Problem 24
Question
Write a formula for the general term (the nth term) of each arithmetic sequence. Do not use a recursion formula. Then use the formula for \(a_{n}\) to find \(a_{20}\), the 20 th term of the sequence. $$ 2,7,12,17, \dots $$
Step-by-Step Solution
Verified Answer
The 20th term of the given arithmetic sequence is 97.
1Step 1: Identify the common difference
The common difference (d) of an arithmetic sequence is the difference between any two successive terms. It is constant throughout the sequence. Looking at the sequence, take the second term (7) and subtract the first term (2) to calculate the common difference: \(d = 7 - 2 = 5\).
2Step 2: Write the formula for the nth term of the arithmetic sequence
The generic formula for the nth term of an arithmetic sequence is: \(a_{n} = a_{1} + (n-1)*d\), where \(a_{1}\) is the first term and d is the common difference. Substituting the known values in, the formula becomes: \(a_{n} = 2 + (n-1)*5\).
3Step 3: Compute the 20th term of the sequence
Substitute n = 20 into the formula: \(a_{20} = 2 + (20-1)*5\). Simplify it to get the 20th term: \(a_{20} = 2 + 19*5 = 2 + 95 = 97\). Hence, the 20th term of the sequence is 97.
Key Concepts
Common DifferenceNth Term FormulaSequence Calculation
Common Difference
One of the fundamental concepts in understanding arithmetic sequences is the **common difference**. In an arithmetic sequence, this value remains constant across the entire sequence and is simply the difference between successive terms.
To find the common difference, take any term in the sequence and subtract the previous term from it. For example, consider the sequence: 2, 7, 12, 17, \(\dots\). If we take the second term, 7, and subtract the first term, 2, we obtain:
When dealing with arithmetic sequences, identifying this difference correctly is vital, as it is the building block for forming the formula that can determine any term in the sequence.
To find the common difference, take any term in the sequence and subtract the previous term from it. For example, consider the sequence: 2, 7, 12, 17, \(\dots\). If we take the second term, 7, and subtract the first term, 2, we obtain:
- **Common Difference (\(d\))**: \(7 - 2 = 5\)
When dealing with arithmetic sequences, identifying this difference correctly is vital, as it is the building block for forming the formula that can determine any term in the sequence.
Nth Term Formula
The **nth term formula** provides a method to locate any term in an arithmetic sequence, without having to list all previous terms. This formula is a crucial tool for sequence calculation and is expressed as:
\[ a_{n} = a_{1} + (n-1) \cdot d \]
Here:
\[ a_{n} = 2 + (n-1) \cdot 5 \]
This simplified formula results from substituting \(a_{1} = 2\) and \(d = 5\) into the general formula.
\[ a_{n} = a_{1} + (n-1) \cdot d \]
Here:
- \(a_{n}\) is the nth term we want to find.
- \(a_{1}\) is the first term of the sequence.
- \(n\) is the term number we are interested in.
- \(d\) is the common difference.
\[ a_{n} = 2 + (n-1) \cdot 5 \]
This simplified formula results from substituting \(a_{1} = 2\) and \(d = 5\) into the general formula.
Sequence Calculation
Once you've established the common difference and the nth term formula, you can perform the **sequence calculation** to find any specific term in the series. Let's see how this plays out using our sequence example and finding the 20th term.
First, substitute n for the term number you wish to calculate—in this case, n equals 20. We already have our nth term formula:
\[ a_{n} = 2 + (n-1) \cdot 5 \]
Substitute \(n = 20\) into the formula:
First, substitute n for the term number you wish to calculate—in this case, n equals 20. We already have our nth term formula:
\[ a_{n} = 2 + (n-1) \cdot 5 \]
Substitute \(n = 20\) into the formula:
- \(a_{20} = 2 + (20-1) \cdot 5\)
- Simplify: \(a_{20} = 2 + 19 \cdot 5\)
- Calculate: \(a_{20} = 2 + 95 = 97\)
Other exercises in this chapter
Problem 24
Evaluate each expression. \(1-\frac{_{5} P_{3}}{_{10} P_{4}}\)
View solution Problem 24
Use mathematical induction to prove that each statement is true for every positive integer n. \(\frac{1}{2 \cdot 3}+\frac{1}{3 \cdot 4}+\frac{1}{4 \cdot 5}+\cdo
View solution Problem 25
Use the formula for the sum of the first n terms of a geometric sequence to solve. Find the sum of the first 12 terms of the geometric sequence: $2,6,18,54,
View solution Problem 25
Use the Binomial Theorem to expand each binomial and express the result in simplified form. $$ (x-1)^{5} $$
View solution