Problem 25
Question
Find the indefinite integral. (Hint: Integration by parts is not required for all the integrals.) $$ \int \frac{e^{1 / t}}{t^{2}} d t $$
Step-by-Step Solution
Verified Answer
The indefinite integral of \(\frac{e^{1 / t}}{t^{2}}\) with respect to \(t\) is \(-e^{1/t} + C\).
1Step 1: Identify the Proper Substitution
For \(\int e^{1/t}/t^{2} dt\), notice the derivative of \(1/t\), which is \(-1/t^{2}\), is in the integrand. That signifies that we should set \(u = 1/t\), therefore, \(du = -1/t^{2} dt\). Change of variables gives us a simpler integral.
2Step 2: Substitute the Variables
Substitute \(u = 1/t\) and \(du = -1/t^{2} dt\), the integral becomes \(-∫e^{u} du\), which looks much simpler.
3Step 3: Compute the Indefinite Integral
An antiderivative of the function \(e^{u}\) is \(e^{u}\), hence the integral of \(-e^{u}\) is \(-e^{u}\) + C, where C is the constant of integration.
4Step 4: Reverse Substitution
Substitute \(u = 1/t\) back in to obtain the final answer: \(-e^{1/t} + C\).
Key Concepts
Substitution MethodAntiderivativeIntegration by Parts
Substitution Method
The substitution method in integration is a powerful technique that simplifies complex integrals. It involves changing the variables in an integral to make the integration process easier.
When confronted with a difficult integral, identifying a part of the integrand that can be substituted is crucial. In the given problem, we notice that the derivative of \(1/t\), which is \(-1/t^2\), happens to be a part of the integrand \(e^{1/t}/t^2\). This suggests using a substitution where \(u = 1/t\).
When confronted with a difficult integral, identifying a part of the integrand that can be substituted is crucial. In the given problem, we notice that the derivative of \(1/t\), which is \(-1/t^2\), happens to be a part of the integrand \(e^{1/t}/t^2\). This suggests using a substitution where \(u = 1/t\).
- Set \(u = 1/t\) and find \(du\). Here, \(du = -1/t^2 dt\).
- Replace \(dt\) and transform the integral into an easier form by substituting the variables.
Antiderivative
The antiderivative, or the indefinite integral, of a function is a fundamental part of calculus. It represents a reverse operation to differentiation.
Finding an antiderivative means identifying a function whose derivative gives the original function. In the context of the problem, once we've substituted and simplified our integral, we are tasked with finding the antiderivative of \(e^u\).
Finding an antiderivative means identifying a function whose derivative gives the original function. In the context of the problem, once we've substituted and simplified our integral, we are tasked with finding the antiderivative of \(e^u\).
- The antiderivative of \(e^u\) is \(e^u\), because the derivative of \(e^u\) is itself \(e^u\).
- Don't forget to add the constant of integration \(C\) when finding indefinite integrals. This constant accounts for any vertical shifts in the family of functions.
Integration by Parts
Integration by parts is another technique in calculus used to evaluate integrals, particularly when products of functions are involved.
However, in the context of this particular problem, integration by parts was not necessary due to the choice of substitution which significantly simplified the integral.
Nonetheless, understanding integration by parts can be useful in other scenarios. It is based on the principle of the product rule for differentiation. The formula can be stated as follows:
\[\int u \, dv = uv - \int v \, du\]Here are the steps for using this method:
However, in the context of this particular problem, integration by parts was not necessary due to the choice of substitution which significantly simplified the integral.
Nonetheless, understanding integration by parts can be useful in other scenarios. It is based on the principle of the product rule for differentiation. The formula can be stated as follows:
\[\int u \, dv = uv - \int v \, du\]Here are the steps for using this method:
- Choose \(u\) and \(dv\) from the integral \(\int u \, dv\).
- Differentiate \(u\) to get \(du\) and integrate \(dv\) to get \(v\).
- Substitute into the formula to simplify and solve the integral.
Other exercises in this chapter
Problem 25
Present Value In Exercises 25 and 26, use a program similar to the Simpson's Rule program on page 906 with \(n=8\) to approximate the present value of the incom
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Use partial fractions to find the indefinite integral. $$ \int \frac{x^{2}-4 x-4}{x^{3}-4 x} d x $$
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Determine whether the improper integral diverges or converges. Evaluate the integral if it converges, and check your results with the results obtained by using
View solution Problem 26
Present Value In Exercises 25 and 26, use a program similar to the Simpson's Rule program on page 906 with \(n=8\) to approximate the present value of the incom
View solution