Problem 245
Question
For the following exercises, find the exact value. $$ \tan ^{-1}(\sqrt{3}) $$
Step-by-Step Solution
Verified Answer
\( \frac{\pi}{3} \)
1Step 1: Understand the Inverse Function
The function \( \tan^{-1}(x) \) is the inverse of the tangent function, thus it gives us an angle \( \theta \) such that \( \tan(\theta) = x \). In this problem, we need to find \( \theta \) for which \( \tan(\theta) = \sqrt{3} \).
2Step 2: Recall Tangent Values for Special Angles
Recall that \( \tan(\theta) = \sqrt{3} \) when \( \theta \) corresponds to one of the special angles on the unit circle. The standard angle with this tangent value is \( \frac{\pi}{3} \) (or 60 degrees) because \( \tan\left(\frac{\pi}{3}\right) = \frac{\sin\left(\frac{\pi}{3}\right)}{\cos\left(\frac{\pi}{3}\right)} = \frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}} = \sqrt{3}\).
3Step 3: Determine the Range of \( \tan^{-1}(x) \)
The range of \( \tan^{-1}(x) \) is \((-\frac{\pi}{2}, \frac{\pi}{2})\). The angle \( \frac{\pi}{3} \), which is approximately 1.047 radians, falls within this range. Therefore, it is a valid solution.
4Step 4: Conclude the Solution
Since the only angle within the range \((-\frac{\pi}{2}, \frac{\pi}{2})\) that satisfies \( \tan(\theta) = \sqrt{3} \) is \( \theta = \frac{\pi}{3} \), the exact value of \( \tan^{-1}(\sqrt{3}) \) is \( \frac{\pi}{3} \).
Key Concepts
Tangent FunctionSpecial AnglesUnit Circle
Tangent Function
The tangent function is a fundamental trigonometric function that often plays a critical role in various mathematical contexts. It relates to the ratio of the opposite side to the adjacent side in a right triangle. In terms of the unit circle, it is the ratio of the y-coordinate (sine) to the x-coordinate (cosine).
- Its representation is given by \( \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \).
- This means when either sine or cosine equals zero, the function reaches infinity, leading to asymptotes at these points.
- Unlike sine and cosine, the tangent function is periodic over \( \pi \) radians (or 180 degrees) instead of \( 2\pi \).
Special Angles
Special angles are key to quickly solving trigonometric problems without the need for a calculator. They are standardized angles whose sine, cosine, and tangent values are well-known.
- The basic special angles are \( 0, \frac{\pi}{6}, \frac{\pi}{4}, \frac{\pi}{3}, \frac{\pi}{2} \), equivalent to 0, 30, 45, 60, and 90 degrees, respectively.
- For these angles, trigonometric ratios such as \( \tan(\frac{\pi}{3}) = \sqrt{3} \) are memorized.
- These values are derived from specific right triangles like the 30-60-90 and 45-45-90 triangles, which provide consistent ratios among their sides.
Unit Circle
The unit circle is a circle of radius one, centered at the origin of a coordinate plane. It is a powerful tool in trigonometry since it defines trigonometric functions for all real numbers and helps visualize their behavior across the angles.
- Points on the unit circle are expressed in terms of their coordinates, \( (\cos(\theta), \sin(\theta)) \).
- These coordinates correspond to the angle formed with the positive x-axis.
- Tangent values can be found by the slope created by this angle from the origin to the circle's edge, which is \( \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \).
- The specific quadrant of the angle can affect the sign and value of these functions.
Other exercises in this chapter
Problem 242
For the following exercises, graph the function. Describe the graph and, wherever applicable, any periodic behavior, amplitude, asymptotes, or undefined points.
View solution Problem 244
For the following exercises, find the exact value. $$ \sin ^{-1}\left(\frac{\sqrt{3}}{2}\right) $$
View solution Problem 246
For the following exercises, find the exact value. $$ \cos ^{-1}\left(-\frac{\sqrt{3}}{2}\right) $$
View solution Problem 247
For the following exercises, find the exact value. $$ \cos ^{-1}(\sin (\pi)) $$
View solution