Problem 25
Question
In Exercises \(23-26,\) use an identity to simplify the sum. $$ \sum_{j=2}^{6} \ln (j) $$
Step-by-Step Solution
Verified Answer
The simplified form of the sum is \( \ln(720) \).
1Step 1: Review the sum expression
The given expression is \( \sum_{j=2}^{6} \ln(j) \). This represents the sum of the natural logarithms of integers from 2 to 6 inclusive.
2Step 2: Apply the logarithm identity
Use the property of logarithms that states \( \ln(a) + \ln(b) = \ln(ab) \). This means we can combine all the terms under a single logarithm: \( \sum_{j=2}^{6} \ln(j) = \ln(2 \times 3 \times 4 \times 5 \times 6) \).
3Step 3: Calculate the product inside the logarithm
Compute the product of the numbers: \( 2 \times 3 \times 4 \times 5 \times 6 = 720 \).
4Step 4: Simplify the logarithmic expression
Substitute the product back into the logarithmic expression: \( \ln(2 \times 3 \times 4 \times 5 \times 6) = \ln(720) \). Therefore, the simplified form of the sum is \( \ln(720) \).
Key Concepts
Logarithm PropertiesNatural LogarithmSummationProduct
Logarithm Properties
Logarithms have a special set of properties that makes them very useful in mathematical calculations. One key property is the product rule for logarithms:
Another important property is the quotient rule, which states that the difference of two logarithms can be expressed as the logarithm of their quotient:
- When you add two logarithms together, you are essentially multiplying their inputs: \( \ln(a) + \ln(b) = \ln(ab) \)
Another important property is the quotient rule, which states that the difference of two logarithms can be expressed as the logarithm of their quotient:
- \( \ln(a) - \ln(b) = \ln \left( \frac{a}{b} \right) \)
Natural Logarithm
The natural logarithm, often written as \( \ln(x) \), is a special type of logarithm. It uses the base \( e \), where \( e \approx 2.71828 \), and is considered one of the most important numbers in mathematics.Natural logarithms are widely used in calculus, science, and engineering because they have nice mathematical properties, which simplify differentiation and integration.
For instance, the derivative of \( \ln(x) \) is \( \frac{1}{x} \), and its integral, \( \int \ln(x) \, dx \), leads to expressions that are easier to handle than logarithms with other bases.Understanding \( \ln \) is crucial for delving deeper into logarithmic operations, particularly when working with exponential functions, given the unique relationship between \( e^x \) and \( \ln(x) \).
For instance, the derivative of \( \ln(x) \) is \( \frac{1}{x} \), and its integral, \( \int \ln(x) \, dx \), leads to expressions that are easier to handle than logarithms with other bases.Understanding \( \ln \) is crucial for delving deeper into logarithmic operations, particularly when working with exponential functions, given the unique relationship between \( e^x \) and \( \ln(x) \).
Summation
Summation is a concise way to express the addition of a sequence of numbers. It's often seen in mathematical and scientific contexts.The notation \( \sum_{j=2}^{6} \ln(j) \) is a summation and indicates that you should add together the natural logarithms of numbers starting from 2 and ending at 6.
Summations are neat tools for expressing long sequences in a compact form, preventing errors and simplifying calculations.They are particularly useful when combined with logarithm properties, as seen in the exercise. By converting the sum into a product under a single logarithm, the process becomes more streamlined, and calculations are minimized.
Summations are neat tools for expressing long sequences in a compact form, preventing errors and simplifying calculations.They are particularly useful when combined with logarithm properties, as seen in the exercise. By converting the sum into a product under a single logarithm, the process becomes more streamlined, and calculations are minimized.
Product
The product refers to the result of multiplying a sequence of numbers together. In the context of logarithmic summation, this operation plays a vital role.Using the example in our exercise, \( 2 \times 3 \times 4 \times 5 \times 6 \) results in 720. This step converts the sum of multiple logarithms into the logarithm of a single value, \( \ln(720) \), thanks to the logarithm property of converting sums into products.
This conversion is particularly beneficial because it enables easy handling of large expressions and makes solving problems more straightforward.Understanding how to compute products quickly and accurately is essential in various fields, particularly in simplifying complex arithmetic operations.
This conversion is particularly beneficial because it enables easy handling of large expressions and makes solving problems more straightforward.Understanding how to compute products quickly and accurately is essential in various fields, particularly in simplifying complex arithmetic operations.
Other exercises in this chapter
Problem 25
Calculate the derivative with respect to \(x\) of the given expression. \(2^{\ln (x)}\)
View solution Problem 25
In each of Exercises \(21-28,\) calculate the derivative of \(F(x)\) with respect to \(x\). $$ F(x)=\int_{0}^{x} \tan \left(t^{2}\right) d t $$
View solution Problem 26
Find the area of the region that is bounded by the graphs of \(y=f(x)\) and \(y=g(x)\) for \(x\) between the abscissas of the two points of intersection. $$ f(x
View solution Problem 26
Use the method of substitution to evaluate the definite integrals. $$ \int_{\pi / 3}^{\pi} \cos ^{3}(5 x) \sin (5 x) d x $$
View solution