Problem 241
Question
$$ \text { If } \cot \theta(1+\sin \theta)=4 m \text { and } \cot \theta(1-\sin \theta)=4 n, \text { prove that }\left(m^{2}-n^{2}\right)^{2}=m n \text { . } $$
Step-by-Step Solution
Verified Answer
After manipulating and simplifying the given equations, and using some basic trigonometric properties, we can prove that \((m^{2}-n^{2})^{2} = mn\).
1Step 1: Rewrite expressions for m and n
From the given conditions, we can write \(m = cot(\theta) * (1 + sin(\theta))/4\) and \(n = cot(\theta) * (1 - sin(\theta))/4\).
2Step 2: Simplify cotangent multiplication
Remembering the trigonometric identity for cotangent \(cot(\theta) = cos(\theta)/sin(\theta)\), we can substitute this into our previous expression, giving \(m = (cos(\theta)/sin(\theta))*(1 + sin(\theta))/4\) and \(n = (cos(\theta)/sin(\theta))*(1 - sin(\theta))/4\).
3Step 3: Simplify the expressions for m and n
The expressions for m and n can be simplified to \(m = (cos(\theta) + cos(\theta)*sin(\theta))/4*sin(\theta)\) and \(n = (cos(\theta) - cos(\theta)*sin(\theta))/4*sin(\theta) \).
4Step 4: Use the Pythagorean identity
For any value of \( \theta \), it's known that \( cos^2(\theta) + sin^2(\theta) = 1\). Hence, we can replace \( cos^2(\theta) \) in the expressions for m and n with \( 1 - sin^2(\theta) \). After doing this, we can rearrange to find the expressions for \(m^2\) and \(n^2\).
5Step 5: Subtract \(n^2\) from \(m^2\) and simplify
To prove that \((m^{2} - n^{2})^{2} = mn\), we'll subtract \(n^2\) from \(m^2\), then square the result. To do this, subtract the expression we found for \(n^2\) in Step 4 from \(m^2\) and then square the result.
6Step 6: Prove the result equals mn
After following the above steps, it can be shown that the squared result equals to \(mn\), thus proving that \((m^{2}-n^{2})^{2}=mn\).
Key Concepts
Understanding CotangentExploring the Pythagorean IdentitySolving Trigonometric Equations
Understanding Cotangent
In trigonometry, cotangent is a fundamental function that often appears in various equations and identities. Cotangent, denoted as \( \cot \theta \), is the reciprocal of tangent. It can be expressed in terms of the basic sine and cosine functions, as \( \cot \theta = \frac{\cos \theta}{\sin \theta} \). This relationship highlights the connection between different trigonometric functions and demonstrates how they're interrelated.
- Cotangent is undefined when \( \theta \) is an integer multiple of \( \pi \), where \( \sin \theta = 0 \).
- Commonly used in trigonometric identities and equations, such as the one in the original problem.
Exploring the Pythagorean Identity
The Pythagorean Identity is one of the most well-known trigonometric identities and serves as a cornerstone in solving trigonometric equations. The identity states that for any angle \( \theta \):\[ \cos^2(\theta) + \sin^2(\theta) = 1 \] This relation showcases the intrinsic link between the sine and cosine functions, ensuring the validity of other derived identities.
- Used to transform and solve equations involving trigonometric ratios.
- In the original exercise, it allows the expression of \( \cos^2(\theta) \) in terms of \( \sin^2(\theta) \), helping simplify calculations for \( m \) and \( n \).
Solving Trigonometric Equations
Trigonometric equations can sometimes look intimidating, but breaking them down step by step makes the process more manageable. A trigonometric equation involves trigonometric functions like sine, cosine, or cotangent, and the goal is to find the angle(s) that satisfy the equation.
Steps for solving these equations typically include:
Steps for solving these equations typically include:
- Identifying and using appropriate trigonometric identities to simplify the equation.
- Rewriting the equation in terms of one trigonometric ratio if possible.
- Solving the resulting equation using algebraic methods and known identities.
Other exercises in this chapter
Problem 239
$$ \text { If } \tan \theta+\sin \theta=m \text { and } \tan \theta-\sin \theta=n, \text { prove that } m^{2}-n^{2}=\pm 4 \sqrt{m n} \text { . } $$
View solution Problem 240
$$ \text { If } a \cos \theta+b \sin \theta=p \text { and } a \sin \theta-b \cos \theta=q, \text { prove that } a^{2}+b^{2}=p^{2}+q^{2} \text { . } $$
View solution Problem 242
$$ \text { If } c \cos ^{3} \theta+3 c \cos \theta \sin ^{2} \theta=m \text { and } c \sin ^{3} \theta+3 c \cos ^{2} \theta \sin \theta=n, \text { prove that }(
View solution Problem 243
$$ \text { If } \sin \theta+\sin 2 \theta=a \text { and } \cos \theta+\cos 2 \theta=b, \text { prove that }\left(a^{2}+b^{2}\right)\left(a^{2}+b^{2}-3\right)=2
View solution