Problem 25
Question
Find the circle and radius of convergence of the given power series. \(\sum_{k=0}^{\infty}(1+3 i)^{k}(z-i)^{k}\)
Step-by-Step Solution
Verified Answer
The circle of convergence is centered at \( z = i \) with radius \( \frac{1}{\sqrt{10}} \).
1Step 1: Identify the Power Series
The given power series is \( \sum_{k=0}^{\infty}(1+3i)^{k}(z-i)^{k} \). This series has the form \( \sum_{k=0}^{\infty} a_k (z - z_0)^k \), where \( a_k = (1+3i)^k \) and \( z_0 = i \).
2Step 2: Find the Center of the Circle of Convergence
For a power series \( \sum_{k=0}^{\infty} a_k (z - z_0)^k \), the center of the circle of convergence is given by the value of \( z_0 \). For this series, \( z_0 = i \). Thus, the center of convergence is at \( z = i \).
3Step 3: Use the Formula for Radius of Convergence
The radius of convergence \( R \) of a power series \( \sum_{k=0}^{\infty} a_k (z - z_0)^k \) can be found using the formula: \( \frac{1}{R} = \limsup_{k \to \infty} \sqrt[k]{|a_k|} \). Here, \( a_k = (1+3i)^k \), so we need to evaluate \( \sqrt[k]{|(1+3i)^k|} \).
4Step 4: Calculate the Modulus of the Coefficients
First, find \( |a_k| = |(1+3i)^k| = |1+3i|^k \). Calculate \( |1+3i| = \sqrt{1^2 + 3^2} = \sqrt{10} \). Therefore, \( |a_k| = (\sqrt{10})^k \).
5Step 5: Determine the Radius of Convergence
Now calculate \( \limsup_{k \to \infty} \sqrt[k]{|(\sqrt{10})^k|} = \limsup_{k \to \infty} \sqrt[k]{10^{k/2}} = \limsup_{k \to \infty} 10^{1/2} = \sqrt{10} \). Therefore, \( \frac{1}{R} = \sqrt{10} \), which gives \( R = \frac{1}{\sqrt{10}} \).
6Step 6: State the Circle and Radius of Convergence
The circle of convergence has its center at \( z = i \) and a radius of \( \frac{1}{\sqrt{10}} \). The power series converges within this circle.
Key Concepts
Power SeriesComplex NumbersCircle of Convergence
Power Series
In mathematics, a power series is an infinite series of the form \( \sum_{k=0}^{\infty} a_k (z - z_0)^k \), where each term is a product of a coefficient \( a_k \) and a power of \((z - z_0)\). Here, \(z_0\) is a constant that represents the center of the series. Power series play a critical role in both real and complex analysis.
- They are useful for approximating functions and solving differential equations.
- Power series have applications in various fields, such as physics and engineering, where they model phenomena like heat and wave equations.
- They converge within a certain radius, beyond which the series does not converge.
Complex Numbers
Complex numbers extend real numbers by incorporating the imaginary unit \(i\), where \(i^2 = -1\). They have the form \(a + bi\), where \(a\) is the real part, and \(b\) is the imaginary part. In the context of power series, complex numbers allow for the exploration of series not just along the real line but across the entire complex plane.
- Complex numbers provide the fundamental framework for complex analysis.
- They are used to describe vibrations, electrical circuits, and quantum mechanics.
- The modulus \(|a + bi| = \sqrt{a^2 + b^2}\) measures the distance from the origin to the point \((a, b)\) in the complex plane.
Circle of Convergence
The circle of convergence is a fundamental concept related to power series, specifically in the context of complex numbers. For a power series centered at \(z_0\), the circle of convergence is the region within which the series converges. This region takes the form of a disk in the complex plane.
- The disk is centered at \(z_0\), the center of the series.
- The radius of the disk is the radius of convergence, \(R\).
- Determining \(R\) involves computing the lim sup of the \(k\)th root of the modulus of the series coefficients.
Other exercises in this chapter
Problem 24
In Problems 21-28, find the circle and radius of convergence of the given power series. $$ \sum_{k=1}^{\infty} \frac{1}{k^{2}(3+4 i)^{k}}(z+3 i)^{k} $$
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Use partial fractions as an aid in obtaining the Maclaurin series for the given function. Give the radius of convergence of the series. \(f(z)=\frac{i}{(z-i)(z-
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Evaluate the Cauchy principal value of the given improper integral. \(\int_{0}^{\infty} \frac{\cos 3 x}{\left(x^{2}+1\right)^{2}} d x\)
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Use Cauchy's residue theorem to evaluate the given integral along the indicated contour. \(\oint_{C} \frac{z e^{z}}{z^{2}-1} d z, C:|z|=2\)
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