Problem 24
Question
Using Properties of Logarithms In Exercises \(21-36\) , find the exact value of the logarithmic expression without using a calculator. (If this is not possible, then state the reason.) $$\log _{6} \sqrt[3]{6}$$
Step-by-Step Solution
Verified Answer
The exact value of \(\log_{6}\sqrt[3]{6}\) is \(1/3\).
1Step 1: Understanding Cube Roots
Express the cubic root of 6 as a power of 6. Recall that the cube root of a number \(n\) is equivalent to raising \(n\) to the power of \(1/3\). Therefore, we can write \(\sqrt[3]{6}\) as \(6^{1/3}\).
2Step 2: Solve using Logarithm Properties
The logarithm property \(\log_{b}(a^m) = m \log_{b}a\) states that the exponent on the argument of a logarithm can be brought out front and multiplied by the logarithm. Applying this property to our expression, we have \(\log_{6}6^{1/3} = (1/3) \log_{6}6\).
3Step 3: Compute the Logarithm
Finally, compute the logarithm \(\log_{6}6\). Any logarithm base \(b\) of \(b\) is always 1, so \(\log_{6}6 = 1\), since \(6^1 = 6\). Multiplying this by \(1/3\), we get the result.
Key Concepts
Properties of LogarithmsCube RootsExponents
Properties of Logarithms
Logarithms have several useful properties that make calculations simpler. Understanding these properties lets us transform complex logarithmic expressions into more manageable forms. Here are some key properties you should know:
- Power Rule: The property \(\log_{b}(a^m) = m \log_{b} a\) tells us how to manage expressions that contain exponents within a logarithm. This allows you to bring the exponent, \(m\), in front of the logarithmic expression as a product.
- Product Rule: The property \(\log_{b}(mn) = \log_{b} m + \log_{b} n\) helps in splitting the logarithm of a product into the sum of two logarithms.
- Quotient Rule: The property \(\log_{b}\left(\frac{m}{n}\right) = \log_{b} m - \log_{b} n\) allows for the division inside a logarithm to be transformed into the difference of two logarithms.
Cube Roots
Cube roots are a specific type of root used frequently in mathematics. When you take the cube root of a number, you are looking for a value that, when multiplied by itself three times, gives the original number.To express a cube root as an exponent, we use powers. For example, the cube root of 6 is expressed as \(\sqrt[3]{6}\), which is equivalent to \(6^{1/3}\). This fractional exponent representation is helpful in logarithmic calculations because it allows us to apply logarithm properties, like the power rule, to simplify expressions.Understanding how roots and exponents relate is important because it opens up the ability to move between these two forms easily. This is evident in our task where \(\sqrt[3]{6}\) was transformed to \(6^{1/3}\) to utilize logarithmic properties effectively.
Exponents
Exponents are a foundational part of algebra that describe how many times a number, known as the base, is multiplied by itself. For example, in the term \(b^n\), \(b\) is the base and \(n\) is the exponent. Exponents can also be fractional, where the numerator indicates a power and the denominator indicates a root. A common example is the expression \(b^{1/3}\), which corresponds to the cube root of \(b\). This concept links closely with how we computed \(\log_{6} \sqrt[3]{6}\) by rewriting the cubic root as an exponent.Knowing how to manipulate expressions with exponents (including fractional ones) is vital for using logarithms effectively. It helps when applying properties like the power rule, simplifying the calculation process and solving expressions without a calculator.
Other exercises in this chapter
Problem 23
Use a calculator to evaluate \(f(x)=\log x\) at the indicated value of \(x .\) Round your result to three decimal places. \(x=12.5\)
View solution Problem 23
Complete the table assuming continuously compounded interest. $$ \begin{array}{llll} \text { Isotope} & \text { Half-Life } & \text { Initial Quantity } & \text
View solution Problem 24
Solve the exponential equation algebraically. Approximate the result to three decimal places. \(4^{-3 t}=0.10\)
View solution Problem 24
Using the One-to-One Property In Exercises \(23-26\) use the One-to-One Property to solve the equation for \(x .\) $$2^{x-3}=16$$
View solution