Problem 244
Question
In the following exercises, simplify. $$ (-2 \sqrt{11})(-4 \sqrt{22}) $$
Step-by-Step Solution
Verified Answer
88 \sqrt{2}
1Step 1 - Multiply the Constants
First, multiply the constants in the expression. The constants are -2 and -4. $$-2 \times -4 = 8$$
2Step 2 - Multiply the Radicals
Next, multiply the radicals together. The radicals are \( \sqrt{11} \) and \( \sqrt{22} \). Using the property \( \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} \), we get: $$ \sqrt{11} \cdot \sqrt{22} = \sqrt{242} $$
3Step 3 - Combine the Results
Now combine the product of the constants and the radicals: $$ 8 \sqrt{242} $$
4Step 4 - Simplify the Radical (if possible)
Finally, check if \( \sqrt{242} \) can be simplified further. The prime factors of 242 are 2, 11, and 11. Thus \( 242 = 2 \cdot 11^2 \).Hence, \( \sqrt{242} = \sqrt{2 \cdot 11^2} = 11 \sqrt{2} \). So the simplified form is: $$ 8 \cdot 11 \sqrt{2} = 88 \sqrt{2} $$
Key Concepts
Multiplying ConstantsMultiplying RadicalsSimplifying Square Roots
Multiplying Constants
Multiplying constants is an essential step when working with expressions that include numbers and radicals. Constants are the numbers written without a radical sign. For example, in the expression \( -2 \sqrt{11} \), \(-2\) is the constant part. To multiply constants, follow these simple steps:
\(-2 \times -4 = 8\).
Notice that multiplying two negative numbers gives a positive result. This is always the case with negative multiplication.
- Identify the constants in the expression.
- Multiply them directly just as you would with regular numbers.
\(-2 \times -4 = 8\).
Notice that multiplying two negative numbers gives a positive result. This is always the case with negative multiplication.
Multiplying Radicals
After dealing with the constants, we move on to multiplying the radicals. Radicals are the parts of the expression under the root sign, like \( \sqrt{11} \) and \(\b\sqrt{22} \). To multiply radicals:
\(\b\sqrt{11} \cdot \sqrt{22} = \sqrt{242} \).
This property allows us to combine the terms easily under a single radical.
- Combine the numbers under the radicals using multiplication.
- Use the property \( \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} \).
\(\b\sqrt{11} \cdot \sqrt{22} = \sqrt{242} \).
This property allows us to combine the terms easily under a single radical.
Simplifying Square Roots
Simplifying square roots can help us make the final expression much neater. To simplify a square root:
\(\b\sqrt{242} = \sqrt{2 \cdot 11^2} \).
Since \( 11^2 \) is a pair, it can be moved outside the radical:
\(\b\sqrt{242} = 11 \sqrt{2} \).
Finally, combine it with the constant we calculated earlier to get the simplified expression: \( 8 \cdot 11 \sqrt{2} = 88 \b\sqrt{2} \).
- Factor the number under the radical into its prime factors.
- Look for pairs of prime factors.
- Move pairs of prime factors out from under the radical, as they combine into a single number outside the radical.
\(\b\sqrt{242} = \sqrt{2 \cdot 11^2} \).
Since \( 11^2 \) is a pair, it can be moved outside the radical:
\(\b\sqrt{242} = 11 \sqrt{2} \).
Finally, combine it with the constant we calculated earlier to get the simplified expression: \( 8 \cdot 11 \sqrt{2} = 88 \b\sqrt{2} \).
Other exercises in this chapter
Problem 242
In the following exercises, simplify. $$ (6 \sqrt{2})(-\sqrt{10}) $$
View solution Problem 243
In the following exercises, simplify. $$ (-2 \sqrt{7})(-2 \sqrt{14}) $$
View solution Problem 245
In the following exercises, simplify. (a) \(\quad(\sqrt{15 y})\left(\sqrt{5 y^{3}}\right)\) (b) \(\left(\sqrt{2 n^{2}}\right)\left(\sqrt{18 n^{3}}\right)\)
View solution Problem 246
In the following exercises, simplify. (a) \(\left(\sqrt{14 x^{3}}\right)\left(\sqrt{7 x^{3}}\right)\) (b) \(\left(\sqrt{3 q^{2}}\right)\left(\sqrt{48 q^{3}}\rig
View solution