Problem 24
Question
Test the series for convergence or divergence. \( \displaystyle \sum_{n = 1}^{\infty} n \sin(1/n) \)
Step-by-Step Solution
Verified Answer
The series diverges by the Test for Divergence.
1Step 1: Define the Series
The series given is \( \sum_{n=1}^{\infty} n \sin\left(\frac{1}{n}\right) \). Our task is to determine whether this series converges or diverges. We will investigate the convergence using an appropriate convergence test.
2Step 2: Simplify the Term
As \( n \to \infty \), the term \( \frac{1}{n} \to 0 \). Consequently, we use the approximation \( \sin\left(\frac{1}{n}\right) \approx \frac{1}{n} \) for small \( x \). Thus, the given term becomes approximately \( n \cdot \frac{1}{n} = 1 \).
3Step 3: Evaluate the Behavior of the Series
The approximation \( a_n = 1 \) suggests that the terms do not approach zero as \( n \to \infty \). For a series \( \sum a_n \) to converge, the terms \( a_n \) must approach zero. Since \( a_n \approx 1 \), this condition is violated.
4Step 4: Conclusion by the Test for Divergence
The Test for Divergence states that if the limit of \( a_n \) as \( n \to \infty \) is not zero, then the series \( \sum a_n \) diverges. In this series, \( \lim_{n \to \infty} n \sin\left(\frac{1}{n}\right) = 1 eq 0 \). Thus, the series diverges.
Key Concepts
Understanding the Test for DivergenceExploring Series ApproximationUnderstanding Sinusoidal Functions in SeriesThe Importance of Limits in Series Analysis
Understanding the Test for Divergence
The Test for Divergence is a fundamental tool in determining whether a series \( \sum a_n \) converges or diverges. It is based on the behavior of the terms as \( n \to \infty \). To apply this test effectively, review the terms of your series.
- If \( \lim_{n \to \infty} a_n eq 0 \), the series diverges.
- If \( \lim_{n \to \infty} a_n = 0 \), this alone does not imply convergence, but it’s a necessary condition.
Exploring Series Approximation
When dealing with series, particularly those involving functions like sine, approximation can be invaluable for simplification and understanding. The Taylor expansion for \( \sin(x) \) approximates \( \sin(x) \) as \( x \) nears zero. For small values of \( x \):
- \( \sin(x) \approx x \).
Understanding Sinusoidal Functions in Series
Sinusoidal functions like \( \sin(x) \) regularly appear in series, often requiring specific handling due to their oscillatory nature. As trigonometric functions, they offer unique behaviors near zero. Some core properties:
- \( \sin(x) \) is bounded between -1 and 1, oscillating as it goes.
- Its approximation close to zero: \( \sin(x) \approx x \).
The Importance of Limits in Series Analysis
The concept of limits is central in sequences and series, guiding us towards understanding long-term behavior. Calculating the limit involves evaluating how a function's value approaches a particular point as its input approaches a given figure—often infinity for series.For a series \( \sum a_n \),
- If \( \lim_{n \to \infty} a_n = 0 \), it suggests potential for convergence but doesn't guarantee it.
- If non-zero, divergence is confirmed.
Other exercises in this chapter
Problem 24
Find a power series representation for \( f, \) and graph \( f \) and several partial sums \( s_n(x) \) on the same screen. What happens as \( n \) increases? \
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Find the radius of convergence and interval of convergence of the series. \( \sum_{n = 1}^{\infty} \frac {n^2x^n}{2 \cdot 4 \cdot 6 \cdot \cdot \cdot \cdot \cdo
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Use the Ratio Test to determine whether the series is convergent or divergent. \( \displaystyle \sum_{n = 1}^{\infty} ( - 1 )^n \frac {2^n n!}{5 \cdot 8 \cdot 1
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Show that the series is convergent. How many terms of the series do we need to add in order to find the sum to the indicated accuracy? \( \displaystyle \sum_{n
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