Problem 25
Question
Graph each rational function. $$ f(x)=\frac{x+4}{x-1} $$
Step-by-Step Solution
Verified Answer
Graph features: vertical asymptote at \( x = 1 \), horizontal asymptote at \( y = 1 \), x-intercept at (-4,0), y-intercept at (0,-4).
1Step 1: Identify the Vertical Asymptotes
For a rational function, vertical asymptotes occur where the denominator equals zero, provided the numerator is not also zero at that point. Set the denominator of the function equal to zero: \[ x - 1 = 0 \]Solving this yields \( x = 1 \). So, there is a vertical asymptote at \( x = 1 \).
2Step 2: Determine the Horizontal Asymptote
A horizontal asymptote is given by the behavior of the function as \( x \) approaches infinity. For the function \( f(x) = \frac{x+4}{x-1} \), since the degrees of the numerator and the denominator are the same (both 1), the horizontal asymptote equals the ratio of the leading coefficients. Here, both coefficients are 1, so the horizontal asymptote is \( y = 1 \).
3Step 3: Find the x-intercept
To find the x-intercept, set \( f(x) = 0 \) and solve for \( x \). This requires the numerator to be zero:\[ x + 4 = 0 \]Solving gives \( x = -4 \). Therefore, the x-intercept is at \( (-4, 0) \).
4Step 4: Calculate the y-intercept
Find the y-intercept by evaluating \( f(x) \) at \( x = 0 \): \[ f(0) = \frac{0+4}{0-1} = -4 \]Thus, the y-intercept is at \( (0, -4) \).
5Step 5: Sketch the Graph
Draw the vertical asymptote as a dashed line at \( x = 1 \) and a horizontal asymptote at \( y = 1 \). Mark the x-intercept at \( (-4, 0) \) and the y-intercept at \( (0, -4) \). Use these points and asymptotes to sketch the general shape of the graph. Note that as \( x \) approaches the vertical asymptote from the left, \( f(x) \) tends to \(-\infty\) and from the right, it tends to \(+\infty\).
Key Concepts
Vertical AsymptotesHorizontal AsymptotesX-InterceptsY-Intercepts
Vertical Asymptotes
Vertical asymptotes are key features in graphing rational functions as they represent the values of \(x\) where the function does not exist. In simpler terms, a vertical asymptote occurs where the denominator of the rational function equals zero. For the function \(f(x) = \frac{x+4}{x-1}\), we find vertical asymptotes by setting the denominator equal to zero:
- Equation: \(x - 1 = 0\)
- Solve: \(x = 1\)
Horizontal Asymptotes
Horizontal asymptotes describe the behavior of a function as the input \(x\) moves towards positive or negative infinity. For the function \(f(x) = \frac{x+4}{x-1}\), we determine the horizontal asymptote by comparing the degrees of the numerator and denominator:
- The degrees are equal (both are 1).
- The ratio of the leading coefficients (both 1) gives the horizontal asymptote.
X-Intercepts
X-intercepts indicate where the graph crosses or touches the x-axis. For rational functions, this happens where the numerator is equal to zero because the whole fraction, therefore, equals zero. For \(f(x) = \frac{x+4}{x-1}\), set the numerator equal to zero:
- Equation: \(x + 4 = 0\)
- Solve: \(x = -4\)
Y-Intercepts
Y-intercepts show where the graph crosses the y-axis. To find the y-intercept, substitute \(x = 0\) into the function and solve for \(f(x)\). With \(f(x) = \frac{x+4}{x-1}\):
- Calculate: \(f(0) = \frac{0+4}{0-1} = -4\)
Other exercises in this chapter
Problem 25
Solve each equation or inequality. Check your solutions. $$ \frac{1}{n-2}=\frac{2 n+1}{n^{2}+2 n-8}+\frac{2}{n+4} $$
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If \(y\) varies directly as \(x\) and \(y=9\) when \(x\) is \(-15,\) find \(y\) when \(x=21\)
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Simplify each expression. $$ \frac{5}{a^{2} b}-\frac{7 a}{5 a^{2}} $$
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Simplify each expression. \(\frac{p^{3}}{2 q} \div \frac{-p}{4 q}\)
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