Problem 25
Question
In \(19-34,\) write each sum or difference in terms of \(i\) $$ \sqrt{4}+\sqrt{-4}+\sqrt{-36}-\sqrt{36} $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(-4 + 8i\).
1Step 1: Simplify Real Square Roots
Identify and simplify the real square roots in the expression. Consider \( \sqrt{4} \) and \( \sqrt{36} \):- \( \sqrt{4} = 2 \)- \( \sqrt{36} = 6 \)
2Step 2: Simplify Imaginary Square Roots
Identify and simplify the imaginary square roots using the fact that \( \sqrt{-a} = \sqrt{a} \times i \):- \( \sqrt{-4} = \sqrt{4} \times i = 2i \)- \( \sqrt{-36} = \sqrt{36} \times i = 6i \)
3Step 3: Substitute and Simplify the Expression
Substitute the simplified square roots back into the original expression and simplify:- Original problem: \( \sqrt{4} + \sqrt{-4} + \sqrt{-36} - \sqrt{36} \)- Substitute: \( 2 + 2i + 6i - 6 \)- Simplify: \( (2 - 6) + (2i + 6i) = -4 + 8i \)
4Step 4: Write the Final Expression
The expression is now simplified in terms of \(i\):\(-4 + 8i\).
Key Concepts
Square RootsComplex NumbersImaginary Unit
Square Roots
Square roots are a fundamental concept in mathematics, representing a number that, when multiplied by itself, gives the original number. For instance, the square root of 4, denoted as \( \sqrt{4} \), is 2 because \( 2 \times 2 = 4 \). Regular square roots deal with positive numbers or zero, and this is because these numbers have real square roots.
When solving problems, it's often important to simplify square roots to make calculations easier. For example:
When solving problems, it's often important to simplify square roots to make calculations easier. For example:
- \( \sqrt{4} = 2 \)
- \( \sqrt{16} = 4 \)
- \( \sqrt{36} = 6 \)
Complex Numbers
Complex numbers expand our number system beyond the real numbers, allowing us to include the square roots of negative numbers. A complex number is expressed as \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit.
Consider complex numbers as a combination of real parts and imaginary parts:
Consider complex numbers as a combination of real parts and imaginary parts:
- The real part, represented by \( a \), is a familiar real number.
- The imaginary part is \( bi \), where \( b \) is a real number and \( i \) represents the square root of \(-1\).
Imaginary Unit
The imaginary unit \( i \) is the cornerstone of understanding complex numbers. Defined as the square root of \(-1\), \( i \) is not a typical number you find on the number line. Instead, it is a foundational element that extends the concept of square roots to negative values.
Key points about the imaginary unit include:
\( \sqrt{-4} = \sqrt{4} \times i = 2i \). This principle allows for the simplification of expressions involving the square roots of negative numbers, as seen in complex number calculations.Understanding \( i \) not only demystifies the concept of negative square roots but also unlocks an entire dimension of mathematical applications in fields ranging from engineering to physics.
Key points about the imaginary unit include:
- \( i^2 = -1 \)
- To find the square root of a negative number, such as \( \sqrt{-a} \), you can express it as \( \sqrt{a} \times i \).
\( \sqrt{-4} = \sqrt{4} \times i = 2i \). This principle allows for the simplification of expressions involving the square roots of negative numbers, as seen in complex number calculations.Understanding \( i \) not only demystifies the concept of negative square roots but also unlocks an entire dimension of mathematical applications in fields ranging from engineering to physics.
Other exercises in this chapter
Problem 25
One of the roots is given. Find the other root. \(z^{2}+2 z+k=0 ; \frac{3}{4}\)
View solution Problem 25
In \(18-25,\) write the complex conjugate of each number. $$ \pi+2 i $$
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In \(19-25,\) express each answer in simplest radical form. Check each answer. A parabola is symmetric under a line reflection. Each real root of the quadratic
View solution Problem 25
In \(9-26,\) solve each quadratic equation by completing the square. Express the answer in simplest radical form. $$ \frac{1}{2} x^{2}+x-3=0 $$
View solution