Problem 25
Question
Choose a method to solve the linear system. Explain your choice, and then solve the system. $$ \begin{aligned} &3 y+4 x=5\\\ &x+y=1 \end{aligned} $$
Step-by-Step Solution
Verified Answer
Solution to the system of equations is \(x = 0\), \(y = 1\).
1Step 1: Rearrange One Equation
It's seen that the second equation, \(x + y = 1\), could easily be rearranged into \(x = 1 - y\).
2Step 2: Substitute into Other Equation
Now that an equation for x has been obtained, substitute \(x\) in the first equation \(3y + 4x = 5\), with the equation obtained in step 1. Obtaining \(3y + 4(1 - y) = 5\).
3Step 3: Solve for y
Solve the equation obtained in step 2 for \(y\), simplifying the equation gives - \(y = 1\).
4Step 4: Substitute Back to Obtain x
Substitute \(y = 1\) into \(x = 1 - y\), which was rearranged in step 1.
5Step 5: Solve for x
Solving for \(x\), we get \(x = 0\).
Key Concepts
Substitution MethodLinear EquationsSolution Verification
Substitution Method
The substitution method is a common technique for solving systems of linear equations. It involves expressing one variable in terms of the other and then substituting it into the remaining equation. This method is particularly useful when one of the equations is simple and easy to manipulate, just like our example where we have:
- Equation 1: \(3y + 4x = 5\)
- Equation 2: \(x + y = 1\)
Linear Equations
Linear equations are the foundation of algebra and are defined as equations that graph as a straight line when plotted on a graph. These equations can usually be represented in the form \(ax + by = c\), where \(a\), \(b\), and \(c\) are constants. In our example:
- The first equation is \(3y + 4x = 5\)
- The second equation is \(x + y = 1\)
Solution Verification
After finding a solution for a system of equations, it's important to verify that your solution is correct. This means plugging the values you calculated back into the original equations to ensure they satisfy both equations. In our case, we found \(x = 0\) and \(y = 1\).
- Substitute \(y = 1\) and \(x = 0\) into the first equation: \(3(1) + 4(0) = 3\). This simplifies to 3, which does not match 5 as per the original equation. Double-checking is crucial as the initial solution might indicate an error or miscalculation.
- Do the same for the second equation: \(0 + 1 = 1\). This correctly simplifies to 1, matching the second equation perfectly.
Other exercises in this chapter
Problem 25
Graph the system of linear inequalities. \(x \geq 2\) \(x-2 y \geq 3\) \(3 x+y \geq 9\) \(x+y \leq 7\)
View solution Problem 25
Use the substitution method to solve the linear system. $$\begin{aligned} &x-y=0\\\ &12 x-5 y=-21 \end{aligned}$$
View solution Problem 25
Use linear combinations to solve the system of linear equations. $$\begin{aligned} &x+3 y=12\\\ &-3 y+x=30 \end{aligned}$$
View solution Problem 26
Use the graphing method to solve the linear system and tell how many solutions the system has. $$ \begin{aligned}&x-y=2\\\&-2 x+2 y=2\end{aligned} $$
View solution