Executing scalar multiplication and showing step-by-step processes
- Handling matrix addition with ease and speed
- Allowing visualization of matrix transformations
- You can input the matrix data and apply operations like multiplication and addition seamlessly.
- It's crucial to ensure matrices are entered correctly to match the operations needed.
- The visual output helps in understanding how operations impact the dataset.
Other exercises in this chapter
Problem 25
In Exercises 25-32, find all (a) minors and (b) cofactors of the matrix. \(\left[ \begin{array}{r} 4 & 5 \\ 3 & -6 \end{array} \right]\)
View solution Problem 25
In Exercises 25-34, use the matrix capabilities of a graphing utility to find the inverse of the matrix (if it exists). \(\left[ \begin{array}{r} 1 & 2 & -1 \\
View solution Problem 26
In Exercises 25-32, find all (a) minors and (b) cofactors of the matrix. \(\left[ \begin{array}{r} 0 & 10 \\ 3 & -4 \end{array} \right]\)
View solution Problem 26
In Exercises 25-34, use the matrix capabilities of a graphing utility to find the inverse of the matrix (if it exists). \(\left[ \begin{array}{r} 10 & 5 & -7 \\
View solution