Problem 25
Question
In \(3-26,\) prove that each equation is an identity. $$ \frac{\csc \theta}{\sin \theta}-\cot ^{2} \theta=1 $$
Step-by-Step Solution
Verified Answer
The equation is an identity: both sides simplify to 1.
1Step 1: Start with the Left Side
Let's start with the left side of the equation: \( \frac{\csc \theta}{\sin \theta}-\cot ^{2} \theta \). First, we know that \( \csc \theta = \frac{1}{\sin \theta} \). Therefore, \( \frac{\csc \theta}{\sin \theta} = \frac{\frac{1}{\sin \theta}}{\sin \theta} = \frac{1}{\sin^2 \theta} \). So the left side becomes \( \frac{1}{\sin^2 \theta} - \cot^2 \theta \).
2Step 2: Express Terms using Sine and Cosine
Continue by expressing \( \cot^2 \theta \) in terms of sine and cosine. Since \( \cot \theta = \frac{\cos \theta}{\sin \theta} \), we have \( \cot^2 \theta = \left(\frac{\cos \theta}{\sin \theta}\right)^2 = \frac{\cos^2 \theta}{\sin^2 \theta} \). Thus, the expression becomes \( \frac{1}{\sin^2 \theta} - \frac{\cos^2 \theta}{\sin^2 \theta} \).
3Step 3: Combine the Fractions
Since both terms have a common denominator \( \sin^2 \theta \), we can combine them into a single fraction: \( \frac{1 - \cos^2 \theta}{\sin^2 \theta} \).
4Step 4: Use Pythagorean Identity
Apply the Pythagorean identity \( \sin^2 \theta + \cos^2 \theta = 1 \), which gives \( 1 - \cos^2 \theta = \sin^2 \theta \). Substituting this into our fraction gives \( \frac{\sin^2 \theta}{\sin^2 \theta} \).
5Step 5: Simplify the Expression
Simplify \( \frac{\sin^2 \theta}{\sin^2 \theta} \) to get 1, as any non-zero number divided by itself equals 1. This confirms that the left side of the equation simplifies to 1.
6Step 6: Compare to the Right Side
The right side of the equation is 1. Since the left side also simplified to 1, we have shown that \( \frac{\csc \theta}{\sin \theta} - \cot^2 \theta = 1 \), confirming that the equation is indeed an identity.
Key Concepts
Understanding CosecantDefining CotangentExploring Pythagorean IdentitySine and Cosine Relationships
Understanding Cosecant
Cosecant is one of the six fundamental trigonometric functions. It is often abbreviated as "csc" and is the reciprocal of the sine function. In mathematical terms,
For example, let's say the sine of an angle \( \theta \) is 0.5. The cosecant of \( \theta \) would then be \( \csc \theta = \frac{1}{0.5} = 2 \).
This reciprocal relationship helps us transform and simplify trigonometric expressions, making it easier to handle in proofs and calculations.
- \( \csc \theta = \frac{1}{\sin \theta} \)
For example, let's say the sine of an angle \( \theta \) is 0.5. The cosecant of \( \theta \) would then be \( \csc \theta = \frac{1}{0.5} = 2 \).
This reciprocal relationship helps us transform and simplify trigonometric expressions, making it easier to handle in proofs and calculations.
Defining Cotangent
Cotangent, denoted as "cot," is another important trigonometric function. It is defined in terms of the sine and cosine functions. Specifically, it is the reciprocal of the tangent function.
In practical terms, let's consider an angle \( \theta \) where \( \cos \theta = \frac{3}{5} \) and \( \sin \theta = \frac{4}{5} \). Here, \( \cot \theta = \frac{\frac{3}{5}}{\frac{4}{5}} = \frac{3}{4} \).
Cotangent can be particularly useful in solving problems involving right triangles and circular functions, as it provides another way to express the tangent-related ratio.
- \( \cot \theta = \frac{1}{\tan \theta} = \frac{\cos \theta}{\sin \theta} \)
In practical terms, let's consider an angle \( \theta \) where \( \cos \theta = \frac{3}{5} \) and \( \sin \theta = \frac{4}{5} \). Here, \( \cot \theta = \frac{\frac{3}{5}}{\frac{4}{5}} = \frac{3}{4} \).
Cotangent can be particularly useful in solving problems involving right triangles and circular functions, as it provides another way to express the tangent-related ratio.
Exploring Pythagorean Identity
The Pythagorean identity is a fundamental relation in trigonometry that connects sine and cosine, the principal trigonometric functions. It states:
It's a powerful tool because it allows us to express sine in terms of cosine (or vice versa), and it helps in simplifying expressions involving squares of these functions. For instance, if you know \( \sin^2 \theta = 0.6 \), then \( \cos^2 \theta = 1 - 0.6 = 0.4 \).
The Pythagorean identity is especially useful in transforming complex trigonometric expressions into simpler forms, aiding in the proof of identities like the one in the original problem.
- \( \sin^2 \theta + \cos^2 \theta = 1 \)
It's a powerful tool because it allows us to express sine in terms of cosine (or vice versa), and it helps in simplifying expressions involving squares of these functions. For instance, if you know \( \sin^2 \theta = 0.6 \), then \( \cos^2 \theta = 1 - 0.6 = 0.4 \).
The Pythagorean identity is especially useful in transforming complex trigonometric expressions into simpler forms, aiding in the proof of identities like the one in the original problem.
Sine and Cosine Relationships
Sine and cosine are deeply intertwined in trigonometry, and their relationship forms the basis for many trigonometric identities and transformations. They are often referred to together because of their complementary values. If you have an angle \( \theta \), the sine and cosine are complementary in the sense that:
Moreover, sine and cosine can be used to convert between different forms of trigonometric functions, making it easier to prove identities and solve equations. For example, knowing that \( \tan \theta = \frac{\sin \theta}{\cos \theta} \) or \( \cot \theta = \frac{\cos \theta}{\sin \theta} \) simplifies the solving process.
Recognizing these relationships is essential for a strong foundation in trigonometry.
- \( \sin(\frac{\pi}{2} - \theta) = \cos \theta \)
- \( \cos(\frac{\pi}{2} - \theta) = \sin \theta \)
Moreover, sine and cosine can be used to convert between different forms of trigonometric functions, making it easier to prove identities and solve equations. For example, knowing that \( \tan \theta = \frac{\sin \theta}{\cos \theta} \) or \( \cot \theta = \frac{\cos \theta}{\sin \theta} \) simplifies the solving process.
Recognizing these relationships is essential for a strong foundation in trigonometry.
Other exercises in this chapter
Problem 25
a. Derive an identity for \(\sin 4 A\) in terms of the functions of 2\(A .\) b. Derive an identity for \(\cos 4 A\) in terms of the functions of 2\(A .\) c. Der
View solution Problem 25
A tower that is 20 feet tall stands at the edge of a 30 -foot cliff. From a point on level ground that is 20 feet from a point directly below the tower at the b
View solution Problem 26
Two boats leave a dock to cross a river that is 80 meters wide. The first boat travels to a point that is 100 meters downstream from a point directly opposite t
View solution Problem 26
In \(3-26,\) prove that each equation is an identity. $$ \frac{\cos \theta}{\sec \theta}+\frac{\sin \theta}{\csc \theta}=1 $$
View solution