Problem 25
Question
If \(f(x)=(-1)^{\left[x^{2}\right]}\), where \([.]\) denotes the greatest integer
function, then
(A) \(f(x)\) is discontinuous for \(x=n^{1 / 3}\), where \(n \in I\)
(B) \(f(3 / 2)=1\)
(C) \(f^{\prime}(x)=0\) for \(-1
Step-by-Step Solution
Verified Answer
Options (A), (B), and (C) are correct.
1Step 1: Understanding the Function
The function is given as \( f(x) = (-1)^{[x^2]} \). The symbol \([.]\) represents the greatest integer function, also known as the floor function, which returns the greatest integer less than or equal to the given number.
2Step 2: Analyzing Discontinuity
To check where \( f(x) \) is discontinuous, we need to determine if \( (-1)^{[x^2]} \) changes value abruptly for small changes in \( x \). Notice that \( [x^2] \) changes value at integer squares, suggesting potential discontinuity at cube roots of integers (i.e., \( x = n^{1/3} \) where \( n \) is an integer). Therefore, option (A) is likely true.
3Step 3: Evaluate for Specific Value
Calculate \( f(3/2) \): \( \left(\frac{3}{2}\right)^2 = \frac{9}{4} = 2.25 \). Thus, \( [2.25] = 2 \). Therefore, \( f\left(\frac{3}{2}\right) = (-1)^2 = 1 \). Thus, option (B) is correct.
4Step 4: Check Derivative Condition
For \( -1 < x < 1 \), \( x^2 < 1 \), so \( [x^2] = 0 \) for all such \( x \). Therefore, \( f(x) = (-1)^0 = 1 \), which is constant. This would imply \( f'(x) = 0 \) in this range, making option (C) correct.
Key Concepts
greatest integer functiondiscontinuity analysisfunction derivativesmathematical problem solving
greatest integer function
The greatest integer function, denoted by \([.]\), is often referred to as the floor function. It is a mathematical function that takes any real number as input and gives the greatest integer that is less than or equal to the input number as output. For example, the greatest integer function of 2.9 is 2, and the greatest integer function of -1.2 is -2. It essentially "rounds down" a number to the nearest integer.
- Useful in algorithms and computer science for integer division.
- Provides a piecewise constant function, which is often discontinuous.
discontinuity analysis
Discontinuity in functions occurs when there is a jump, break, or hole in the graph of the function. For the function \(f(x) = (-1)^{[x^2]}\), discontinuity can occur where \[x^2\] results in a different greatest integer for infinitesimally small changes in \(x\). The excursion from one integer value of \[x^2\] to the next introduces points where the function may abruptly change its value:
- Discontinuity in greatest integer functions: typically occurs at integer boundaries, where the output of the function jumps from one integer to the next.
- Critical points for \(f(x)\) are therefore where \(x^2\) crosses an integer boundary, notably at \(x = n^{1/3}\), where the cube of \(x\) results in an integer.
function derivatives
Derivatives represent the rate of change of a function. For constant functions, their derivative is straightforward — it is zero, as there is no change in function value with respect to change in the independent variable.
- In the exercise, for the interval \(-1 < x < 1\), the function \(f(x)\) simplifies to a constant \(1\) because \([x^2] = 0\).
- With \(f(x) = 1\) being constant over that interval, \(f'(x) = 0\) demonstrates no change or slope.
mathematical problem solving
Mathematical problem solving is a systematic process of applying mathematical methods to analyze complex scenarios and arrive at a solution. This approach demands:
- Understanding the problem: Fully grasping all elements described, such as the function definition \(f(x) = (-1)^{[x^2]}\).
- Analyzing components: Breaking down the function into simpler parts (e.g., evaluating \[x^2\]).
- Recognizing patterns and behavior: Such as identifying where discontinuities might appear.
- Justifying outcomes: Explaining why certain intervals or results meet the problem's conditions (e.g., why \(f'(x) = 0\) for \(-1 < x < 1\)).
Other exercises in this chapter
Problem 23
Let \(f(x)\) be a continuous function defined for \(1 \leq x \leq 3\). If \(f(x)\) takes rational values for all \(x\) and \(f(2)=10\), then \(f(1.5)\) is equal
View solution Problem 24
If \(f(x)=\int_{0}^{x} t \cos \frac{1}{t} d t\), then the number of points of discontinuity of \(f(x)\) in the interval \((0, \pi)\) is (A) 1 (B) 2 (C) 0 (D) No
View solution Problem 26
If \(f(x)=\left[\frac{1}{\sqrt{2}}(\cos x+\sin x)\right], 0
View solution Problem 27
Let \(f(x)=a[x]+b e^{|x|}+c|x|^{2}\), where \(a, b\) and \(c\) are real constants. If \(f(x)\) is differentiable at \(x=0\), then (A) \(b=0, c=0, a \in R\) (B)
View solution