Problem 24
Question
When \(b^{2}-4 a c=0,\) is \(a x^{2}+b x+c\) a perfect square trinomial or a constant times a perfect square trinomial? Explain why or why not.
Step-by-Step Solution
Verified Answer
Yes, it is a constant times a perfect square trinomial because the discriminant is zero, resulting in a repeated root.
1Step 1: Identify the Discriminant
The discriminant for a quadratic function \( ax^2 + bx + c \) is given by the formula \( b^2 - 4ac \). This value helps to determine the nature of the roots of the quadratic equation. In the given problem, we know \( b^2 - 4ac = 0 \).
2Step 2: Roots of the Quadratic Equation
When the discriminant \( b^2 - 4ac = 0 \), it implies that the quadratic equation \( ax^2 + bx + c = 0 \) has exactly one distinct root, meaning it has a repeated root or double root. This can be expressed as \( x = \frac{-b}{2a} \).
3Step 3: Recognizing Perfect Square Trinomial
A perfect square trinomial is a quadratic expression that can be rewritten as \( (px + q)^2 \). With a zero discriminant, \( ax^2 + bx + c \) can be expressed as \( a(x + \frac{b}{2a})^2 \), showing that the quadratic is a constant factor \( a \) times a perfect square trinomial.
4Step 4: Verification with the Perfect Square Formula
The perfect square trinomial \( (px + q)^2 \) expands to \( p^2x^2 + 2pqx + q^2 \). Here \( p = \sqrt{a} \), \( q = \frac{b}{2\sqrt{a}} \). Simplifying, it relates back to \( ax^2 + bx + c \), confirming it is a constant times a perfect square trinomial.
Key Concepts
Quadratic FunctionDiscriminantRoots of a Quadratic EquationRepeated Root
Quadratic Function
A quadratic function is a mathematical expression of the form \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \). The graph of a quadratic function is a parabola, which can open upwards or downwards depending on the sign of \( a \). These functions are key in algebra because they describe a wide range of natural phenomena and situations, like projectile motion and area calculations. To better understand them, let's break them down a bit more:
- The term \( ax^2 \) is the quadratic term, responsible for the parabola's curvature.
- The term \( bx \) is the linear term, affecting the slope and direction of the curve.
- The term \( c \) is the constant term, which shifts the graph up or down on the y-axis.
Discriminant
The discriminant of a quadratic function \( ax^2 + bx + c \) is found using the formula \( b^2 - 4ac \). It serves a crucial role in determining the nature of the roots of the quadratic equation. The discriminant tells us how many solutions, or roots, a quadratic equation will have and what type they will be. Here’s how it works:
- If \( b^2 - 4ac > 0 \), the equation has two distinct real roots.
- If \( b^2 - 4ac = 0 \), the equation has one real root, known as a repeated root.
- If \( b^2 - 4ac < 0 \), the equation has no real roots, but two complex conjugate roots instead.
Roots of a Quadratic Equation
The roots of a quadratic equation are the values of \( x \) that satisfy the equation \( ax^2 + bx + c = 0 \). The process of finding these roots is called solving the quadratic equation. The roots can be determined using the quadratic formula:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]The discriminant \( b^2 - 4ac \) decides the number and type of roots. For example, when \( b^2 - 4ac = 0 \), there's exactly one root. This root is termed a repeated or double root since it's the only solution and appears twice in the context of the quadratic formula:
- The formula simplifies to \( x = \frac{-b}{2a} \), highlighting the root's simplicity.
Repeated Root
A repeated root, also known as a double root, is a root that occurs when a quadratic equation has a discriminant of zero. When this happens, the quadratic function \( ax^2 + bx + c \) does not cross the x-axis twice, but rather just touches it at a single point. The repeated root is calculated as \( x = \frac{-b}{2a} \).Understanding the concept of a repeated root can be quite useful:
- It signifies that the graph of the function is tangent to the x-axis.
- It highlights symmetry, as this point is the vertex of the parabola.
- It implies that the quadratic expression can be rewritten as a square, specifically \( a(x + \frac{b}{2a})^2 \), a key characteristic of perfect square trinomials.
Other exercises in this chapter
Problem 24
In \(19-28 :\) a. Find \(\mathrm{f}(a)\) for each given function. b. Is \(a\) a root of the function? $$ f(x)=2 x^{3}+3 x^{2}-1 \text { and } a=\frac{1}{2} $$
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One of the roots is given. Find the other root. \(m^{2}-4 m+n=0 ; 3\)
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In \(18-25,\) write the complex conjugate of each number. $$ \frac{5}{3}-\frac{2}{3} i $$
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In \(19-34,\) write each sum or difference in terms of \(i\) $$ 2 \sqrt{-5}+\sqrt{-125} $$
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