Problem 25
Question
Find the limits if \(\lim _{x \rightarrow a} f(x)=3\) and \(\lim _{x \rightarrow a} g(x)=-1\) (see Example 4\()\). $$\lim _{x \rightarrow a} \sqrt{f^{2}(x)+g^{2}(x)}$$
Step-by-Step Solution
Verified Answer
The limit is \( \sqrt{10} \).
1Step 1: Understanding the expression inside the limit
We start by considering the expression inside the limit: \( \sqrt{f^{2}(x)+g^{2}(x)} \). This involves finding the square root of the sum of the squares of two functions.
2Step 2: Finding limits of individual squared functions
Since \( \lim _{x \rightarrow a} f(x) = 3 \), we know \( \lim _{x \rightarrow a} f^{2}(x) = 3^{2} = 9 \). Similarly, since \( \lim _{x \rightarrow a} g(x) = -1 \), it follows that \( \lim _{x \rightarrow a} g^{2}(x) = (-1)^{2} = 1 \).
3Step 3: Adding the limits of the squared functions
Add the limits of the squared functions: \( \lim _{x \rightarrow a} f^{2}(x) + \lim _{x \rightarrow a} g^{2}(x) = 9 + 1 = 10 \).
4Step 4: Finding the limit of the square root of the sum
Finally, take the square root of the combined limit: \( \lim _{x \rightarrow a} \sqrt{f^{2}(x) + g^{2}(x)} = \sqrt{10} \).
Key Concepts
ContinuitySquared FunctionsSquare Root
Continuity
Continuity is an essential property of functions in calculus. A function is continuous at a point if you can draw it without picking up your pencil at that point. Formally, a function \( f(x) \) is continuous at \( x = a \) when three conditions are met:
- \( f(a) \) is defined, meaning the function has a real value at \( a \).
- The limit of \( f(x) \) as \( x \) approaches \( a \) exists.
- The value of the function at \( a \), \( f(a) \), is equal to the limit as \( x \) approaches \( a \): \( \lim_{x \to a} f(x) = f(a) \).
Squared Functions
Squared functions involve the expression \( f(x)^2 \), where each output of the function \( f(x) \) is multiplied by itself. Consider the limit of a squared function: if \( \lim_{x \to a} f(x) = L \), then \( \lim_{x \to a} f(x)^2 = L^2 \).
When working with squared functions, remember that:
When working with squared functions, remember that:
- The square of a function is always non-negative, meaning it won't produce negative results, even if \( f(x) \) itself is negative.
- Squaring a negative value results in a positive value, as seen with \( (-1)^2 = 1 \).
- Such transformations often simplify expressions and make calculations easier, as they convert differences into sums.
Square Root
The square root function is one of the most fundamental operations in mathematics. Taking the square root of a number \( y \) means finding a number \( x \) such that \( x^2 = y \). Its importance lies in:
- Only non-negative numbers have real square roots in the domain of real numbers.
- The square root reverses the squaring operation, which can help in solving equations and simplifying expressions.
- In the context of limits, finding the limit of a square root function often involves ensuring the expression inside the root is non-negative. If \( \lim_{x \to a} (f(x)^2 + g(x)^2) \) is always positive, \( \lim_{x \to a} \sqrt{f(x)^2 + g(x)^2} \) exists and equals \( \sqrt{L} \), where \( L \) is the limit of the expression inside.
Other exercises in this chapter
Problem 25
In Problems 19-28, use a calculator to find the indicated limit. Use a graphing calculator to plot the function near the limit point. $$ \lim _{x \rightarrow \p
View solution Problem 25
In Problems 24-35, at what points, if any, are the functions discontinuous? $$ f(x)=\frac{33-x^{2}}{x \pi+3 x-3 \pi-x^{2}} $$
View solution Problem 25
Find the limits. \(\lim _{n \rightarrow \infty} \frac{n}{\sqrt{n^{2}+1}}\)
View solution Problem 26
In Problems 19-28, use a calculator to find the indicated limit. Use a graphing calculator to plot the function near the limit point. $$ \lim _{t \rightarrow 0}
View solution