Problem 25
Question
Find a rectangular equation. State the appropriate interval for \(x\) or \(y .\) $$x=3 t, y=t-1, \text { for } t \text { in }(-\infty, \infty)$$
Step-by-Step Solution
Verified Answer
The rectangular equation is \( y = \frac{x}{3} - 1 \) with \( x \) in \( (-\infty, \infty) \).
1Step 1: Express t in terms of x
Given the parameterized equation for \( x \), \( x = 3t \), solve for \( t \) by dividing both sides by 3. Thus, \( t = \frac{x}{3} \).
2Step 2: Substitute t in y equation
Using the expression from Step 1, substitute \( t = \frac{x}{3} \) into the equation \( y = t - 1 \). This gives us \( y = \frac{x}{3} - 1 \).
3Step 3: Simplify to find the rectangular equation
After substitution, you have the equation \( y = \frac{x}{3} - 1 \). Simplify this equation to express \( y \) in terms of \( x \): \( y = \frac{x}{3} - 1 \).
4Step 4: Determine the interval for x
Since \( t \) can take any real number value from \( (-\infty, \infty) \), and \( x = 3t \), \( x \) can also take any real number value. Therefore, the interval for \( x \) is \( (-\infty, \infty) \).
Key Concepts
Parameterized EquationsRectangular CoordinatesInterval Notation
Parameterized Equations
Parameterized equations are expressions where one or more variables are expressed in terms of a third variable, called a parameter. In our exercise, the equations for both \(x\) and \(y\) are expressed in terms of \(t\), which is the parameter.
- For \(x\), we have \(x = 3t\).
- For \(y\), we have \(y = t - 1\).
Rectangular Coordinates
Rectangular coordinates, often referred to as Cartesian coordinates, are used to specify the position of a point in a plane using two numbers, \(x\) and \(y\). The point \((x, y)\) describes a small position in the two-dimensional space defined by the perpendicular \(x\) and \(y\) axes.
In our example, we have derived a rectangular equation from the parameterization. We started with the parameterized form \(x = 3t\) and \(y = t - 1\), and then eliminated \(t\) to get \(y = \frac{x}{3} - 1\). This equation now directly relates \(x\) and \(y\), allowing us to plot the line without relying on \(t\). This process is important as it provides a clearer geometric interpretation, enabling easier analysis and graphing of the relation.
In our example, we have derived a rectangular equation from the parameterization. We started with the parameterized form \(x = 3t\) and \(y = t - 1\), and then eliminated \(t\) to get \(y = \frac{x}{3} - 1\). This equation now directly relates \(x\) and \(y\), allowing us to plot the line without relying on \(t\). This process is important as it provides a clearer geometric interpretation, enabling easier analysis and graphing of the relation.
Interval Notation
Interval notation is a standardized way to express the set of numbers between two endpoints. In our problem, we use interval notation to express the range of possible values for \(x\).
From the solution, since \(t\) can be any real number \((-\infty, \infty)\), and \(x = 3t\), \(x\) also spans all real numbers. Therefore, the interval for \(x\) is \((-\infty, \infty)\).
From the solution, since \(t\) can be any real number \((-\infty, \infty)\), and \(x = 3t\), \(x\) also spans all real numbers. Therefore, the interval for \(x\) is \((-\infty, \infty)\).
- \((-\infty, \infty)\) signifies all real numbers without restriction.
- Square brackets \([a, b]\) imply inclusion of endpoints, while round brackets \((a, b)\) imply exclusion of endpoints.
Other exercises in this chapter
Problem 24
Find an equation for each ellipse. \(y\) -intercepts \((0, \pm 3) ;\) foci \((0, \pm \sqrt{3})\)
View solution Problem 24
We can find an equation of a circle if we know the coordinates of the endpoints of a diameter of the circle. First, find the midpoint of the diameter, which is
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Find an equation for each ellipse. \(y\) -intercepts \((0, \pm 2 \sqrt{2}) ;\) foci \((0, \pm 2)\)
View solution Problem 25
Determine the type of conic section represented by each equation, and graph it, provided a graph exists. $$x^{2}=4 y-8$$
View solution