Problem 24
Question
Solve each of the equations. $$-2+\frac{x+3}{4}=\frac{5}{6}$$
Step-by-Step Solution
Verified Answer
\(x = \frac{25}{3}\).
1Step 1: Eliminate the Fraction
To eliminate the fraction in the equation, multiply every term by 12, which is the least common multiple of 4 and 6, to make the fractions disappear: \[ 12(-2) + 12\left(\frac{x+3}{4}\right) = 12\left(\frac{5}{6}\right). \] Simplifying, you get:\[ -24 + 3(x+3) = 10. \]
2Step 2: Distribute the Coefficient
Distribute the 3 in the equation:\[ -24 + 3x + 9 = 10. \] Combine the constants (3 times 3) to simplify further:\[ 3x - 15 = 10. \]
3Step 3: Isolate the Variable Term
To isolate the term with \( x \), add 15 to both sides of the equation:\[ 3x - 15 + 15 = 10 + 15, \]which simplifies to:\[ 3x = 25. \]
4Step 4: Solve for x
Finally, divide both sides by 3 to solve for \( x \):\[ x = \frac{25}{3}. \]
Key Concepts
Fraction EliminationDistributionIsolating Variables
Fraction Elimination
Fractions in equations can make solving them seem more complicated than they really are. A useful approach is the elimination of these fractions. This technique involves finding a common multiple of the denominators, so we can multiply every term by this number to simplify the equation.
In our original equation, \(-2+\frac{x+3}{4}=\frac{5}{6}\), we have fractions with denominators of 4 and 6. The least common multiple (LCM) of these numbers is 12. By multiplying each term in the equation by 12, we effectively "clear" the fractions:
In our original equation, \(-2+\frac{x+3}{4}=\frac{5}{6}\), we have fractions with denominators of 4 and 6. The least common multiple (LCM) of these numbers is 12. By multiplying each term in the equation by 12, we effectively "clear" the fractions:
- Multiply \(-2\) by 12 which results in \(-24\).
- Multiply \(\frac{x+3}{4}\) by 12, giving us \(3(x+3)\), because \(12 / 4 = 3\).
- Multiply \(\frac{5}{6}\) by 12, resulting in 10, since \(12 / 6 = 2\).
Distribution
The next step in solving the equation involves distribution. This technique is crucial for dealing with expressions that include parentheses.
In our transformed equation \(-24 + 3(x+3) = 10\), we need to distribute the coefficient 3 across the terms inside the parentheses. This means multiplying 3 by each term inside the parentheses, which in this case are \(x\) and 3:
In our transformed equation \(-24 + 3(x+3) = 10\), we need to distribute the coefficient 3 across the terms inside the parentheses. This means multiplying 3 by each term inside the parentheses, which in this case are \(x\) and 3:
- Multiply 3 by \(x\) to get \(3x\).
- Multiply 3 by 3 to get 9.
Isolating Variables
The ultimate goal in solving equations is to find the value of the variable, here represented by \(x\). This involves isolating the variable on one side of the equation.
Starting from our last equation \(3x - 15 = 10\), we need to get rid of all constants on the side with \(x\). The constant here is \(-15\). To eliminate it, add 15 to both sides of the equation:
Starting from our last equation \(3x - 15 = 10\), we need to get rid of all constants on the side with \(x\). The constant here is \(-15\). To eliminate it, add 15 to both sides of the equation:
- This step leaves us with \(3x = 25\) when the constants on the left cancel out.
- Divide both sides by 3, yielding \(x = \frac{25}{3}\).
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