Problem 25
Question
Explain how the following functions can be obtained from \(y=1 / x\) by basic transformations: (a) \(y=1-\frac{1}{x}\) (b) \(y=-\frac{1}{x-1}\) (c) \(y=\frac{x}{x+1}\)
Step-by-Step Solution
Verified Answer
(a) Vertical shift up by 1; (b) Right shift by 1 and reflection across x-axis; (c) Manipulate into form 1-function.
1Step 1: Original Function
We begin with the base function \(y = \frac{1}{x}\). This is a hyperbola centered at the origin with the x and y-axes as asymptotes.
2Step 2a: Transformation for (a)
To obtain \(y = 1 - \frac{1}{x}\), start with \(y = \frac{1}{x}\). Then apply the transformation of adding 1 to the entire function, resulting in a vertical shift upwards by 1 unit.
3Step 2b: Transformation for (b)
To transform \(y = \frac{1}{x}\) into \(y = -\frac{1}{x-1}\), first apply a horizontal shift to the right by 1 unit (replacing \(x\) with \(x-1\)). Follow this by a reflection across the x-axis by multiplying the entire function by -1.
4Step 2c: Transformation for (c)
To achieve \(y = \frac{x}{x+1}\), understand that \(\frac{x}{x + 1}\) can be seen as \(1 - \frac{1}{x+1}\). Hence, this involves combining a horizontal shift of \(x\) by 1 unit to the left inside the denominator and then adjusting the overall structure to represent \(1 - \text{function}\).
Key Concepts
Understanding the HyperbolaReflection Across AxesVertical and Horizontal Shifts
Understanding the Hyperbola
A hyperbola is a type of curve on a graph that is distinctively shaped due to its asymptotic nature. Consider the function \(y = \frac{1}{x}\). This forms a hyperbola characterized by two symmetrical curves separated by the asymptotes: the x-axis and y-axis. Whenever you encounter a hyperbola, its key features include:
- Two branches opening in opposite directions (either vertically or horizontally).
- Asymptotes, which are lines the hyperbola approaches but never touches.
- A center, around which the hyperbola is symmetric, that doesn't intersect the actual graph. For \(y = \frac{1}{x}\), the center is located at the origin \((0,0)\).
Reflection Across Axes
The concept of reflection in mathematics, particularly for functions, remains a simple yet powerful tool. In essence, reflecting a graph across an axis involves mirroring it with respect to that axis.
- Across the x-axis: To reflect a function across the x-axis, multiply the function by -1. For instance, reflecting \(y = \frac{1}{x}\) across the x-axis results in \(y = -\frac{1}{x}\). This transformation inverts the graph, flipping it upside down across the horizontal line.
- Across the y-axis: Reflecting a graph across the y-axis means replacing each \(x\) with \(-x\) in the function. However, for a hyperbola like \(y = \frac{1}{x}\), this transformation does nothing because the function is inherently symmetric about the origin, a property called origin symmetry.
Vertical and Horizontal Shifts
Vertical and horizontal shifts are straightforward transformations that reposition the graph of a function without altering its shape. This involves either moving the function up, down, left, or right on the graph.
- Vertical Shifts: Adjusting the function by adding or subtracting a constant value changes its position along the y-axis. For instance, with \(y = \frac{1}{x}\) becoming \(y = 1 - \frac{1}{x}\), we've effectively shifted the hyperbola up by 1 unit.
- Horizontal Shifts: These shifts involve modifying the input \(x\). Replacing \(x\) with \(x + a\) (a positive \(a\)) shifts the graph left, while replacing it with \(x - a\) causes a right shift. For example, \(y = \frac{1}{x-1}\) represents a shift to the right by 1 unit compared to \(y = \frac{1}{x}\).
Other exercises in this chapter
Problem 24
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