Problem 25
Question
Convert the rectangular equation to polar form and sketch its graph. $$ y^{2}=9 x $$
Step-by-Step Solution
Verified Answer
The polar form of the equation is \(r\sin^2(\theta) = 9\cos(\theta)\) and the graph is undefined at \(\theta = 0\) with parabolic symmetry.
1Step 1: Conversion of Variables
In polar coordinates, the x and y variables of the rectangular equation can be replaced with \(r\cos(\theta)\) and \(r\sin(\theta)\) respectively. Therefore, the given rectangular equation: \(y^2 = 9x\) can be re-written as \((r\sin(\theta))^2 = 9(r\cos(\theta))\) which simplifies to \(r^2\sin^2(\theta) = 9r\cos(\theta)\).
2Step 2: Simplify the Polar Equation
Rewrite the equation from step 1 by canceling out the common parameter r from both sides giving \(r\sin^2(\theta) = 9\cos(\theta)\). We can only cancel the common r if \(r \neq 0\). This is an essential step to ensure there are no mathematical fallacies in the solution.
3Step 3: Graphing the Polar Function
To graph this function, observe that the function will have values when the right side is equal to the left side. Hence, the equation represents a graph where for every theta, r equals to \(9\cos(\theta)\) divided by \(\sin^2(\theta)\) provided \(\theta \neq 0\). This graph is undefined at \(\theta = 0\), displays symmetry, and will have a parabolic shape.
Other exercises in this chapter
Problem 25
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Use a graphing utility to graph the polar equations and find the area of the given region. Inside \(r=3 \sin \theta\) and outside \(r=2-\sin \theta\)
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