Problem 25
Question
Graph the points and draw a line through them. Write an equation in slope- intercept form of the line that passes through the points. $$ (2,-3),(-3,7) $$
Step-by-Step Solution
Verified Answer
The equation of the line that passes through the points (2,-3) and (-3,7) is \(y = -2x + 1\).
1Step 1: Calculate the slope
The formula for slope (m) is given by \((y_2-y_1) / (x_2-x_1)\). Here, \(x_1 = 2\), \(y_1 = -3\), \(x_2 = -3\), and \(y_2 = 7\). Substituting these values into the formula gives \(m = (7 - (-3)) / (-3 - 2) = 10 / -5 = -2\).
2Step 2: Calculate the y-intercept
Using the slope intercept form \(y = mx + b\), and substituting \(m = -2\), \(x = 2\), and \(y = -3\), the y-intercept (b) is calculated as follows: \(-3 = -2*2 + b\), which simplifies to \(-3 = -4 + b\). Therefore, \(b = 1\).
3Step 3: Write the equation
Finally, substituting \(m = -2\) and \(b = 1\) into the slope-intercept equation gives us the equation of the line: \(y = -2x + 1\).
4Step 4: Graph the points and the line
Plot the given points (2, -3) and (-3, 7) on the graph and draw a straight line through them. This line will represent the equation \(y = -2x + 1\).
Key Concepts
Graphing Linear EquationsCalculating SlopeY-intercept
Graphing Linear Equations
Graphing linear equations is like creating a map that shows the relationship between two variables, typically x and y. When we graph a linear equation, we're essentially drawing a straight line that goes through all the points that meet the equation's criteria. To graph a line, you need only two points, but checking with a third ensures accuracy.
To put it simply, every point on that line is a solution to the equation. You can start by plotting the points on a grid. In our exercise, we have two points, (2, -3) and (-3, 7), which tell us where the line passes. After marking these points on graph paper or using digital graphing tools, draw a straight line that connects them, and extend it across the grid. This visual representation mirrors the equation's behavior and the change in values.
To put it simply, every point on that line is a solution to the equation. You can start by plotting the points on a grid. In our exercise, we have two points, (2, -3) and (-3, 7), which tell us where the line passes. After marking these points on graph paper or using digital graphing tools, draw a straight line that connects them, and extend it across the grid. This visual representation mirrors the equation's behavior and the change in values.
Calculating Slope
The slope of a line measures its steepness and direction. Think of it as how fast a line travels upward or downward as you move from left to right across a graph. Calculating slope is crucial because it tells us the rate at which y changes with respect to x.
To calculate it, we use the formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\), where \(m\) represents the slope, and \(x_1, y_1\) and \(x_2, y_2\) are the coordinates of any two points on the line. With our given points (2, -3) and (-3, 7), we found that the slope \(m = -2\). This negative value means the line goes down as we move from left to right, which would indicate a downhill slope in real life.
To calculate it, we use the formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\), where \(m\) represents the slope, and \(x_1, y_1\) and \(x_2, y_2\) are the coordinates of any two points on the line. With our given points (2, -3) and (-3, 7), we found that the slope \(m = -2\). This negative value means the line goes down as we move from left to right, which would indicate a downhill slope in real life.
Y-intercept
The y-intercept is the point where our line crosses the y-axis. It’s like telling us the starting position of y before x starts to change. To find it, we often rearrange the equation to the slope-intercept form \(y = mx + b\), with \(m\) as the slope and \(b\) as the y-intercept. Knowing the slope, we can plug in our known x and y from a point on our line to discover \(b\).
In the example given, after calculating the slope as -2, we used one of the given points, plugged the values into the slope-intercept form, and solved for \(b\), finding it to be 1. This means our line crosses the y-axis at the point (0, 1). It's an important part of the equation because it gives us a fixed point from which we can draw our line.
In the example given, after calculating the slope as -2, we used one of the given points, plugged the values into the slope-intercept form, and solved for \(b\), finding it to be 1. This means our line crosses the y-axis at the point (0, 1). It's an important part of the equation because it gives us a fixed point from which we can draw our line.
Other exercises in this chapter
Problem 25
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