Problem 25
Question
Compute ax for each vector \(\mathbf{x}\) and scalar \(a\). Represent \(\mathbf{x}\) and ax in the plane, and explain graphically how you obtain \(a \mathrm{x}\) \(\mathbf{x}=\left[\begin{array}{r}0 \\ -4\end{array}\right]\) and \(a=0.5\)
Step-by-Step Solution
Verified Answer
The vector \(a\mathbf{x}\) is \(\begin{bmatrix} 0 \\ -2 \end{bmatrix}\).
1Step 1: Understanding the Multiplication
To compute the vector \(a\mathbf{x}\), we need to multiply each component of the vector \(\mathbf{x}\) by the scalar \(a\). In this case, \(\mathbf{x} = \begin{bmatrix} 0 \ -4 \end{bmatrix}\) and \(a = 0.5\).
2Step 2: Perform the Scalar Multiplication
Multiply each component of \(\mathbf{x}\) by \(a\):For the first component: \(0.5 \times 0 = 0\).For the second component: \(0.5 \times (-4) = -2\).Thus, \(a\mathbf{x} = \begin{bmatrix} 0 \ -2 \end{bmatrix}\).
3Step 3: Graphical Representation
In the graph, 1. Represent the original vector \(\mathbf{x} = \begin{bmatrix} 0 \ -4 \end{bmatrix}\) by drawing an arrow from the origin (0,0) to the point (0, -4).2. Represent the new vector \(a\mathbf{x} = \begin{bmatrix} 0 \ -2 \end{bmatrix}\) from the origin to the point (0, -2).Since \(a = 0.5\), the new vector is 0.5 times the length of the original \(\mathbf{x}\) and points in the same direction.
Key Concepts
Scalar MultiplicationVector RepresentationGraphical Vector Analysis
Scalar Multiplication
When working with vectors and scalars, scalar multiplication is a fundamental operation. Suppose you have a vector \( \mathbf{x} \) and a scalar \( a \). Scalar multiplication involves multiplying each component of the vector by the scalar. This results in a new vector pointing in the same direction but either longer or shorter, depending on the value of \( a \). For example, if \( a = 0.5 \), each component of \( \mathbf{x} \) is halved, creating a vector that is half the length of the original.
- If \( a = 1 \), the vector's magnitude remains unchanged.
- When \( a > 1 \), the vector's length increases.
- If \( a < 1 \), it becomes shorter.
- A negative \( a \) reverses the vector's direction.
Vector Representation
Vectors can be represented in the plane using coordinates. In two dimensions, a vector \( \mathbf{x} \) like \( \begin{bmatrix} 0 \ -4 \end{bmatrix} \) represents a movement from the origin to the point \((0, -4)\) on a graph. This helps visualize vectors in a straightforward manner by portraying them as arrows. The tail of the arrow starts at the origin, and the head points towards the vector's terminal coordinates. The components of the vector define its direction and magnitude.
- The first component determines horizontal movement. Here it's \( 0 \), so there's no movement along the x-axis.
- The second component indicates vertical movement. In this example, it is \( -4 \), showing a downward direction along the y-axis.
Graphical Vector Analysis
To understand graphical vector analysis, imagine drawing vectors in a coordinate system. For the vector \( \mathbf{x} = \begin{bmatrix} 0 \ -4 \end{bmatrix} \), start by drawing an arrow from the origin (0,0) to the point (0,-4). This arrow visually shows the vector's direction and magnitude.Next, when performing scalar multiplication with \( a \), a new vector is created. For instance, using \( a = 0.5 \), sketch an arrow from the origin to the point (0,-2).
- The direction stays the same as the original vector but its length is scaled by \( a \), which in this case is half the original length.
- This scaling effect due to \( a \) is what's visually evident on the graph.
Other exercises in this chapter
Problem 24
In Problems 19-24, solve each system of linear equations. $$ \begin{array}{r} 2 x+y-2 z=3 \\ 2 x-3 y-4 z=0 \\ x-5 y+3 z=-6 \end{array} $$
View solution Problem 25
Find the angle between \(\mathbf{x}=[0,-1,3]^{\prime}\) and \(\mathbf{y}=[-3,1,1]^{\prime}\).
View solution Problem 25
Let $$A=\left[\begin{array}{rr} -1 & 0 \\ 1 & 2 \end{array}\right], \quad B=\left[\begin{array}{rr} 2 & 0 \\ -1 & -1 \end{array}\right], \quad C=\left[\begin{ar
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In Problems 25-28, find the augmented matrix and use it to solve the system of linear equations. $$ \begin{array}{lr} 3 x-2 y+z= & 4 \\ 4 x+y-2 z= & -12 \\ 2 x-
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