Problem 24
Question
Use a calculator to solve the given equations. If there are no real roots, state this as the answer. \(3 x^{2}-25=20 x\)
Step-by-Step Solution
Verified Answer
The solutions are approximately \( x \approx 7.74 \) and \( x \approx -1.08 \).
1Step 1: Simplify the Equation
Start by rearranging the equation to set it to zero. Move all terms to one side:\[ 3x^2 - 20x - 25 = 0 \]
2Step 2: Identify Quadratic Formula Components
The equation is now in the form \( ax^2 + bx + c = 0 \) where \( a = 3 \), \( b = -20 \), and \( c = -25 \).
3Step 3: Apply Quadratic Formula
Use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Substitute the values of \( a \), \( b \), and \( c \):\[ x = \frac{-(-20) \pm \sqrt{(-20)^2 - 4 \cdot 3 \cdot (-25)}}{2 \cdot 3} \]
4Step 4: Calculate Discriminant
Calculate the discriminant part of the quadratic formula, \( b^2 - 4ac \):\[ (-20)^2 - 4 \, (3) \, (-25) = 400 + 300 = 700 \]
5Step 5: Compute the Roots
Since the discriminant is positive, we have real roots. Solve for \( x \):\[ x = \frac{20 \pm \sqrt{700}}{6} \]Calculate the two solutions:1. \( x = \frac{20 + 26.46}{6} \approx 7.74 \)2. \( x = \frac{20 - 26.46}{6} \approx -1.08 \)
Key Concepts
Quadratic FormulaReal RootsDiscriminantCalculator Usage
Quadratic Formula
The quadratic formula is a powerful tool used to find the solutions, or 'roots', of quadratic equations. A quadratic equation is typically represented in the standard form:\[ ax^2 + bx + c = 0 \]This is where the quadratic formula comes into play, as it allows you to quickly and efficiently find the values of \( x \) by plugging in the coefficients \( a \), \( b \), and \( c \) from your equation. The formula itself is:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]With the quadratic formula, you're equipped to deal with any quadratic equation, whether it has real or complex roots. Remember that the terms "\( -b \pm \)" signify that you will need to perform two calculations to find the two possible solutions for \( x \).Using this formula requires accurate calculations, which makes it very useful to know how to use a scientific calculator effectively. Having a strong grasp of this formula and its application is crucial when dealing with quadratic equations.
Real Roots
Real roots refer to the solutions of the quadratic equation where the values obtained from the formula are real numbers. Quadratic equations can have either real roots or complex numbers as roots, depending on the value of the discriminant (which we'll cover in the next section).When solving quadratic equations, you'll often encounter scenarios with either:
- Two distinct real roots
- One real root (this occurs when they are repeated or equal)
- No real roots (meaning the solutions are complex)
Discriminant
The discriminant is part of the quadratic formula under the square root, specifically the expression \( b^2 - 4ac \). It holds significant importance because it tells us about the nature of the roots without actually computing them entirely. The value of the discriminant determines whether the roots are real or complex:
- If \( b^2 - 4ac > 0 \): There are two distinct real roots.
- If \( b^2 - 4ac = 0 \): There is exactly one real root (also known as a repeated or equal root).
- If \( b^2 - 4ac < 0 \): The roots are complex (not real).
Calculator Usage
Using a calculator efficiently, especially in solving quadratic equations, can significantly simplify your problem-solving process. Here’s why and how you should streamline calculator usage:First, ensure that you are comfortable with basic and scientific calculator functions. For calculating roots using the quadratic formula, follow these tips:
- Use parentheses wisely to maintain the structure of your expressions.
- Double-check your input to avoid common errors with signs and parentheses.
- Utilize the square root function diligently to solve accurately, especially when handling decimals.
Other exercises in this chapter
Problem 23
Solve the given quadratic equations by factoring. $$3 x=4-7 x^{2}$$
View solution Problem 23
Solve the given quadratic equations by completing the square. Exercises \(11-14\) and \(17-20\) may be checked by factoring. $$2 y^{2}-y-2=0$$
View solution Problem 24
solve the given quadratic equations, using the quadratic formula. Exercises \(5-8\) are the same as Exercises \(11-14\) of Section 7.2. $$20 r^{2}=20 r+1$$
View solution Problem 24
In Exercises \(11-30,\) solve the given quadratic equations by completing the square. Exercises \(11-14\) and \(17-20\) may be checked by factoring. $$2+6 v=9 v
View solution