Problem 24
Question
Reduce the equation to one of the standard forms, classify the surface, and sketch it. \(y^{2}=x^{2}+4 z^{2}+4\)
Step-by-Step Solution
Verified Answer
The surface is a hyperboloid of one sheet: \( \frac{y^2}{4} - \frac{x^2}{4} - z^2 = 1 \).
1Step 1: Arrange Equation in Standard Form
The given equation is \(y^{2} = x^{2} + 4z^{2} + 4\). Our goal is to rewrite this equation to match one of the standard forms of conic sections. Start by rearranging the terms: \[ y^{2} - x^{2} - 4z^{2} = 4 \]
2Step 2: Identify the Standard Form
The rearranged equation \( y^{2} - x^{2} - 4z^{2} = 4 \) resembles the standard form of a hyperboloid of one sheet which is \( \frac{y^2}{c^2} - \frac{x^2}{a^2} - \frac{z^2}{b^2} = 1 \). To match, divide the entire equation by 4:\[ \frac{y^{2}}{4} - \frac{x^{2}}{4} - z^{2} = 1 \]
3Step 3: Classify the Surface
The equation \( \frac{y^2}{4} - \frac{x^2}{4} - z^2 = 1 \) is now in the standard form for a hyperboloid of one sheet, where \( a^2 = 4 \), \( b^2 = 4 \), and \( c^2 = 1 \).
4Step 4: Sketch the Hyperboloid
To sketch the hyperboloid, note the following characteristics:
1. It is centered at the origin (0, 0, 0).
2. The z-axis is the axis of symmetry.
3. It opens along the y-axis.
4. The vertices are at (0, ±2, 0) and saddle points extend as hyperbolic sheets along the x and z axes.
Key Concepts
HyperboloidConic SectionsCoordinate Geometry
Hyperboloid
A hyperboloid is a fascinating surface found frequently in mathematics, especially within the realm of multivariable calculus. It comes in two types: hyperboloid of one sheet and hyperboloid of two sheets. The equation we are dealing with is a hyperboloid of one sheet, which has a unique appearance that can be visualized like a cooling tower of a power plant.
This type of hyperboloid is characterized by its ability to open along one axis and have hyperbolic curves in cross-sections parallel to the other axes. In the equation from our exercise, we find that the hyperboloid centers at the origin and opens along the y-axis, following the standard form:
This type of hyperboloid is characterized by its ability to open along one axis and have hyperbolic curves in cross-sections parallel to the other axes. In the equation from our exercise, we find that the hyperboloid centers at the origin and opens along the y-axis, following the standard form:
- The general equation is \(\frac{y^2}{c^2} - \frac{x^2}{a^2} - \frac{z^2}{b^2} = 1\)
- Here, \(c^2=1\), \(a^2=4\), and \(b^2=4\)
- The hyperboloid is symmetric with respect to the xy-plane and the yz-plane
- It extends infinitely along all three axes, primarily expanding along the y-axis
Conic Sections
Conic sections describe the curves obtained by intersecting a plane with a cone. These include circles, ellipses, parabolas, and hyperbolas. In three dimensions, similar structures emerge, providing insight into the surfaces such as hyperboloids.
In multivariable calculus, conic sections help in recognizing patterns in these surfaces. When looking at our equation, the transformation into a hyperboloid of one sheet is possible because of the inherent nature of conic sections:
In multivariable calculus, conic sections help in recognizing patterns in these surfaces. When looking at our equation, the transformation into a hyperboloid of one sheet is possible because of the inherent nature of conic sections:
- Conic sections are defined by second-degree polynomial equations
- By rearranging and classifying these equations, we can identify the type of surface (e.g., hyperboloid of one sheet)
- The hyperboloid obtained is essentially a three-dimensional extension of hyperbolic curves
Coordinate Geometry
Coordinate geometry bridges algebra and geometry, enabling us to translate equations into compelling visual representations. In multivariable calculus, it's especially useful for visualizing and analyzing surfaces.
Our given hyperboloid example illustrates how a simple algebraic equation can describe complex geometry:
Our given hyperboloid example illustrates how a simple algebraic equation can describe complex geometry:
- The initial step involved rewriting the equation in standard form, essential for recognizing it as a hyperboloid
- By dividing coefficients, the equation was transformed into a cleaner form for a straightforward geometric interpretation
- The resulting surface, a hyperboloid, is described not just by its formula but by its symmetry and spatial orientation
Other exercises in this chapter
Problem 23
Find a unit vector that is orthogonal to both \(\mathbf{i}+\mathbf{j}\) and \(\mathbf{i}+\mathbf{k}\)
View solution Problem 24
Show that the curve with parametric equations \(x=\sin t\) \(y=\cos t, z=\sin ^{2} t\) is the curve of intersection of the surfaces \(z=x^{2}\) and \(x^{2}+y^{2
View solution Problem 24
\(21-32=\) Find an equation of the plane. The plane through the point \((2,0,1)\) and perpendicular to the line \(x=3 t, y=2-t, z=3+4 t\)
View solution Problem 24
Describe in words the region of \(\mathbb{R}^{3}\) represented by theequations or inequalities. \(x \geqslant-3\)
View solution