Problem 25
Question
(a) Find an equation whose graph consists of all points equidistant from the points \((-1,2)\) and \((3,4)\). (b) Draw a sketch of the graph of the equation found in (a).
Step-by-Step Solution
Verified Answer
The equation is \y = -2x + 5\. The graph is a line passing through (1, 3) with a slope of -2.
1Step 1: Identify the Concept
The problem involves finding all points equidistant from two fixed points, which forms the perpendicular bisector of the line segment joining the points \((-1,2)\) and \((3,4)\).
2Step 2: Find the Midpoint
Calculate the midpoint of the line segment joining \((-1,2)\) and \((3,4)\) using the midpoint formula: \(\text{Midpoint} = \frac{ (x_1 + x_2)}{2}, \frac{(y_1 + y_2)}{2}) = \frac{-1 + 3}{2}, \frac{2 + 4}{2}) = (1,3)\).
3Step 3: Calculate the Slope of the Segment
Determine the slope of the line segment joining the points: \(m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{4 - 2}{3 - (-1)} = \frac{2}{4} = \frac{1}{2}\).
4Step 4: Find the Slope of the Perpendicular Bisector
The slope of the perpendicular bisector is the negative reciprocal of the slope of the segment. Therefore, it is: \(m_{\text{perp}} = -\frac{1}{\frac{1}{2}} = -2\).
5Step 5: Write the Equation of the Perpendicular Bisector
Using the point-slope form \(y - y_1 = m(x - x_1)\) and the midpoint \((1, 3)\), the equation of the perpendicular bisector is \y - 3 = -2(x - 1)\. Simplifying, \y - 3 = -2x + 2\ and \y = -2x + 5\.
6Step 6: Sketch the Graph
Draw the graph of the line \y = -2x + 5\. It should pass through the midpoint \((1, 3)\), and its slope should be -2. Also, plot the original points \((-1, 2)\) and \((3, 4)\) for reference.
Key Concepts
midpoint formulaslope calculationpoint-slope form
midpoint formula
The midpoint formula is a fundamental concept in geometry. It is used to find the exact middle point of a line segment
connecting two points, \((-1,2)\) and \((3,4)\). This formula helps greatly in problems where symmetry or bisecting a line is needed.
To find the midpoint, you add the x-coordinates of both points and divide by 2 for the x-coordinate of the midpoint.
You do the same for the y-coordinates to get the y-coordinate of the midpoint.
The formula is written as:
\[ \text{Midpoint} = \frac{{ (x_1 + x_2) }}{2}, \frac{{ (y_1 + y_2) }}{2} \]
Here's how it works with our points:
So, the midpoint is \((1, 3)\).
connecting two points, \((-1,2)\) and \((3,4)\). This formula helps greatly in problems where symmetry or bisecting a line is needed.
To find the midpoint, you add the x-coordinates of both points and divide by 2 for the x-coordinate of the midpoint.
You do the same for the y-coordinates to get the y-coordinate of the midpoint.
The formula is written as:
\[ \text{Midpoint} = \frac{{ (x_1 + x_2) }}{2}, \frac{{ (y_1 + y_2) }}{2} \]
Here's how it works with our points:
- Add the x-coordinates: \(-1 + 3 = 2 \)
- Divide by 2: \(\frac{2}{2} = 1 \)
- Add the y-coordinates: \(2 + 4 = 6 \)
- Divide by 2: \(\frac{6}{2} = 3 \)
So, the midpoint is \((1, 3)\).
slope calculation
Finding the slope of a line segment between two points is key to understanding the line's inclination.
The slope tells you how steep the line is. To calculate it, you need the difference in y-coordinates divided by the difference in x-coordinates.
This is particularly useful when you need to find perpendicular lines.
The formula for the slope, \(m\), is:
\[ m = \frac{ y_2 - y_1 }{ x_2 - x_1 } \]
Applying this to our points, \((-1,2)\) and \((3,4)\):
So, the slope of the line segment is \(\frac{1}{2}\).
The slope tells you how steep the line is. To calculate it, you need the difference in y-coordinates divided by the difference in x-coordinates.
This is particularly useful when you need to find perpendicular lines.
The formula for the slope, \(m\), is:
\[ m = \frac{ y_2 - y_1 }{ x_2 - x_1 } \]
Applying this to our points, \((-1,2)\) and \((3,4)\):
- Subtract the y-coordinates: \(4 - 2 = 2 \)
- Subtract the x-coordinates: \(3 - (-1) = 4 \)
- Divide the differences: \( \frac{2}{4} = \frac{1}{2} \)
So, the slope of the line segment is \(\frac{1}{2}\).
point-slope form
Point-slope form is one of the ways to write the equation of a line. It is especially useful when you have a point on the line
and the slope of the line. The general form of this equation is:
\[ y - y_1 = m(x - x_1) \]
Here, \( (x_1, y_1) \) is a specific point on the line, and \(m\) is the slope.
Using the midpoint \((1, 3)\) and the perpendicular slope \(-2\):
The final equation of the perpendicular bisector is \( y = -2x + 5 \). This line will pass through the midpoint \((1, 3)\)
and has a slope of \(-2\).
and the slope of the line. The general form of this equation is:
\[ y - y_1 = m(x - x_1) \]
Here, \( (x_1, y_1) \) is a specific point on the line, and \(m\) is the slope.
Using the midpoint \((1, 3)\) and the perpendicular slope \(-2\):
- Plug in the values:
\( y - 3 = -2(x - 1) \) - Simplify:
\( y - 3 = -2x + 2 \) - Add 3 to both sides:
\( y = -2x + 5 \)
The final equation of the perpendicular bisector is \( y = -2x + 5 \). This line will pass through the midpoint \((1, 3)\)
and has a slope of \(-2\).
Other exercises in this chapter
Problem 25
In Exercises 11 through 32 , find the solution set of the given inequality and illustrate the solution on the real number $$ 1-x-2 x^{2} \geq 0 $$
View solution Problem 25
In Exercises 7 through 28 , draw a sketch of the graph of the equation. $$ 4 x^{2}+y^{2}=0 $$
View solution Problem 25
Find equations of the three medians of the triangle having vertices \(A(3,-2), B(3,4)\), and \(C(-1,1)\), and prove that they meet in a point.
View solution Problem 26
In Exercises 11 through 34, the function is the set of all ordered pairs \((x, y)\) satisfying the given equation. Find the domain and range of the function, an
View solution