Problem 25
Question
Assume that the mathematics score \(X\) on the Scholastic Aptitude Test (SAT) is normally distributed with mean 500 and standard deviation 100 . (a) Find the probability that an individual's score exceeds 700 . (b) Find the math SAT score so that \(10 \%\) of the students who took the test have that score or greater.
Step-by-Step Solution
Verified Answer
(a) 0.0228; (b) Approximately 628.
1Step 1: Understanding the Problem
We need to calculate two probabilities involving a normally distributed SAT math score. For part (a), we need to determine the probability of a score exceeding 700. For part (b), we find the score beyond which the top 10% of students scored.
2Step 1: Standardize the Score for Part (a)
To find the probability of a score greater than 700, we first standardize 700 using the formula for a z-score: \[ z = \frac{X - \mu}{\sigma} \]where \(X = 700\), \(\mu = 500\), and \(\sigma = 100\). Calculating this gives:\[ z = \frac{700 - 500}{100} = 2 \]
3Step 2: Calculate Probability for Part (a)
Using the standard normal distribution table, find \(P(Z > 2)\). The value for \(P(Z < 2)\) is typically about 0.9772. Therefore, \[ P(Z > 2) = 1 - 0.9772 = 0.0228 \]Thus, the probability that an individual's score exceeds 700 is 0.0228.
4Step 3: Find Z-Score for Top 10% for Part (b)
For part (b), we need to find the score corresponding to the top 10%. This means you need the z-score where the cumulative probability is 0.90 (since 10% are above it). From the z-table, \(P(Z < z) = 0.90\) corresponds to a \(z \approx 1.2816\).
5Step 4: Convert Z-Score to Actual SAT Score for Part (b)
To convert this z-score to an SAT score, use the z-score formula in reverse:\[ X = \mu + z\sigma \]Substituting the values, we get:\[ X = 500 + (1.2816)(100) \approx 628.16 \]Therefore, about 10% of students scored 628 or higher.
Key Concepts
Standard DeviationZ-ScoreCumulative Probability
Standard Deviation
Standard deviation is a measure of how spread out numbers are in a dataset. In the context of a normal distribution, it helps describe how much scores deviate from the average, or mean, score.
When you're dealing with the standard deviation:
When you're dealing with the standard deviation:
- **Small Standard Deviation**: Most data points are close to the mean.
- **Large Standard Deviation**: Data points are more spread out from the mean.
Z-Score
The z-score is a way of standardizing scores on different scales to make them comparable. It measures the number of standard deviations a data point is from the mean.
For the SAT math scores:
For the SAT math scores:
- The z-score formula: \[ z = \frac{X - \mu}{\sigma} \]where \(X\) is the score, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.
- In step (a), to find the z-score for a score of 700, we used: \[ z = \frac{700 - 500}{100} = 2 \]
Cumulative Probability
Cumulative probability refers to the probability that a random variable is less than or equal to a certain value. In normal distribution, it's often visualized as the area under the curve to the left of a z-score.
Here's how it works using the SAT example:
Here's how it works using the SAT example:
- In step (a), we calculated the probability of a score exceeding 700, which involved finding \( P(Z > 2) \). This is 1 minus the cumulative probability of a z-score of 2: \[ P(Z > 2) = 1 - 0.9772 = 0.0228 \]
- For step (b), we sought the score where only 10% of students scored higher. We needed the z-score corresponding to a cumulative probability of 0.90, indicating 90% scored below it. This score translated back from the z-score was approximately 628.
Other exercises in this chapter
Problem 24
How often should you toss a coin to be at least \(90 \%\) certain that your estimate of \(P\) (heads) is within \(0.01\) of its true value?
View solution Problem 25
Assume that \(X\) is a discrete random variable with finite range, and set $$p(x)=P(X=x)$$ (a) Show that $$E(a X+b)=\sum_{x}(a x+b) p(x)$$ (b) Use your result i
View solution Problem 25
Roll a fair die twice and find the probability of at least one \(4 .\)
View solution Problem 25
A bag contains two coins, one fair and the other with two heads. You pick one coin at random and flip it. Find the probability that the outcome is heads.
View solution