Problem 24
Question
Solve the given equation. $$ \frac{1}{x+3}=0 $$
Step-by-Step Solution
Verified Answer
The given equation is \(\frac{1}{x+3}=0\). After isolating the denominator and simplifying, we end up with \(1=0\), which is a false statement. Therefore, there is no solution for x in the given equation.
1Step 1: Isolate the denominator
Given that the equation is \(\frac{1}{x+3}=0\), we must first get rid of the denominator. To do this, first multiply both sides of the equation by (x+3), which is the denominator of the fraction. We get:
\((x+3) \cdot \frac{1}{x+3} = 0 \cdot (x+3)\)
2Step 2: Simplify the equation
Now, we simplify the equation and eliminate the denominator. We get:
\(1 = 0\)
3Step 3: Analyze the result
The result at the end of step 2 is a statement that is always false (1 is not equal to 0). This means that there is no value of x that would make the original equation true. Therefore, there is no solution for x in the given equation.
Key Concepts
Isolating VariablesEquation SimplificationNo Solution EquationsRational Expressions
Isolating Variables
Understanding how to isolate variables is crucial when solving algebraic equations. Isolating a variable means manipulating the equation in such a way that you get the variable by itself on one side, and the rest of the equation on the other side. This helps you to solve for the unknown. The process usually involves performing the same operation on both sides of the equation to maintain the equality.
For example, if you have an equation like \(3x + 2 = 11\), you would subtract 2 from both sides, and then divide both sides by 3 to isolate \(x\). The steps would look like this: Subtract 2 from both sides \(→ 3x = 9\), and then divide by 3 \(→ x = 3\). It's important to ensure that every step you take is valid and keeps the equation balanced.
For example, if you have an equation like \(3x + 2 = 11\), you would subtract 2 from both sides, and then divide both sides by 3 to isolate \(x\). The steps would look like this: Subtract 2 from both sides \(→ 3x = 9\), and then divide by 3 \(→ x = 3\). It's important to ensure that every step you take is valid and keeps the equation balanced.
Equation Simplification
The simplification of an equation often makes it easier to solve or understand. During simplification, you eliminate unnecessary parts, such as fractions or parentheses, and combine like terms when possible. It can involve several mathematical operations like addition, subtraction, multiplication, division, and exponentiation.
Assuming you're dealing with a more complex equation, like \(2(x + 3) - 4x = 12\), the process of simplification might look like: expand the parenthesis \(→ 2x + 6 - 4x = 12\), then subtract \(2x\) from \(4x\) \(→ -2x + 6 = 12\), and finally, subtract 6 from both sides to isolate the \(x\) term \(→ -2x = 6\). The goal is to create an equation that is as simple as possible before you solve for the variable.
Assuming you're dealing with a more complex equation, like \(2(x + 3) - 4x = 12\), the process of simplification might look like: expand the parenthesis \(→ 2x + 6 - 4x = 12\), then subtract \(2x\) from \(4x\) \(→ -2x + 6 = 12\), and finally, subtract 6 from both sides to isolate the \(x\) term \(→ -2x = 6\). The goal is to create an equation that is as simple as possible before you solve for the variable.
No Solution Equations
Some algebraic equations are designed as a trap, with no solution available. These are known as 'no solution' or 'inconsistent' equations and usually result in a statement that's always false, such as \(1 = 0\). The equation \(\frac{1}{x+3} = 0\) is an example of such a scenario, as there cannot be a real number solution that will satisfy the equation given that the fraction's value can never be zero regardless of what \(x\) is.
When faced with such an equation during simplification, you end up with contradictory statements. It's crucial to recognize that not every equation has a solution, and knowing how to identify such cases is a valuable skill for mathematics students.
When faced with such an equation during simplification, you end up with contradictory statements. It's crucial to recognize that not every equation has a solution, and knowing how to identify such cases is a valuable skill for mathematics students.
Rational Expressions
Rational expressions involve ratios of polynomials, resembling fractions where the numerator and the denominator are both polynomials. Just like fractions, they can undergo operations such as addition, subtraction, multiplication, and division. However, one must pay special attention to the denominator, as it dictates the domain of the expression -- it can never be zero.
A common mistake is disregarding the domain, which can lead to undefined expressions or incorrect solutions. For instance, if you encounter an expression like \(\frac{x^2 - 4}{x - 2}\), it's important to factor and simplify, but you should also remember that \(x\) cannot be 2 since this would make the denominator zero, leading to an undefined expression. Thus, dealing with rational expressions requires careful analysis to correctly manage both the algebraic manipulation and domain considerations.
A common mistake is disregarding the domain, which can lead to undefined expressions or incorrect solutions. For instance, if you encounter an expression like \(\frac{x^2 - 4}{x - 2}\), it's important to factor and simplify, but you should also remember that \(x\) cannot be 2 since this would make the denominator zero, leading to an undefined expression. Thus, dealing with rational expressions requires careful analysis to correctly manage both the algebraic manipulation and domain considerations.
Other exercises in this chapter
Problem 24
Solve the equation by completing the square. $$ 10 x-5=4 x^{2} $$
View solution Problem 24
Carry out the indicated operation and write your answer using positive exponents only. $$ \frac{3^{-5 / 4}}{3^{-1 / 4}} $$
View solution Problem 24
Simplify the expression, writing your answer using positive exponents only. $$ \frac{\left(3 x^{2}\right)\left(4 x^{3}\right)}{2 x^{4}} $$
View solution Problem 24
In Exercises, factor the polynomial. If the polynomial is prime, state it. $$ 4 u^{2}-12 u v+9 v^{2} $$
View solution