Problem 25
Question
Enediynes are a class of compounds that include some antibiotic drugs. Draw the structure of an "enediyne" fragment that contains six carbons in a row.
Step-by-Step Solution
Verified Answer
The enediyene fragment containing six carbons in a row can be represented by the following structure:
H H
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H-C=C-C≡C-C≡C
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H H
1Step 1: Identify the Alkene and Diyne Positions
To create a six-carbon enediyene fragment, we need to first consider the positions of the alkene and diyne bonds in the structure. Since there are only six carbons, we can start by identifying pi-bond positions to create the enediyene fragment. The alkene can be positioned between carbons 1 and 2, and the diyne can be positioned between carbons 3 and 4, and carbons 5 and 6.
2Step 2: Illustrate the Bonds
Now that the positions of the alkene and diyne have been identified, the next step is to draw the structure. Start by drawing 6 carbon atoms in a row, and then add the appropriate bonds between these carbons: a single bond between carbons 2 and 3 and a single bond between carbons 4 and 5. Add a double bond between carbons 1 and 2, create two triple bonds between carbons 3 and 4, and between carbons 5 and 6.
3Step 3: Add Hydrogen Atoms
After completing the carbon framework, it's essential to add the necessary hydrogen atoms bonded to each carbon, fulfilling the tetravalency of carbon atoms. Add hydrogen atoms to each of the carbon atoms so that each carbon atom has four bonds. There should be two hydrogen atoms on carbon 1, one hydrogen atom on carbon 2, only one hydrogen atom on both carbon 3 and 6, and no hydrogen atoms on carbon 4 and 5.
The resulting structure for the enediyene fragment containing six carbons in a row is as follows:
H H
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H-C=C-C≡C-C≡C
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H H
Other exercises in this chapter
Problem 23
Give the molecular formula of a hydrocarbon containing five carben atoms that is (a) an alkane, (b) a cycloalkane, (c) an alkene
View solution Problem 24
Give the molecular formula of a hydrocarbon containing six carbon atoms that is (a) a cyclic alkane, (b) a cyclic alkene. (c) a linear alkyne, (d) an aromatic h
View solution Problem 26
Give the general formula for any cyclic alkene, that is, a cyclic hydrocarbon with one double bond.
View solution Problem 29
Name or write the condensed structural formula for the following compounds: (a) trans-2-pentene (b) 2,5-dimethyl-4-octene (c) CCC=CCC(C)CC (d) Brc1ccc(Br)cc1 (c
View solution