Problem 25
Question
Exer. 21-32: Find a general form of an equation of the line through the point \(A\) that satisfies the given condition. $$ A(4,0) ; \quad \text { slope }-3 $$
Step-by-Step Solution
Verified Answer
The general form of the equation is \(3x + y = 12\).
1Step 1: Identify the Point-Slope Formula
A line through a given point \(x_1, y_1\) with a slope \(m\) can be represented by the point-slope form of a linear equation: \[ y - y_1 = m(x - x_1) \] Given that the point is \(A(4, 0)\) and the slope is \(-3\), we recognize this as the problem's starting point.
2Step 2: Substitute Values into the Point-Slope Formula
Substitute the given point \(A(4,0)\) and the slope \(-3\) into the point-slope formula: \[ y - 0 = -3(x - 4) \] This simplifies to: \[ y = -3(x - 4) \]
3Step 3: Simplify to Find the Equation
Distribute the slope \(-3\) through the expression \(x - 4\): \[ y = -3x + 12 \] This equation can be written in general form as: \\[ y = -3x + 12 \]
4Step 4: Rewrite in General Form
To express the equation in the general form \(Ax + By = C\), rearrange the terms: \[ 3x + y = 12 \] So the general form of the equation of the line is \(3x + y = 12\).
Key Concepts
Point-Slope FormulaSlopeEquation of a Line
Point-Slope Formula
The point-slope formula is a valuable tool in understanding the relationship between a point and a line's slope. It’s expressed as: \( y - y_1 = m(x - x_1) \), where:
To use the point-slope formula effectively, substitute the specific values of the point and the slope into the formula. For example, with a point \( A(4, 0) \) and a slope of \(-3\), substituted into the formula, it becomes: \( y - 0 = -3(x - 4) \).
The power of the point-slope formula lies in its simplicity. It directly gives the equation of the line without additional calculations, making it easier for both teaching and learning linear equations.
- \( (x_1, y_1) \) is a known point on the line.
- \( m \) is the slope of the line.
To use the point-slope formula effectively, substitute the specific values of the point and the slope into the formula. For example, with a point \( A(4, 0) \) and a slope of \(-3\), substituted into the formula, it becomes: \( y - 0 = -3(x - 4) \).
The power of the point-slope formula lies in its simplicity. It directly gives the equation of the line without additional calculations, making it easier for both teaching and learning linear equations.
Slope
Slope is a critical concept in linear equations as it measures the steepness or incline of a line. It is often denoted by the letter \( m \) and calculated as the change in \( y \) over the change in \( x \), also known as "rise over run."
- Mathematically, it's expressed as: \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
- In the provided exercise, the given slope is \(-3\).
- This negative sign indicates a line that descends from left to right.
Equation of a Line
The equation of a line is a way to express the line mathematically. It is usually given in one of several forms, such as point-slope, slope-intercept, or general form. Here’s a quick glance at them:
Rearranging terms, we have \( 3x + y = 12 \). This is the general form of a linear equation, which is often preferred in mathematics for its simplicity and ability to handle any line on a Cartesian plane.
Understanding each form’s structure helps in moving between different types of equation forms, allowing flexibility in solving and graphing problems involving linear equations.
- Point-Slope Form: \( y - y_1 = m(x - x_1) \)
- Slope-Intercept Form: \( y = mx + b \)
- General Form: \( Ax + By = C \)
Rearranging terms, we have \( 3x + y = 12 \). This is the general form of a linear equation, which is often preferred in mathematics for its simplicity and ability to handle any line on a Cartesian plane.
Understanding each form’s structure helps in moving between different types of equation forms, allowing flexibility in solving and graphing problems involving linear equations.
Other exercises in this chapter
Problem 25
Exer. 13-26: Sketch, on the same coordinate plane, the graphs of \(f\) for the given values of \(c\). (Make use of symmetry, shifting, stretching, compressing,
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Exer. 21-34: Find (a) \((f \circ g)(x)\) and the domain of \(f \circ g\) and (b) \((g \circ f)(x)\) and the domain of \(g \circ f\). $$ f(x)=\sqrt{x-2}, \quad g
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Exer. 21-32: Find the domain of \(f\). $$ f(x)=\frac{x+1}{x^{3}-4 x} $$
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Exer. 23-34: Sketch the graph of the circle or semicircle. $$ (x+3)^{2}+(y-2)^{2}=9 $$
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