Problem 243
Question
Sketch the graph of the exponential function. Determine the domain, range, and horizontal asymptote. \(f(x)=1-2^{-x}\)
Step-by-Step Solution
Verified Answer
Domain: \((-\infty, \infty)\); Range: \((-\infty, 1)\); Horizontal Asymptote: \(y = 1\).
1Step 1: Identify the Base Function
The given function is \(f(x) = 1 - 2^{-x}\). Here, the base function is \(g(x) = 2^{-x}\), which is an exponential function. The standard form of an exponential function is \(a^{x}\), where \(a > 0\). In this case, \(a = \frac{1}{2}\).
2Step 2: Determine the Transformation
The transformation applied to \(g(x) = 2^{-x}\) is a vertical shift. The term \(1 - g(x)\) indicates that the graph of \(2^{-x}\) is reflected across the x-axis and then shifted up by 1 unit. The function \(f(x)\) is obtained by taking the inverted and shifted version of \(2^{-x}\).
3Step 3: Sketch the Basic Graph
Start by sketching the graph of \(2^{-x}\), which decreases rapidly as \(x\) increases. Then reflect this graph across the x-axis and shift it up by 1 unit to obtain the graph for \(f(x) = 1 - 2^{-x}\).
4Step 4: Determine the Domain
The domain of an exponential function like \(f(x) = 1 - 2^{-x}\) is all real numbers, written as \((-\infty, \infty)\). This is because you can substitute any real number for \(x\).
5Step 5: Determine the Range
For the function \(f(x) = 1 - 2^{-x}\), as \(x\) approaches infinity, \(2^{-x}\) approaches zero, making \(f(x)\) approach 1. Conversely, as \(x\) approaches negative infinity, \(2^{-x}\) becomes very large, making \(1 - 2^{-x}\) deeply negative. Thus, the range is \((-\infty, 1)\).
6Step 6: Identify the Horizontal Asymptote
The horizontal asymptote is the line that the function approaches as \(x\) approaches infinity or negative infinity. For \(f(x) = 1 - 2^{-x}\), the horizontal asymptote is \(y = 1\). As \(x\) goes to infinity, \(f(x)\) approaches but does not reach this value.
Key Concepts
Domain and RangeHorizontal AsymptoteTransformations of Functions
Domain and Range
The domain of an exponential function refers to all the possible values that the variable, often denoted as \(x\), can take. For the function \(f(x) = 1 - 2^{-x}\), there are no limitations on \(x\). You can substitute any real number into the function, leading to a domain of \((-æfty, æfty)\).
In contrast, the range of the function describes all possible output values. To find the range for \(f(x) = 1 - 2^{-x}\), let's analyze the behavior of the function as \(x\) changes: - As \(x\) increases toward infinity, \(2^{-x}\) tends toward zero, causing \(f(x)\) to approach the value 1.
- As \(x\) decreases (tends toward negative infinity), \(2^{-x}\) grows significantly large, thus making \(1 - 2^{-x}\) a very negative number.
Combining these insights, the range of \(f(x)\) is \((-æfty, 1)\), meaning the outputs will cover all real numbers less than 1.
In contrast, the range of the function describes all possible output values. To find the range for \(f(x) = 1 - 2^{-x}\), let's analyze the behavior of the function as \(x\) changes: - As \(x\) increases toward infinity, \(2^{-x}\) tends toward zero, causing \(f(x)\) to approach the value 1.
- As \(x\) decreases (tends toward negative infinity), \(2^{-x}\) grows significantly large, thus making \(1 - 2^{-x}\) a very negative number.
Combining these insights, the range of \(f(x)\) is \((-æfty, 1)\), meaning the outputs will cover all real numbers less than 1.
Horizontal Asymptote
A horizontal asymptote is a horizontal line that a function approaches as \(x\) heads towards infinity or negative infinity. It represents a value that the function will get arbitrarily close to but never quite reach. For \(f(x) = 1 - 2^{-x}\), the function approaches the value of 1 as \(x\) becomes very large (positive). This behavior is due to \(2^{-x}\) nearing zero, resulting in \(f(x) \approx 1\).
Therefore, the horizontal asymptote for this function is the line \(y = 1\). It's important to note that the graph will never actually cross this asymptote, serving instead as a "boundary" for where the function's outputs can approach but not surpass.
Therefore, the horizontal asymptote for this function is the line \(y = 1\). It's important to note that the graph will never actually cross this asymptote, serving instead as a "boundary" for where the function's outputs can approach but not surpass.
Transformations of Functions
Exponentials can be shifted and transformed in various ways, affecting their graphs. In the case of \(f(x) = 1 - 2^{-x}\), there are noticeable transformations applied to the base function \(g(x) = 2^{-x}\).
Here are the transformations to focus on:
Understanding transformations is crucial because it helps predict changes in the graph's position and style without recalculating each individual point.
Here are the transformations to focus on:
- Reflection: The negative sign in \(-2^{-x}\) indicates a reflection across the x-axis, flipping the graph upside down.
- Vertical Shift: The "+1" part of the equation \(1 - 2^{-x}\) signifies a vertical shift upward by 1 unit. This raises the entire graph one unit higher on the coordinate plane.
Understanding transformations is crucial because it helps predict changes in the graph's position and style without recalculating each individual point.
Other exercises in this chapter
Problem 242
Sketch the graph of the exponential function. Determine the domain, range, and horizontal asymptote. \(f(x)=4^{x}-1\)
View solution Problem 243
For the following exercises, sketch the graph of the exponential function. Determine the domain, range, and horizontal asymptote. $$ f(x)=1-2^{-x} $$
View solution Problem 244
For the following exercises, sketch the graph of the exponential function. Determine the domain, range, and horizontal asymptote. $$ f(x)=5^{x+1}+2 $$
View solution Problem 244
Sketch the graph of the exponential function. Determine the domain, range, and horizontal asymptote. \(\quad f(x)=5^{x+1}+2\)
View solution