Problem 24
Question
You light a \(25-W\) light bulb with the current from a \(12-V\) lead-acid storage battery. Calculate how much energy the light bulb utilized after \(1.0 \mathrm{~h}\) of operation. Calculate how many coulombs passed through the bulb. Assume \(100 \%\) efficiency. \((1 \mathrm{~W}=1 \mathrm{~J} / \mathrm{s} .)\)
Step-by-Step Solution
Verified Answer
Energy used: 90000 J; Charge passed: 7488 C.
1Step 1: Understanding Energy Consumption
Since power is given by the formula \( P = \frac{E}{t} \), where \( E \) is energy in joules and \( t \) is time in seconds, we can rearrange it to find \( E = P \times t \).
2Step 2: Converting Time to Seconds
The time given is \(1.0 \h\), which needs to be converted into seconds. Thus, \( t = 1.0 \times 3600 \text{ seconds} = 3600 \text{ seconds} \).
3Step 3: Calculating Energy Used by the Light Bulb
Substitute the values into the energy formula: \( E = 25 \text{ W} \times 3600 \text{ s} = 90000 \text{ J} \). So, the light bulb used \( 90000 \text{ joules} \) of energy.
4Step 4: Understanding Charge Flow
The current \( I \) can be calculated using \( P = VI \), where \( V \) is the voltage. Rearrange to find \( I = \frac{P}{V} \).
5Step 5: Calculating Current Through the Bulb
Substitute the known values into the formula: \( I = \frac{25 \text{ W}}{12 \text{ V}} = 2.08 \text{ A} \).
6Step 6: Calculating Total Charge
Charge \( Q \) can be calculated using \( Q = I \times t \). Substitute \( I = 2.08 \text{ A} \) and \( t = 3600 \text{ s} \): \( Q = 2.08 \times 3600 = 7488 \text{ C} \). So, \( 7488 \text{ coulombs} \) passed through the bulb.
Key Concepts
Power CalculationElectric ChargeCoulombsLead-Acid BatteryElectric CurrentEnergy Conversion
Power Calculation
In the realm of physics, power refers to the rate at which energy is used or transferred, and it is usually measured in watts (W). To calculate the power consumed by a device, we use the formula:
In this scenario, a 25-watt light bulb is the focus, which implies it consumes 25 joules of energy per second. Applying this understanding allows us to deduce how much energy is consumed over a more extended period of time, by rearranging the formula to find \( E \) if needed.
- \( P = \frac{E}{t} \)
In this scenario, a 25-watt light bulb is the focus, which implies it consumes 25 joules of energy per second. Applying this understanding allows us to deduce how much energy is consumed over a more extended period of time, by rearranging the formula to find \( E \) if needed.
Electric Charge
Electric charge is a fundamental property of matter that interacts with electric fields to produce current. Charges are generally denoted by \( Q \) and measured in coulombs. In electricity, charge relates to the flow of electrons through a conductor, creating what we observe as electric current.
Within a circuit, understanding electric charge is crucial as it affects how devices power up and function. When a current flows through a bulb, it carries a flow of charges that illuminate the bulb and is a key factor in power calculations.
Within a circuit, understanding electric charge is crucial as it affects how devices power up and function. When a current flows through a bulb, it carries a flow of charges that illuminate the bulb and is a key factor in power calculations.
Coulombs
The coulomb (named after Charles-Augustin de Coulomb) is the SI unit of electric charge. It's the amount of charge transported by a constant current of one ampere in one second. Coulombs provide a tangible way to quantify electric charge in energy-related calculations.
In our example, after one hour of operation, 7488 coulombs of charge pass through the light bulb, highlighting the volume of charge movement in that time frame.
Formula used:
In our example, after one hour of operation, 7488 coulombs of charge pass through the light bulb, highlighting the volume of charge movement in that time frame.
Formula used:
- \( Q = I \times t \), where \( I \) is current and \( t \) is time.
Lead-Acid Battery
A lead-acid battery is a type of rechargeable battery commonly used in vehicles and backup power systems due to its reliability and cost-effectiveness. It consists of lead dioxide and sponge lead with an electrolyte solution of sulfuric acid.
For this exercise, the battery provides 12 volts to the light bulb. This voltage influences how much current flows through the bulb according to Ohm's Law (\( V = IR \)). In this manner, it's capable of powering devices such as our light bulb continuously for the required duration.
For this exercise, the battery provides 12 volts to the light bulb. This voltage influences how much current flows through the bulb according to Ohm's Law (\( V = IR \)). In this manner, it's capable of powering devices such as our light bulb continuously for the required duration.
Electric Current
Electric current is the flow of electric charge along a conductor, measured in amperes (A). It quantifies how much charge passes a point in a circuit per second.
Current generation relies on the movement of electrons and is driven by voltage from a power source like a battery. In this exercise, we calculate the current flowing through a 25-Watt bulb using the relationship:
Current generation relies on the movement of electrons and is driven by voltage from a power source like a battery. In this exercise, we calculate the current flowing through a 25-Watt bulb using the relationship:
- \( I = \frac{P}{V} \)
Energy Conversion
Energy conversion entails changing one form of energy to another. In electrical applications, it's often the transformation of electrical energy into light, heat, or motion.
Here, the energy stored in the lead-acid battery is converted to light energy by the light bulb. This transformation is typically governed by the principle of efficiency, although the exercise assumes a 100% conversion rate for simplicity.
Understanding this helps in designing systems and choosing components that maximize energy use effectively to power different loads efficiently.
Here, the energy stored in the lead-acid battery is converted to light energy by the light bulb. This transformation is typically governed by the principle of efficiency, although the exercise assumes a 100% conversion rate for simplicity.
Understanding this helps in designing systems and choosing components that maximize energy use effectively to power different loads efficiently.
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