Problem 24
Question
Use the quadratic formula to solve each equation. These equations have real solutions and complex, but not real, solutions. $$ x^{2}+2 x+2=0 $$
Step-by-Step Solution
Verified Answer
The solutions are \(x = -1 + i\) and \(x = -1 - i\).
1Step 1: Identify Coefficients
First, identify the coefficients for the quadratic equation, which is in the form \(ax^2 + bx + c = 0\). Here, \(a = 1\), \(b = 2\), and \(c = 2\).
2Step 2: Write the Quadratic Formula
The quadratic formula is used to find the roots of a quadratic equation. It is given by: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
3Step 3: Calculate the Discriminant
The discriminant \(b^2 - 4ac\) determines the nature of the roots. Substitute the values: \[ b^2 - 4ac = 2^2 - 4 imes 1 imes 2 = 4 - 8 = -4 \]
4Step 4: Discriminant Indicates Complex Solutions
Since the discriminant \(-4\) is negative, the quadratic equation has complex solutions.
5Step 5: Apply the Quadratic Formula
Substitute the values of \(a\), \(b\), and \(c\) into the quadratic formula: \[ x = \frac{-2 \pm \sqrt{-4}}{2 \times 1} \] Simplify under the square root, \(\sqrt{-4} = 2i\), where \(i\) is the imaginary unit.
6Step 6: Simplify the Expression
Now, simplify the equation to solve for \(x\): \[ x = \frac{-2 \pm 2i}{2} \]Split this fraction: \[ x = -1 \pm i \]
Key Concepts
Quadratic Equation SolutionsDiscriminant in Quadratic EquationsComplex Numbers in AlgebraSolving Quadratic Equations
Quadratic Equation Solutions
Quadratic equations take the form of \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants. These equations can have one, two, or no real solutions, all depending on the discriminant which we'll discuss later. The solutions to quadratic equations are the x-values, or roots, where the equation is satisfied, meaning it equals zero. To find these solutions, the quadratic formula is often used, especially when the quadratic does not easily factor. The formula is given by:
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
Discriminant in Quadratic Equations
The discriminant, represented by \(b^2 - 4ac\), plays a critical role in helping us understand the nature of the roots in quadratic equations. It is derived from within the square root part of the quadratic formula. Depending on its value, we can determine what types of solutions our equation has. Here’s what you need to know:
- If \(b^2 - 4ac > 0\), the equation has two distinct real solutions.
- If \(b^2 - 4ac = 0\), there is one real solution, sometimes called a repeated or double root.
- If \(b^2 - 4ac < 0\), the roots are complex, indicating that they are not real numbers.
Complex Numbers in Algebra
When faced with a negative discriminant in a quadratic equation, complex numbers come into play. Complex numbers extend the idea of one-dimensional numbers (like real numbers) to a two-dimensional plane, allowing them to express solutions involving the square root of negative numbers. These are written in the form \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part. In our example, \(\sqrt{-4}\) becomes \(2i\), where \(i\) represents the imaginary unit, defined as \(\sqrt{-1}\).
- The real part of complex numbers often involves coefficients from the original equation.
- The imaginary part results directly from the negative discriminant.
Solving Quadratic Equations
To solve any quadratic equation, you can use various methods, like factoring, completing the square, or the quadratic formula. In scenarios where the equation is not factorable or the solutions are complex, the quadratic formula provides a reliable solution. Here's a quick guide to effectively use the formula:
- Identify coefficients: Spot the values of \(a\), \(b\), and \(c\) in the equation.
- Calculate the discriminant: Work out \(b^2 - 4ac\) to determine the nature of the roots.
- Substitute in the formula: Plug \(a\), \(b\), and \(c\) into the quadratic formula.
- Simplify: Solve the resulting expression to find the roots.
Other exercises in this chapter
Problem 23
Use the square root property to solve each equation. $$ (z+7)^{2}=5 $$
View solution Problem 23
Graph each quadratic function. Label the vertex and sketch and label the axis of svmmetrv. $$ h(x)=\frac{1}{3} x^{2} $$
View solution Problem 24
Solve. Write the solution set in interval notation. $$ \frac{y^{2}+15}{8 y} \leq 1 $$
View solution Problem 24
Find the vertex of the graph of each quadratic function. Determine whether the graph opens upward or downward, find any intercepts, and graph the function. $$ f
View solution