Problem 24
Question
perform the indicated operations for each expression, if possible. $$A=\left[\begin{array}{rrr}-1 & 3 & 0 \\\2 & 4 & 1\end{array}\right] \quad B=\left[\begin{array}{rrr}0 & 2 & 1 \\\3 & -2 & 4\end{array}\right] \quad C=\left[\begin{array}{rr}0 & 1 \\\2 & -1 \\\3 & 1\end{array}\right] \quad D=\left[\begin{array}{rr}2 & -3 \\\0 & 1 \\\4 & -2\end{array}\right]$$ $$2B-3A$$
Step-by-Step Solution
Verified Answer
The resulting matrix is \(\left[\begin{array}{ccc}3 & -5 & 2 \\ 0 & -16 & 5 \end{array}\right]\).
1Step 1: Define the Operation
We need to perform the operation \(2B - 3A\), which involves scalar multiplication of matrices and matrix subtraction. First, understand that matrix \(B\) and \(A\) are both 2x3 matrices, allowing these operations to be valid.
2Step 2: Scalar Multiplication of Matrices
Multiply each element in matrix \(B\) by 2. \[ 2B = \left[ \begin{array}{ccc}2 \times 0 & 2 \times 2 & 2 \times 1 \2 \times 3 & 2 \times (-2) & 2 \times 4 \\end{array} \right] = \left[ \begin{array}{ccc}0 & 4 & 2 \6 & -4 & 8 \\end{array} \right] \]
3Step 3: Second Scalar Multiplication
Multiply each element in matrix \(A\) by 3. \[ 3A = \left[ \begin{array}{ccc}3 \times (-1) & 3 \times 3 & 3 \times 0 \3 \times 2 & 3 \times 4 & 3 \times 1 \\end{array} \right] = \left[ \begin{array}{ccc}-3 & 9 & 0 \6 & 12 & 3 \\end{array} \right] \]
4Step 4: Subtraction of Matrices
Subtract the matrix \(3A\) from \(2B\). This is done element-wise.\[ 2B - 3A = \left[ \begin{array}{ccc}0 - (-3) & 4 - 9 & 2 - 0 \6 - 6 & -4 - 12 & 8 - 3 \\end{array} \right] = \left[ \begin{array}{ccc}3 & -5 & 2 \0 & -16 & 5 \\end{array} \right] \]
5Step 5: Conclusion
The resulting matrix from the operation \(2B - 3A\) is: \[ \left[ \begin{array}{ccc}3 & -5 & 2 \0 & -16 & 5 \\end{array} \right] \]
Key Concepts
Scalar MultiplicationMatrix Subtraction2x3 Matrices
Scalar Multiplication
Scalar multiplication in matrix operations is a fundamental concept that involves multiplying each element within a matrix by a constant value, known as a scalar. Picture scaling a drawing; each line becomes proportionally longer or shorter depending on the scaling factor.
In more formal terms:
In more formal terms:
- Given a matrix \( M \), a scalar multiplication by a constant \( k \) means that every element \( m_{ij} \) in \( M \) is multiplied by \( k \).
- The resultant matrix has each element as \( k \times m_{ij} \).
Matrix Subtraction
Matrix subtraction is performed when you have two matrices of the same size and wish to create a new matrix representing the difference between the two. It's akin to subtracting numbers, but here you subtract one matrix from another, element by element.
A few important rules:
A few important rules:
- The matrices must be of the same dimensions. For instance, both being 2x3 matrices.
- The subtraction is done on each corresponding element from both matrices.
2x3 Matrices
A 2x3 matrix is a rectangular arrangement of numbers with two rows and three columns. It represents a common format for many practical and theoretical calculations within the realm of linear algebra. It's seen frequently in systems of equations, data representation, and transformations.
Understanding the Layout:
Understanding the Layout:
- The notation 2x3 describes the structure of the matrix – 2 rows and 3 columns.
- Each element of a matrix is usually denoted in a manner where the row number comes before the column number, like \( a_{ij} \), where \( i \) is the row, and \( j \) is the column.
Other exercises in this chapter
Problem 24
Find the partial-fraction decomposition for each rational function. $$\frac{3 x+1}{x^{2}+4 x+4}$$
View solution Problem 24
Indicate whether each matrix is in row-echelon form. If it is, determine whether it is in reduced row-echelon form. $$\left[\begin{array}{lll|l} 1 & 0 & 0 & -3
View solution Problem 24
Use Cramer's rule to solve each system of equations, if possible. $$\begin{array}{r} 2 x-3 y=2 \\ 10 x-15 y=20 \end{array}$$
View solution Problem 24
Solve each system of linear equations by elimination. $$\begin{array}{r} -2 x+3 y=1 \\ 2 x-y=7 \end{array}$$
View solution