Problem 25
Question
Find the lengths of the sides of the triangle with the given vertices, and determine whether the triangle is a right triangle, an isosceles triangle, or neither of these. $$ (0,0,0),(2,2,1),(2,-4,4) $$
Step-by-Step Solution
Verified Answer
The triangle is a right triangle. Side lengths are 3 for AB, 3√5 for BC, and 6 for AC. It is not an isosceles triangle as no two sides are of equal length.
1Step 1: Calculate the Distance Between the Points
The distance between two points in 3D space is given by the equation \[d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}\]. Use this equation to calculate the distance between the points (0,0,0) and (2,2,1), (2,2,1) and (2,-4,4), and (0,0,0) and (2,-4,4). These distances constitute the lengths of the sides of the triangle.
2Step 2: Compute the Side Lengths
After performing the computations in Step 1, the side lengths of the triangle should be, \(AB=\sqrt{2^2 + 2^2 + 1^2}=3\), \(BC=\sqrt{0^2 + (-6)^2 + 3^2}=3\sqrt{5}\), and \(AC=\sqrt{2^2 + 4^2 + 4^2}=6\).
3Step 3: Categorize the Triangle
Now, it is time to characterize the triangle. A right triangle satisfies the Pythagorean theorem \(AB^2 + BC^2 = AC^2\). An isosceles triangle has at least two equal sides. Given our side lengths, it is clear that the triangle is a right triangle because \(3^2 + (3\sqrt{5})^2 = 6^2\). However, none of the sides are equal length, so it is not an isosceles triangle.
Key Concepts
Distance FormulaRight TriangleIsosceles Triangle
Distance Formula
In 3D geometry, to find the distance between two points, we use a specific formula that takes into account the differences in the x, y, and z coordinates. This formula is:\[d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2-z_1)^2}\]Where:
This computation can be repeated for the additional sides of a triangle formed by points in 3D space to find all side lengths.
- \((x_1, y_1, z_1)\) and \((x_2, y_2, z_2)\) are the coordinates of the two points.
- The square root symbol \(\sqrt{}\) ensures that the distance is a non-negative number.
This computation can be repeated for the additional sides of a triangle formed by points in 3D space to find all side lengths.
Right Triangle
A right triangle is a type of triangle that has one angle measuring exactly 90 degrees. The presence of a right angle offers a unique property, adhering to the Pythagorean theorem, which states:\[a^2 + b^2 = c^2\]Here:
This method can also help in various applications where determining angles and relationships between lines is crucial.
- \(a\) and \(b\) are the lengths of the shorter sides of the triangle, known as "legs."
- \(c\) is the length of the longest side, known as the "hypotenuse."
This method can also help in various applications where determining angles and relationships between lines is crucial.
Isosceles Triangle
An isosceles triangle is characterized by having at least two sides of equal length. This property means that it also has two equal angles opposite those sides. Recognizing an isosceles triangle is important in geometry due to its symmetry properties, which can simplify many mathematical problems.
- An isosceles triangle may resemble an equilateral triangle, where all sides are equal, but it only requires two equal sides.
- If a triangle does not have at least two equal side lengths, it cannot be classified as isosceles.
Other exercises in this chapter
Problem 25
Describe the region \(R\) in the \(x y\) -plane that corresponds to the domain of the function. $$ h(x, y)=x \sqrt{y} $$
View solution Problem 25
Determine whether the planes \(a_{1} x+b_{1} y+c_{1} z=d_{1}\) and \(a_{2} x+b_{2} y+c_{2} z=d_{2}\) are parallel, perpendicular, or neither. The planes are par
View solution Problem 26
Use a double integral to find the volume of the solid bounded by the graphs of the equations. $$ z=x+v, x^{2}+v^{2}=4 \text { (first octant) } $$
View solution Problem 26
Sketch the region \(R\) whose area is given by the double integral. Then change the order of integration and show that both orders yield the same area. $$ \int_
View solution