Problem 25
Question
Determine whether the equation has two solutions, one solution, or no real solution. \(2 x^{2}+3 x-2=0\)
Step-by-Step Solution
Verified Answer
The quadratic equation has two real solutions.
1Step 1: Identify a, b, and c from the equation
The quadratic equation is in the form \(ax^2 + bx + c = 0\). Here \(a = 2\), \(b = 3\), and \(c = -2\) from the given equation \(2x^2 + 3x - 2 = 0\).
2Step 2: Compute the Discriminant
The discriminant is given by \(D = b^2 - 4ac\). Substituting the values of \(a\), \(b\), and \(c\) we have \(D = (3)^2 - 4 * 2 * (-2) = 9 + 16 = 25\)
3Step 3: Determine the number of real solutions
Since the discriminant \(D = 25\) is greater than 0, it means the given quadratic equation \(2x^2 + 3x - 2 = 0\) has two real solutions.
Key Concepts
Understanding the DiscriminantNumber of Solutions Determined by the DiscriminantWhat Real Solutions Mean in Context
Understanding the Discriminant
The discriminant is a crucial component in the study of quadratic equations. It helps us understand the nature of the roots, or solutions, of a quadratic equation. A quadratic equation typically looks like this: \[ ax^2 + bx + c = 0 \] where \(a\), \(b\), and \(c\) are constants. To find the discriminant \(D\), you use the formula:\[ D = b^2 - 4ac \]
- If the discriminant is greater than zero: The equation has two distinct real solutions.
- If the discriminant equals zero: The quadratic equation has exactly one real solution, as the roots are coincident, or the same.
- If the discriminant is less than zero: The equation has no real solutions, implying that the roots are complex numbers.
Number of Solutions Determined by the Discriminant
Using the discriminant, we can easily determine the number of solutions a quadratic equation will have. As a restatement, consider the quadratic formula derived from the general equation \(ax^2 + bx + c = 0\): \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]The term under the square root, \(b^2 - 4ac\), is the discriminant.
- When \(D > 0\): Since the square root of a positive number is real and yields two solutions due to the \(\pm\) sign, there are two solutions.
- When \(D = 0\): The square root of zero is zero, yielding a single solution, \(x = -b/2a\). This is when the vertex of the parabola touches the x-axis.
- When \(D < 0\): A negative discriminant under a square root results in an imaginary number, indicating no real solutions exist for the equation.
What Real Solutions Mean in Context
"Real solutions" refer to the values of \(x\) that satisfy the quadratic equation and are real numbers. When dealing with real solutions, we mean that the solution points lie on the real number line. In practical terms:
- Two real solutions (\(D > 0\)): The graph of the equation, a parabola, intersects the x-axis at two distinct points. Each intersection is a solution or root of the equation.
- One real solution (\(D = 0\)): The parabola just touches the x-axis at exactly one point—this is called a double root because it's both a maximum or a minimum point.
- No real solutions (\(D < 0\)): The parabola does not intersect the x-axis at all, indicating that no actual, recommendable number satisfies the equation in terms of real solutions.
Other exercises in this chapter
Problem 25
Find the coordinates of the vertex. Make a table of values, using \(x\) -values to the left and to the right of the vertex. $$ y=6 x^{2} $$
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Use a graph to estimate the solutions of the equation. Check your solutions algebraically. $$2 x^{2}+4 x=6$$
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Simplify the expression. $$ \sqrt{27} $$
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Evaluate the expression. Check the results by squaring each root. $$ \sqrt{144} $$
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