Problem 25
Question
\(\frac{90-n}{n}=10+\frac{2}{n}\)
Step-by-Step Solution
Verified Answer
\(n = 8\).
1Step 1: Eliminate Fractions
To simplify the equation, eliminate fractions by multiplying every term by the denominator, which is \(n\). This gives: \[ n \left( \frac{90-n}{n} \right) = n(10) + n \left( \frac{2}{n} \right) \] which simplifies to: \[ 90-n = 10n + 2 \].
2Step 2: Rearrange Terms
Next, rearrange the terms to bring all terms involving \(n\) on one side of the equation. This results in: \[ 90 - n = 10n + 2 \] Add \(n\) to both sides and subtract 2 from both sides:\[ 90 - 2 = 10n + n \].
3Step 3: Simplify
Now, simplify both sides:\[ 88 = 11n \].
4Step 4: Solve for \(n\)
Divide both sides by 11 to solve for \(n\):\[ n = \frac{88}{11} \].
5Step 5: Simplification
Perform the division to find the value of \(n\):\[ n = 8 \].
Key Concepts
Eliminating Fractions in EquationsSolving Linear EquationsRearranging Algebraic Equations
Eliminating Fractions in Equations
Fractions in equations can often make calculations more complex and confusing. Fortunately, there’s a straightforward method to eliminate them and simplify the problem. In algebra, you can remove fractions by finding a common denominator and multiplying all terms by it. This not only helps in simplifying the equation but also makes solving much easier.
In our example, we started with the equation \( \frac{90-n}{n} = 10 + \frac{2}{n} \). The common denominator here is \( n \). By multiplying each term by \( n \), we turn
In our example, we started with the equation \( \frac{90-n}{n} = 10 + \frac{2}{n} \). The common denominator here is \( n \). By multiplying each term by \( n \), we turn
- \( \frac{90-n}{n} \) into just \( 90-n \)
- \( 10 \cdot n \) remains as \( 10n \)
- \( \frac{2}{n} \cdot n \) becomes \( 2 \)
Solving Linear Equations
Once fractions are out of the equation, solving a linear equation becomes a lot more manageable. Solving involves finding the value of the variable that makes the equation true. In this equation, \( 90 - n = 10n + 2 \), our goal is to determine the value of \( n \).
The general strategy:
Then subtract 2 from both sides to simplify further, resulting in \( 88 = 11n \). With the variable isolated, our next step will be to solve for it.
The general strategy:
- Isolate the variable on one side.
- Move all other terms to the opposite side.
Then subtract 2 from both sides to simplify further, resulting in \( 88 = 11n \). With the variable isolated, our next step will be to solve for it.
Rearranging Algebraic Equations
Rearranging equations is about re-positioning terms to isolate the variable in question. This is a fundamental skill needed in algebra.
The principle is to move terms around to group like terms or perform operations that make solving easier. In our example, after rearranging and simplifying, we had \( 88 = 11n \).
To find the value of \( n \), divide both sides of the equation by the coefficient of \( n \), which was 11. This step is crucial as it isolates \( n \):
The principle is to move terms around to group like terms or perform operations that make solving easier. In our example, after rearranging and simplifying, we had \( 88 = 11n \).
To find the value of \( n \), divide both sides of the equation by the coefficient of \( n \), which was 11. This step is crucial as it isolates \( n \):
- \( \frac{88}{11} = n \)
- Simplify to find \( n = 8 \)
Other exercises in this chapter
Problem 25
For Problems 1-40, perform the indicated operations and express answers in simplest form. $$ \frac{2}{x^{2}+7 x+12}+\frac{3}{x^{2}-9} $$
View solution Problem 25
$$ \text { For Problems 1-32, solve each equation. (Objective 1) } $$ $$ x-\frac{5 x}{x-2}=\frac{-10}{x-2} $$
View solution Problem 26
Perform the indicated multiplications and divisions and express your answers in simplest form. $$\frac{4 a b}{2 a^{2}-2 a b} \div \frac{a b+b}{3 a-3 b}$$
View solution Problem 26
Add or subtract as indicated. Be sure to express your answers in simplest forn. (Objective 1) $$\frac{4(x-3)}{5 x}+\frac{2(x+6)}{5 x}$$
View solution