Problem 24
Question
In Exercises 19-32, find the standard form of the equation of the parabola with the given characteristic(s) and vertex at the origin. Focus: \((0, -2)\)
Step-by-Step Solution
Verified Answer
The standard form of the equation of the parabola is \(y=-(1/8)x^2\)
1Step 1: Determine orientation and a-value
The focus of the parabola is under the vertex (0, 0). When the focus is above or below the vertex, the parabola has a vertical orientation, meaning the general form will be \((x-h)^2 = 4a(y-k)\). Since the vertex and focus lie on the y-axis, the value of \(a\) will be the absolute y-coordinate of the vertex subtracted from the y-coordinate of the focus, i.e., \(-2-0 = -2\). So \(a=-2\)
2Step 2: Substituting vertex and a into general form
Substitute the vertex (h, k = 0, 0) and \(a=-2\) into \((x-h)^2 = 4a(y-k)\) to get \(x^2 = -8y\)
3Step 3: Final Equation of Parabola
Re-arranging the equation from step 2, we have \(y=-(1/8)x^2\). So the standard form of the equation of the parabola that opens downwards and has its vertex at the origin, with focus at \((0, -2)\) is \(y=-(1/8)x^2\)
Key Concepts
Standard Form of EquationVertex of ParabolaFocus of Parabola
Standard Form of Equation
The parabola is a famous curve in mathematics, and its equation in standard form reveals a lot about its properties. The standard form for a parabola that opens either up or down is
When the parabola opens left or right, the roles of \(x\) and \(y\) are switched:
Understanding the standard form helps us quickly find information about the parabola's direction, width, and position.
- \((x-h)^2 = 4a(y-k)\)
When the parabola opens left or right, the roles of \(x\) and \(y\) are switched:
- \((y-k)^2 = 4a(x-h)\)
Understanding the standard form helps us quickly find information about the parabola's direction, width, and position.
Vertex of Parabola
The vertex of a parabola is a critical point where the curve changes direction. In the standard form equation, \((h, k)\) is the vertex of the parabola. The vertex is essential because it provides the anchor point around which the parabola is shaped.
There are two primary cases for a parabola's vertex:
There are two primary cases for a parabola's vertex:
- For a parabola that opens up or down, the vertex is the point of minimum or maximum value, respectively.
- For a parabola that opens left or right, the vertex is the point of least or greatest \(x\)-value.
Focus of Parabola
The focus of a parabola is a special point located inside the parabola, along its axis of symmetry. The parabola's definition is that it is the set of all points equidistant from the directrix and the focus.
In our example, the focus is at \((0, -2)\), which indicates the parabola opens downwards in a vertical orientation. The value of \(a\) (from the standard form equation) is derived from the distance between the vertex and the focus. In this case, \(-2 - 0 = -2\), so \(a = -2\).
In our example, the focus is at \((0, -2)\), which indicates the parabola opens downwards in a vertical orientation. The value of \(a\) (from the standard form equation) is derived from the distance between the vertex and the focus. In this case, \(-2 - 0 = -2\), so \(a = -2\).
- This implies a negative \(a\) value, confirming the downward direction.
- The vertex to focus distance informs not just the direction but also the steepness of the parabola.
Other exercises in this chapter
Problem 24
In Exercises 13-26, rotate the axes to eliminate the \(xy\)-term in the equation. Then write the equation in standard form. Sketch the graph of the resulting eq
View solution Problem 24
In Exercises 19-28, find the standard form of the equation of the ellipse with the given characteristics. Center: \((2, -1); \quad\) vertex: \((2, \frac{1}{2});
View solution Problem 24
In Exercises 19-26, find the inclination \(\theta\) (in radians and degrees) of the line passing through the points. \((12, 8)\), \((-4, -3)\)
View solution Problem 25
In Exercises 15-28, identify the conic and sketch its graph. \(r=\dfrac{3}{2-6\cos\ \theta}\)
View solution