Problem 25
Question
Exer. 1-50: Solve the equation. $$ x+\sqrt{5 x+19}=-1 $$
Step-by-Step Solution
Verified Answer
The solution is \(x = -3\), as it satisfies the original equation.
1Step 1: Isolate the Square Root
We start by isolating the square root expression. To do so, subtract \(x\) from both sides of the equation: \(\sqrt{5x + 19} = -1 - x\).
2Step 2: Square Both Sides
Square both sides of the equation to eliminate the square root. This gives us: \(5x + 19 = (-1 - x)^2\).
3Step 3: Expand and Simplify
Expand the right side of the equation: \((-1 - x)^2 = 1 + 2x + x^2\). So the equation becomes: \(5x + 19 = x^2 + 2x + 1\).
4Step 4: Rearrange the Equation
Rearrange the equation to bring all terms to one side: \(x^2 - 3x - 18 = 0\).
5Step 5: Solve the Quadratic Equation
We solve the quadratic equation \(x^2 - 3x - 18 = 0\) using the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 1\), \(b = -3\), \(c = -18\).
6Step 6: Calculate the Discriminant
The discriminant is \(b^2 - 4ac = (-3)^2 - 4(1)(-18) = 81\). Since the discriminant is positive, we have two real solutions.
7Step 7: Obtain the Solutions
Plug the values into the quadratic formula: \(x = \frac{3 \pm \sqrt{81}}{2}\). Simplifying, we get \(x = \frac{3 + 9}{2} = 6\) and \(x = \frac{3 - 9}{2} = -3\).
8Step 8: Verify the Solutions
Check both solutions in the original equation. For \(x = 6\), \(x + \sqrt{5x + 19} = 6 + \sqrt{49} = 6 + 7 = 13 eq -1\). Therefore, \(x = 6\) is not a solution. For \(x = -3\), \(x + \sqrt{5x + 19} = -3 + \sqrt{4} = -3 + 2 = -1\). This solution works.
Key Concepts
Square Root IsolationDiscriminant CalculationQuadratic FormulaSolution Verification
Square Root Isolation
When solving equations that contain square roots, the first crucial step is to isolate the square root component.
This means moving all other terms to the other side of the equation.
In our example equation, we start with
Knowing how to properly manipulate an equation to isolate terms will be invaluable as you tackle more complex problems.
This means moving all other terms to the other side of the equation.
In our example equation, we start with
- \(x + \sqrt{5x + 19} = -1\)
- \(\sqrt{5x + 19} = -1 - x\)
Knowing how to properly manipulate an equation to isolate terms will be invaluable as you tackle more complex problems.
Discriminant Calculation
The discriminant is a powerful element of the quadratic formula that determines the nature of the solutions of a quadratic equation.
It's calculated from the formula:
In our problem, the quadratic equation \(x^2 - 3x - 18 = 0\) has:
It's calculated from the formula:
- \(b^2 - 4ac\)
In our problem, the quadratic equation \(x^2 - 3x - 18 = 0\) has:
- \(a = 1\)
- \(b = -3\)
- \(c = -18\)
- \((-3)^2 - 4(1)(-18) = 9 + 72 = 81\)
Quadratic Formula
The quadratic formula is a staple tool for finding solutions to quadratic equations.
It is expressed as:
For our exercise, the substitutions are:
It is expressed as:
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
For our exercise, the substitutions are:
- \(a = 1\), \(b = -3\), \(c = -18\)
- \(x = \frac{3 \pm \sqrt{81}}{2}\)
- \(x = \frac{3 \pm 9}{2}\)
- \(x = 6\)
- \(x = -3\)
Solution Verification
Verifying solutions is the final and crucial step in solving equations.
This step ensures that the values found actually satisfy the original equation.
For verification:
This step ensures that the values found actually satisfy the original equation.
For verification:
- Substitute each solution back into the original equation
- Checking \(x = 6\) gives: \(6 + \sqrt{49} = 6 + 7 = 13\), which does not equal -1. So, \(x = 6\) is not a solution.
- Checking \(x = -3\) gives: \(-3 + \sqrt{4} = -3 + 2 = -1\), which equals -1. Thus, \(x = -3\) is a valid solution.
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Problem 25
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