Problem 25
Question
23-26 \(\mathbf{}\) Do the graphs intersect in the given viewing rectangle? If they do, how many points of intersection are there? $$ y=6-4 x-x^{2}, y=3 x+18 ;[-6,2] \text { by }[-5,20] $$
Step-by-Step Solution
Verified Answer
The graphs intersect at two points within the viewing rectangle.
1Step 1: Understand the Problem
We need to determine whether the graphs of the equations \(y = 6 - 4x - x^2\) and \(y = 3x + 18\) intersect in the specified viewing rectangle \([-6, 2]\) by \([-5, 20]\). If they intersect, we should find the number of intersection points.
2Step 2: Set the Equations Equal to Each Other
To find the points of intersection, set the equations equal: \(6 - 4x - x^2 = 3x + 18\), and solve for \(x\).
3Step 3: Rearrange the Equation
Rearrange the equation to form a quadratic equation: \[- x^2 - 7x - 12 = 0.\]
4Step 4: Solve the Quadratic Equation
Use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) where \(a = -1\), \(b = -7\), and \(c = -12\) to solve for \(x\).
5Step 5: Calculate the Discriminant
The discriminant \(b^2 - 4ac\) helps determine the nature of the solutions. Calculate it:\[(-7)^2 - 4(-1)(-12) = 49 - 48 = 1.\]
6Step 6: Compute the Roots
Since the discriminant is positive, compute the roots:\[x = \frac{-(-7) \pm \sqrt{1}}{2(-1)} = \frac{7 \pm 1}{-2}.\]The roots are \(x = -4\) and \(x = -3\).
7Step 7: Verify the Points of Intersection
Substitute \(x = -4\) and \(x = -3\) back into either original equation to verify the \(y\)-coordinates:- For \(x = -4\): - Using the first equation: \(y = 6 - 4(-4) - (-4)^2 = 6 + 16 - 16 = 6\).- For \(x = -3\): - Using the first equation: \(y = 6 - 4(-3) - (-3)^2 = 6 + 12 - 9 = 9\).Both points fall within the given viewing rectangle.
Key Concepts
Quadratic EquationsDiscriminantFinding Roots
Quadratic Equations
A quadratic equation is a type of polynomial equation that follows the standard form: \[ ax^2 + bx + c = 0, \]where \(a, b,\) and \(c\) are constants, and \(a eq 0\). The graph of a quadratic equation is a parabola. Depending on the sign of \(a\), the parabola opens upwards (\(a > 0\)) or downwards (\(a < 0\)). For example, in the problem, the equation \(6 - 4x - x^2 = y\) represents a downward-opening parabola, due to the coefficient \(a = -1\) being negative.
Quadratic equations often arise in various contexts, such as projectile motion or finding the area of certain geometric shapes. They are crucial when determining the points of intersection between curves, as they provide values where two graphs meet.
Quadratic equations often arise in various contexts, such as projectile motion or finding the area of certain geometric shapes. They are crucial when determining the points of intersection between curves, as they provide values where two graphs meet.
- To solve a quadratic manually, we can factorize it, complete the square, or use the quadratic formula.
Discriminant
The discriminant is a powerful tool in determining the nature and number of solutions for a quadratic equation. It's derived from the quadratic formula itself and is given by:\[ b^2 - 4ac. \] In our case, with the equation \(-x^2 - 7x - 12 = 0\), the values are \(a = -1\), \(b = -7\), and \(c = -12\). Calculating the discriminant gives:\[ (-7)^2 - 4(-1)(-12) = 49 - 48 = 1. \]This value tells us a lot:
- If the discriminant is positive, there are two distinct real roots.
- If the discriminant is zero, there is one real root (a double root).
- If the discriminant is negative, there are no real roots, but two complex roots.
Finding Roots
Finding the roots or solutions of a quadratic equation means figuring out the values of \(x\) that satisfy the equation. This is where the quadratic formula comes into play:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. \]In the example, we first rearrange the intersection equation into quadratic form, then apply the formula with \(a = -1, b = -7, \) and \(c = -12\):\[x = \frac{-(-7) \pm \sqrt{1}}{2(-1)}.\]Solving this gives the roots:
- \(x = -4\)
- \(x = -3\)
Other exercises in this chapter
Problem 24
\(11-36\) Make a table of values and sketch the graph of the equation. Find the \(x\) - and \(y\) -intercepts. $$ x+y^{2}=4 $$
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Find an equation of the line that satisfies the given conditions. Slope \(3 ; \quad y\) intercept \(-2\)
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Express the statement as an equation. Use the given information to find the constant of proportionality. \(C\) is jointly proportional to \(I, w,\) and \(h .\)
View solution Problem 25
\(11-36\) Make a table of values and sketch the graph of the equation. Find the \(x\) - and \(y\) -intercepts. $$ y=\sqrt{x} $$
View solution