Problem 24
Question
Rewrite the equation so that \(y\) is a function of \(x .\) $$7 x-4 x+12=36-5 y$$
Step-by-Step Solution
Verified Answer
The equation, when solved for \(y\) in terms of \(x\), is \(y = \frac{3}{5}x + \frac{12}{5}\).
1Step 1: Combine Like Terms
Our first step is to simplify the equation by combining like terms on both sides of the equation. Thus, \(7x - 4x + 12 = 36 - 5y\) simplifies to \(3x + 12 = 36 - 5y\)
2Step 2: Rearrange the Equation
We need to isolate the term containing \(y\) on one side of the equation. To do this, let's subtract \(36\) and \(3x\) from both sides of the equation to get \(-5y = -3x -12\)
3Step 3: Solve for y
Now we need to solve for \(y\) by dividing every term by -5, which gives us the equation \(y = \frac{3}{5}x + \frac{12}{5}\).
Key Concepts
Combining Like TermsRearranging EquationsIsolating Variables
Combining Like Terms
When solving linear equations, it's essential to first simplify the equation by combining like terms. Like terms are terms that have the same variable raised to the same power. In the given exercise, the equation starts with multiple x-terms on the left side: \(7x - 4x + 12 = 36 - 5y\). Combining like terms involves adding or subtracting the coefficients (numerical factors) of these terms.
For instance, \(7x\) and \(4x\) are like terms because they both contain the variable \(x\) to the first power. To combine them, subtract the coefficient of \(4x\) from the coefficient of \(7x\), resulting in \(3x\). No other like terms exist in the equation, so the simplified form becomes \(3x + 12 = 36 - 5y\). This step is a foundation for efficiently solving the equation as it reduces complexity and minimizes potential errors in later steps.
For instance, \(7x\) and \(4x\) are like terms because they both contain the variable \(x\) to the first power. To combine them, subtract the coefficient of \(4x\) from the coefficient of \(7x\), resulting in \(3x\). No other like terms exist in the equation, so the simplified form becomes \(3x + 12 = 36 - 5y\). This step is a foundation for efficiently solving the equation as it reduces complexity and minimizes potential errors in later steps.
Rearranging Equations
Rearranging equations is a crucial step in solving for a specific variable. After combining like terms, the next step in our problem is to isolate the variable \(y\) on one side of the equation. To achieve this, we rearrange the equation by performing the same operation on both sides, thus maintaining the equality.
In the equation \(3x + 12 = 36 - 5y\), we want to move all terms not containing \(y\) to the opposite side. This is done by subtracting \(36\) and \(3x\) from both sides. This step can be visualized as balancing a scale—whatever you do to one side, you must do to the other to keep the scale balanced. By performing these subtractions, we get \( -5y = -3x - 12 \), which is a neater arrangement where \(y\) is closer to being isolated.
In the equation \(3x + 12 = 36 - 5y\), we want to move all terms not containing \(y\) to the opposite side. This is done by subtracting \(36\) and \(3x\) from both sides. This step can be visualized as balancing a scale—whatever you do to one side, you must do to the other to keep the scale balanced. By performing these subtractions, we get \( -5y = -3x - 12 \), which is a neater arrangement where \(y\) is closer to being isolated.
Isolating Variables
The final step to solve for \(y\) is to isolate the variable, meaning to get \(y\) by itself on one side of the equality. In this case, we want to isolate \(y\) from the equation \( -5y = -3x - 12\). This is accomplished by dividing all terms in the equation by the coefficient of \(y\), which is \( -5\).
Dividing each term by \( -5 \) results in \(y = \frac{3}{5}x + \frac{12}{5}\). It's important to apply the division across all terms to preserve the equation's balance. Now \(y\) is isolated and expressed as a function of \(x\), achieving our goal. This form is useful for graphing the equation or for identifying how changes in \(x\) will affect \(y\). The process of isolating variables is fundamental in algebra and can be applied to various types of equations to solve for unknowns.
Dividing each term by \( -5 \) results in \(y = \frac{3}{5}x + \frac{12}{5}\). It's important to apply the division across all terms to preserve the equation's balance. Now \(y\) is isolated and expressed as a function of \(x\), achieving our goal. This form is useful for graphing the equation or for identifying how changes in \(x\) will affect \(y\). The process of isolating variables is fundamental in algebra and can be applied to various types of equations to solve for unknowns.
Other exercises in this chapter
Problem 23
Tell whether the equations are equivalent. $$\frac{2}{3} x=24 \text { and } x=16$$
View solution Problem 24
Convert the measure. Round your answer to the nearest tenth. 21 inches to centimeters ( 1 inch \(=2.54\) centimeters)
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Solve the equation. $$11=r-4$$
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Solve the equation. $$22=18-\frac{1}{4} x$$
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