Problem 25
Question
An initial amplitude \(k,\) damping constant \(c,\) and frequency \(f\) or period \(p\) are given. (Recall that frequency and period are related by the equation \(f=1 / p . )\) (a) Find a function that models the damped harmonic motion. Use a function of the form \(y=k e^{-c t} \cos \omega t\) in Exercises \(19-22,\) and of the form \(y=k e^{-c t} \sin \omega t\) in Exercises \(23-26\) (b) Graph the function. $$ k=0.3, \quad c=0.2, \quad f=20 $$
Step-by-Step Solution
Verified Answer
Function: \( y = 0.3 e^{-0.2 t} \cos (40\pi t) \); Graph shows high-frequency damping.
1Step 1: Determine Angular Frequency
The angular frequency \( \omega \) is determined by the frequency \( f \) using the formula \( \omega = 2\pi f \). Given \( f = 20 \), we find:\[\omega = 2\pi \times 20 = 40\pi.\]
2Step 2: Choose Function Form
The problem specifies using the cosine form for exercises 19-22. Therefore, the function should be of the form:\[ y = k e^{-ct} \cos \omega t. \]
3Step 3: Substitute Known Values
Substitute the given values into the function. We have \( k = 0.3 \), \( c = 0.2 \), and \( \omega = 40\pi \). Thus, the function becomes:\[ y = 0.3 e^{-0.2 t} \cos (40\pi t). \]
4Step 4: Graph the Function
To graph the function \( y = 0.3 e^{-0.2 t} \cos (40\pi t) \), consider plotting in a graphing calculator or software. The graph will feature oscillations with decreasing amplitude over time due to the exponential decay \( e^{-0.2 t} \). The term \( \cos (40\pi t) \) will generate rapid oscillations due to the high angular frequency.
Key Concepts
Angular FrequencyExponential DecayOscillationsGraphing Functions
Angular Frequency
Angular frequency, often denoted by \( \omega \), is a concept that links the frequency of an oscillation to its rotational characteristic. It tells us how fast something oscillates in a circular or repetitive manner. Angular frequency is measured in radians per second. This is different from regular frequency, which is usually measured in cycles per second, or Hertz (Hz).
- Frequency \( f \) is related to angular frequency by the formula \( \omega = 2\pi f \).
- In our example, the frequency \( f = 20 \), therefore the angular frequency is \( \omega = 40\pi \) radians per second.
Exponential Decay
Exponential decay is a process where a quantity decreases at a rate proportional to its current value. In the context of damped harmonic motion, it describes how the amplitude of oscillations reduces over time.
- The damping factor here is represented by the term \( e^{-ct} \).
- The constant \( c \) dictates the rate at which this decay happens.
Oscillations
Oscillations refer to the repeated back-and-forth motion around an equilibrium position. In the context of damped harmonic motion, these oscillations slowly decrease in amplitude over time due to damping.
- The function \( \cos(\omega t) \) describes these oscillations in the given system.
- Here, \( \omega = 40\pi \) means there are very rapid oscillations.
Graphing Functions
Graphing functions in damped harmonic motion provides a visual representation of the concepts discussed. The graph of our function \( y = 0.3 e^{-0.2t} \cos(40\pi t) \) shows how oscillations behave with respect to time.
- The \( e^{-0.2t} \) term causes the amplitude of oscillation to decrease exponentially, which can be seen as shrinking wave peaks over time.
- The \( \cos(40\pi t) \) term results in frequent oscillations, showing tight, rapidly-changing waves.
Other exercises in this chapter
Problem 24
23-32 \(\approx\) Find the terminal point \(P(X, y)\) on the unit circle determined by the given value of \(t\) $$ t=\frac{3 \pi}{2} $$
View solution Problem 25
Find the value of each of the six trigonometric functions (if it is defined) at the given real number \(t\). Use your answers to complete the table. \(t=0\)
View solution Problem 25
\(23-44=\) Find the exact value of the expression, if it is defined. \(\tan \left(\tan ^{-1} 5\right)\)
View solution Problem 25
\(17-28\) . Find the amplitude and period of the function, and sketch its graph. $$ y=-2 \sin 2 \pi x $$
View solution