Problem 24
Question
Indicate the quadrant in which the terminal side of \(\theta\) must lie in order for the information to be true. \(\cot \theta\) is negative and \(\csc \theta\) is positive.
Step-by-Step Solution
Verified Answer
The terminal side of \( \theta \) is in the second quadrant.
1Step 1: Understanding the Sign of Cotangent
The cotangent of an angle, \( \cot \theta \), is negative when the sine and cosine of the angle have opposite signs. This occurs in the second and fourth quadrants.
2Step 2: Understanding the Sign of Cosecant
The cosecant of an angle, \( \csc \theta \), is positive when the sine of the angle is positive. This happens in the first and second quadrants because sine is positive in these quadrants.
3Step 3: Finding the Common Quadrant
We need to find a quadrant where \( \cot \theta \) is negative and \( \csc \theta \) is positive. From Steps 1 and 2, the second quadrant is the only quadrant that satisfies both conditions, as cosine is negative and sine is positive there.
Key Concepts
Cotangent SignCosecant SignTrigonometric Functions
Cotangent Sign
The cotangent function, denoted as \( \cot \theta \), is the reciprocal of tangent. It is calculated as the ratio of the cosine to the sine:
\[ \cot \theta = \frac{\cos \theta}{\sin \theta} \]
The sign of \( \cot \theta \) depends on the signs of both \( \cos \theta \) and \( \sin \theta \). Since it is a ratio, \( \cot \theta \) is negative when \( \cos \theta \) and \( \sin \theta \) have opposite signs. This occurs in the following quadrants:
\[ \cot \theta = \frac{\cos \theta}{\sin \theta} \]
The sign of \( \cot \theta \) depends on the signs of both \( \cos \theta \) and \( \sin \theta \). Since it is a ratio, \( \cot \theta \) is negative when \( \cos \theta \) and \( \sin \theta \) have opposite signs. This occurs in the following quadrants:
- Second Quadrant: \( \sin \theta > 0 \) and \( \cos \theta < 0 \)
- Fourth Quadrant: \( \sin \theta < 0 \) and \( \cos \theta > 0 \)
Cosecant Sign
The cosecant function, denoted as \( \csc \theta \), is the reciprocal of the sine function. It is expressed as:
\[ \csc \theta = \frac{1}{\sin \theta} \]
Because it relies on sine, the sign of \( \csc \theta \) is directly influenced by the sign of \( \sin \theta \). Therefore, \( \csc \theta \) is positive when \( \sin \theta \) is positive.
\[ \csc \theta = \frac{1}{\sin \theta} \]
Because it relies on sine, the sign of \( \csc \theta \) is directly influenced by the sign of \( \sin \theta \). Therefore, \( \csc \theta \) is positive when \( \sin \theta \) is positive.
- First Quadrant: \( \sin \theta > 0 \)
- Second Quadrant: \( \sin \theta > 0 \)
Trigonometric Functions
Trigonometric functions are fundamental in mathematics, relating the angles of a triangle to the lengths of their sides. The primary functions include sine, cosine, tangent, cotangent, secant, and cosecant. Each function has a specific role and behavior in different quadrants, as follows:
- First Quadrant: All trigonometric functions are positive.
- Sine, cosine, tangent, cotangent, secant, and cosecant are all positive here.
- Second Quadrant: Only sine and cosecant are positive.
- Cosine, tangent, cotangent, and secant are negative.
- Third Quadrant: Only tangent and cotangent are positive.
- Sine, cosine, secant, and cosecant are negative.
- Fourth Quadrant: Only cosine and secant are positive.
- Sine, tangent, cotangent, and cosecant are negative.
Other exercises in this chapter
Problem 24
Solve each triangle. $$a=11, c=12, \gamma=60^{\circ}$$
View solution Problem 24
The measures of two sides and an angle are given. Determine whether a triangle (or two) exist, and if so, solve the triangle(s). $$\alpha=45^{\circ}, b=\sqrt{2}
View solution Problem 24
Convert from degrees to radians. Leave the answers in terms of \(\pi\). $$540^{\circ}$$
View solution Problem 25
Solve each triangle. $$a=\sqrt{7}, b=\sqrt{8}, c=\sqrt{3}$$
View solution